Latest aptitude round in tech mahindra Aptitude Question SOLUTION: can any one tell me the answer for this? 1) 1, 2, 3, 5, 7, 11, __? 2) ___, ayw, gec, mki, sqo

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(#M40037679) APTITUDE ROUND IN TE Logical Reasoning question Keep an EYE

can any one tell me the answer for this?
1) 1, 2, 3, 5, 7, 11, __?
2) ___, ayw, gec, mki, sqo

Asked In aptitude round in tech mahindra PRIYA (9 years ago)

Solved Saraswathy Read Solution (8)

Is this Puzzle helpful?   (4)   (1) Submit Your Solution Number Series

Read Solution (8) :

Saraswathy  (9 years ago) Best Solution

1) 1, 2, 3, 5, 7, 11, x
Divide it into 2 groups...
(1, 3, 7, x) (2, 5, 11)
2nd group
2 + (3) = 5
5 + (3*2) = 11
1st group
1 + (2) = 3
3 + (2*2) = 7
7 + (4*2) = 15
Ans : 15

(2) ___, ayw, gec, mki, sqo
1st letter of each word differ by 6...
a+6=g, g+6=m, m+6=s
So 1st letter of 1st word ll be a-6=u
2nd nd 3rd letters differ by 2...
ayw => a-2=y, y-2=w
Similarly u-2=s, s-2=q
Ans : usq

Is this solution Helpfull? Yes (15) | No   

Saraswathy  (9 years ago)

"1" is not a prime no.
An integer >1 is called a prime number if its only positive divisors are one and itself.

Is this solution Helpfull? Yes (2) | No   

rocky  (9 years ago)

1) 1, 2, 3, 5, 7, 11 all prime numbers.
so next is 13(Ans.).
2) ___, ayw, gec, mki, sqo
1st letter of each word differ by 6.
a+6=g, g+6=m, m+6=s
So 1st letter of 1st word ll be a-6=u
2nd and 3rd letters differ by 2.
ayw => a-2=y, y-2=w
Similarly u-2=s, s-2=q
Ans : usq

Is this solution Helpfull? Yes (1) | No (1)  

Anish Mathur  (9 years ago)

1) 1, 2, 3, 5, 7, 11 all prime numbers.
so next is 13(Ans.).
2) ___, ayw, gec, mki, sqo
1st letter of each word differ by 6.
a+6=g, g+6=m, m+6=s
So 1st letter of 1st word ll be a-6=u
2nd and 3rd letters differ by 2.
ayw => a-2=y, y-2=w
Similarly u-2=s, s-2=q
Ans : usq

Is this solution Helpfull? Yes (1) | No (1)  

Sourojit Dhua  (9 years ago)

answer: 15
ESQ

1) 1, 2, 3, 5, 7, 11, x
Divide it into 2 groups...
(1, 3, 7, x) (2, 5, 11)
2nd group
2 + (3) = 5
5 + (3*2) = 11
1st group
1 + (2) = 3
3 + (2*2) = 7
7 + (4*2) = 15
Ans : 15

(2) ___, ayw, gec, mki, sqo
1st letter of each word differ by 6...
a+6=g, g+6=m, m+6=s
So 1st letter of 1st word ll be a-6=u
2nd nd 3rd letters differ by 2...
ayw => a-2=y, y-2=w
Similarly u-2=s, s-2=q
Ans : usq

Is this solution Helpfull? Yes (1) | No   

vinusha reddy  (9 years ago)

1)13 order of odd numbers
2)usq

Is this solution Helpfull? Yes | No (1)  

pokala manohar reddy  (9 years ago)

1)13 why bcoz all cosetutive prime nos
2)usq
by substracting 2 we get last digit nd by adding 2 we get the first no.
by adding 6 to middle no we gwt nwxt middle no.
so the middle no is "s".

Is this solution Helpfull? Yes | No (1)  

Ritu raj  (9 years ago)

15(1 is neither prime nor composite)
usq

Is this solution Helpfull? Yes | No   

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