Latest TCS Aptitude Question SOLUTION: What is the output of the following program: void main() { printf("%d %d %d %d",65,065,0x65,0X65); }

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What is the output of the following program:

void main()
{
printf("%d %d %d %d",65,065,0x65,0X65);
}

Asked In TCS Subrata Patra (10 years ago)

Solved Saraswathy Read Solution (10)

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Read Solution (10) :

Saraswathy  (10 years ago)

O/p: 65, 53, 101, 101

%d always print the decimal form of any number...
65 -> decimal no
065 => octal no. So it ll convert to decimal no.
065=> 000 110 101 => 1*2^0 + 1*2^2+ 1*2^4 + 1*2^5 = 53
0x65 => hexa-decimal number
65 => 0110 0101 => 1*2^0 + 1*2^2 + 1*2^5 + 1*2^6 = 101
0X65 => hexa decimal no.

Hence it ll print 65, 53, 101, 101

Is this solution Helpfull? Yes (46) | No (2)  

reshma  (9 years ago)

octal to decimal conversion
Octal = 065
Decimal= 0×8²+6×8¹+5×8⁰ = 53

Is this solution Helpfull? Yes (3) | No (1)  

srisailam nambu  (9 years ago)

printf() is predefined method in stdio
but not included

Is this solution Helpfull? Yes (1) | No (4)  

M.PRIYANKA  (9 years ago)

saraswathy..!!! can u tell me hw this 1*2^0 + 1*2^2+ 1*2^4 + 1*2^5 = 53 and 1*2^0 + 1*2^2 + 1*2^5 + 1*2^6 = 101 written??

Is this solution Helpfull? Yes | No (3)  

pooja  (9 years ago)

priyanka.....
065 is octal no ..convert it to binary so the binary value is 000 110 101 ...now convert this binary no to decimal ..so 1*2^0 + 1*2^2+ 1*2^4 + 1*2^5 = 53...

Is this solution Helpfull? Yes | No (5)  

sundeep gullapudi  (9 years ago)

65
53 => 065 is in octal notation ..after converting it into decimal 53
101 => from hex to decimal
101

Is this solution Helpfull? Yes | No (1)  

PRASANNA KUMAR N  (9 years ago)

ans:65 53 101 101

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thamizhvel  (9 years ago)

error in program , there is no declaration

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Mirudhu Bashini  (7 years ago)

it shows error.."compile error:variable not defined"

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PRIYA  (6 years ago)

65,53,101,101

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