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(#M40035080) SELF Numerical Ability question Keep an EYE

total no of 4 digit natural numbers divisible by either 101 or 7.

harshal agrawal (11 years ago)

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Ann Theressa  (11 years ago)

1363

Four digit terms divisible by 7 are
1001,1008,...9996
This is an AP whose nth term = 1st term+(n-1)*difference
9996 = 1001+(n-1)*7
n=1286

Four digit terms divisible by 101 are
1010,1111,1212,1313....9898,9999
9999 = 1010+(n-1)*101
n = 90

Common terms for both the series are,
1414,2121,2828,3535,....9898
9898 = 1414 + (n-1)*707
n = 13

Total no. of 4 digit natural numbers divisible by 101 or 7 = 1286 + 90 - 13
=1363

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