Latest Elitmus Aptitude Question SOLUTION: if any one has given accenture written xam plz share ur experience... plz send the placement papers of accenture at.. dimplekhushi922@gmail.com

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(#M40038322) ELITMUS Category question Keep an EYE

if any one has given accenture written xam plz share ur experience... plz send the placement papers of accenture at..

dimplekhushi922@gmail.com

Asked In Elitmus DIMPLE SINGH (9 years ago)

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ashok  (9 years ago)

1)
n(E)=(n-2)!*2!
n(s)=(n-1)! as circular arrngmnt
now
P(E)=(n-2)!*2!/(n-1)!
=2/(n-1)
P(E)'=(1-(2/n-1))=(n-3)/(n-1)
now ATQ
odd against:P(E)'/P(E)=(n-3)/2
ans=(n-3)/2

2)
4 digit no's can be form in following ways=9*10*10*10
only 1,3,7,9 can be multiplied to form 1,3,7,5 in end
so favourable conditions = 4!
p=(9*10*10*10-4!)/9*9*8*7

3)
double numbs are: 1,1 2,2 3,3 4,4 5,5 6,6. so total 6 types.
now cases can be 4C2*(1*1/6 * 1*1/6 * 1*5/6 * 1*5/6) so ans is 25/216. rite?
Alt. (6/36*6/36)

4)
chance of winning of b is.....5/6*1/6, 5/6*5/6*5/6*1/6.....
p= 5/6*1/6 + 5/6*5/6*5/6*1/6 + 5/6*5/6*5/6*5/6*5/6*1/6 +..............
p=1/6*5/6 [1+(5/6)^2+(5/6)^4+(5/6)^6.........)
p=5/11


5)

chance of winning of b is..... 1/2*1/2 + 1/2*1/2*1/2*1/2 +...........
p=1/3

6)
p'=(20C1*18C1*16C1*14C1)/(20C1*19C1*18C1*17C1)
P=1-P'
P=1-((20*18*16*14)/(20*19*18*17))

7)2*(5c1(1/2)*4c1(1/2)*3c1(1/2)*2c1(1/2)*1c1(1/2))

8)p=(4/5)^5

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