Latest TCS Aptitude Question SOLUTION: What is the output of following program? #include int main() { void *ptr1, *ptr2, x; int y; x = 100; y = 200; ptr1 = &x; ptr2 = &y; printf("%d", *ptr1); pri

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(#M40035235) TCS Programming question C Programming Keep an EYE

What is the output of following program?
#include
int main()
{
void *ptr1, *ptr2, x;
int y;
x = 100;
y = 200;

ptr1 = &x;
ptr2 = &y;

printf("%d", *ptr1);
pritnf("%d", *ptr2);

return 0;

}

Asked In TCS Subrata Patra (10 years ago)

Solved Saraswathy Read Solution (22)

Is this Puzzle helpful?   (27)   (2) Submit Your Solution Program

Read Solution (22) :

aniruddha Ghosh  (9 years ago)

the program causes compile time error showing the "variable or field declares as void" or invalid use of void because variables can't be declared as void..though void pointer will be working fine..

Is this solution Helpfull? Yes (23) | No (2)  

Saraswathy  (10 years ago)

Output : 100, 200

Since ptr1 nd ptr2 are pointer variables, it ll always hold the address of another variable...
Assume address of x=1000, y=1002
Then ptr1=&x; ptr2=&y; will store ptr1=1000, ptr2 = 1002
*ptr1 ll print *1000 (ie value of address 1000 => 100
*ptr2 ll print *1002 (ie value of address 1000 => 200

Is this solution Helpfull? Yes (21) | No (16)  

Puja Bharati  (9 years ago)

This will show error in programs as variable x is also declared as void,wrong way of printing values of ptr1 and ptr2.
program should be like this
#include
int main()
{
void *ptr1;
void *ptr2;
int y,x;
x = 100;
y = 200;

ptr1 = &x;
ptr2 = &y;

printf("%dn",*((int *)ptr1));
printf("%dn",*((int *)ptr2));

return 0;

}

Is this solution Helpfull? Yes (10) | No   

Ankit  (10 years ago)

the data type of x,*ptr1,*ptr2 cannot be void

Is this solution Helpfull? Yes (3) | No (1)  

Hanish  (10 years ago)

return type of ptr*1,ptr*2 and x are null so it it impossible to implement this.

Is this solution Helpfull? Yes (1) | No   

priyanka  (9 years ago)

ptri=&x
*ptr1=*&x=x=200
similarly *ptr2=200
output=100 200

Is this solution Helpfull? Yes (1) | No (1)  

Gagan Jawa  (9 years ago)

There is an error..
ptr1 and ptr2 are void so they are not allocated any space to store any value..
Therefore it is not allowed and it will not compile..

Is this solution Helpfull? Yes (1) | No   

manish sukhadia  (9 years ago)

Give the Compile error like..
Not an allowed type

Is this solution Helpfull? Yes (1) | No   

Mukesh kumar  (9 years ago)

ptri=&x
*ptr1=*&x=x=200
similarly *ptr2=200
output=100 200

Is this solution Helpfull? Yes (1) | No   

Sarvjeet Rajvansh  (9 years ago)

error because "X" a variable cant be of void data type , only pointer can be of void data type

Is this solution Helpfull? Yes (1) | No   

karnesahithi  (7 years ago)

we will get compile time errors.

Is this solution Helpfull? Yes (1) | No   

sruthi  (10 years ago)

100,200 is answer

Is this solution Helpfull? Yes | No (1)  

CHENNA BAIGANI  (9 years ago)

it displays the actual values of x and y............i.e. 100,200

Is this solution Helpfull? Yes | No (2)  

PRASANNA KUMAR N  (9 years ago)

ans:100200

Is this solution Helpfull? Yes | No (1)  

mukesh  (9 years ago)

this will be an error

Is this solution Helpfull? Yes | No   

bhargav krishna  (9 years ago)

i think its a compile time error

Is this solution Helpfull? Yes | No   

keerthana chennamsetty  (9 years ago)

output will be 100 200
because ptr1=&x means address of x will be stored in ptr1. similarly for pttr2=address of y.
and in printf it is *ptr1 means value that is present in the pt1.

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hemanth  (8 years ago)

frnds this concept is known as null pointer or generic pointer ,by this we can use pointer to any data type but we should type cast with the respective data type while retriving

As there is no type casting this will result an error

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harijana neeraja  (8 years ago)

*ptr1=100,*ptr2=200

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Niharika Vardhan  (8 years ago)

ptr1 will hold address of x and ptr2 will hold address of y
print("%d", *ptr1) will print value at address ptr1
and print("%d", *ptr2) will print value at address ptr2
tthus, 100, 200 will be answer

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mumtaj  (7 years ago)

100
200
because ptr1 and ptr2 is a pointer variable, it is assigned to the address of x and y.In printf statement once again pointer is used thus,it display the value of the address location of x and y.

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Mirudhu Bashini  (7 years ago)

it provides an error bcoz, *ptr1,*ptr2 is declared as void so it can't return anything
when we declare those pointer variables and x to int the ans is 100 and 200.

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