Latest Elitmus Aptitude Question SOLUTION: ABCD is a square having mid points E,F,G & H respectively. I , J are the mid-points of HG & GF. K is a point on EF such that KF= 1/3(EF). what is the ratio of area of ABCD to the

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(#M40038119) ELITMUS Numerical Ability question area Keep an EYE

ABCD is a square having mid points E,F,G & H respectively.
I , J are the mid-points of HG & GF.
K is a point on EF such that KF= 1/3(EF).
what is the ratio of area of ABCD to the area of triangle IJK?

Asked In Elitmus Liti (9 years ago)

Unsolved Read Solution (10)

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Read Solution (10) :

nishant  (9 years ago)

5:48
area of IJK=1/2*a/2*5a/12
area of ABCD=a^2

Is this solution Helpfull? Yes (9) | No (2)  

jitesh bhojwani  (9 years ago)

1/6root2

by taking the diagram,,,using the side as 'a' of a square.. u can solve it easily

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CHANDAN TIWARY  (9 years ago)

48:5 will be correct answer,,,..suppose ab=bc=cd=da=6sqrt2,then area of square=72unit^2
then ef=fg=gh=he=6 unit
take a mid point on ef as o.....
join as per question ijk...
now,join i and taken point o
you will be able to identify three small right angle triangle
area of ijk=area of iofg-sum of area of(iok,ifj,ijg)=(6*3)-(3+3+4.5)=18-10.5=7.5.......(all values and notation are in sequence here)
ratio of area of abcd to area of ijk=72/7.5=48:5.....enjoyyyyyyyyyy

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Pijush Kar  (9 years ago)

Are E,F,G and H mid points of each side?

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aditya saraswat  (9 years ago)

i think answer is=9/32

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Liti  (9 years ago)

@PIJUSH
yes they are the mid points of AB, BC, CD & DA

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Ranjeet  (9 years ago)

@NISHANT...plz explain yr

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NAVEEN APTI  (9 years ago)

Answer is 7/24......s_naveen46@yahoo.com on Facebook.... For

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ANANT VIKRAM SINGH  (9 years ago)

@nishant pls explain how height of triangle=sa/12

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zohns  (6 years ago)

ans is 48:5

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