Latest Book Aptitude Question SOLUTION: find the 28383rd term of the series 1234567891011121314... need the explanation ..

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(#M40037664) BOOK Numerical Ability question finding 28383rd term Keep an EYE

find the 28383rd term of the series 1234567891011121314...
need the explanation ..

Asked In Book Liti (9 years ago)

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SUDHIR SHARMA  (9 years ago)

28383rd term will be 3

There are 9 numbers starting from 1 to 9. It means we have 9 digits.
Number of digits from number 10 to 99 are 90*2=180 digits.
Number of digits from number 100 to 999 are = 900*3=2700 digits

Total number of digits from number 1 to 999 are = 9+180+2700 = 2889 digits

Therefore remaining number of digits are = 28383-2889=25494 digits

Now, we move on to 4 digits numbers starting from 1000 to 9999.
Number of digits will be=9000*4=36000

It means the 28383rd digit will lies between 4 digits numbers.

number of 4 digits terms in (28383-2889)=25494 digits are = 25494/4= 6373 complete digits and 2 digits also(bcoz 6373 will be quitent and 2 will be remainder)

6374 number will be 7373
It means 3 will be the 28383rd number.

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SUDHIR SHARMA  (9 years ago)

number 6374 lies between 1000 .........9999

using A.P we can find out it easily.

An=a+(n-1)d
= 1000+(6374-1)1
= 1000+6373
=7373

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Sourojit Dhua  (9 years ago)

cannot be found readily if the sequence is 1,2,3,4,5,6,7,8,9,1,0,1,1,1,2,...
but, if the seq is 1,2,3,4,5,6,7,8,9,10,11,12,...
then it is in A.P ans the 28383rd term will be 1+28382=28383.

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Liti  (9 years ago)

@sudhir

how to know that 6374 term will be 7373

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