Latest C Aptitude Question SOLUTION: what is the output of the following piece of code :- #include int main() { int a = 5; printf("%d %d %d",++a,a,a++); return 0; }

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(#M40038668) C Programming question find the output with reason Keep an EYE

what is the output of the following piece of code :-

#include
int main()
{
int a = 5;
printf("%d %d %d",++a,a,a++);
return 0;
}

Asked In C piyush joshi (9 years ago)

Unsolved Read Solution (27)

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Read Solution (27) :

kamini garg  (9 years ago)

output is 7,6,5
because (,) operator works right to left
so first evalute a++ which is post increment so value remains 5.
and after that a=6
++a=7.

Is this solution Helpfull? Yes (15) | No (2)  

saranya kannedhari  (9 years ago)

6,6,6 Declaring 'a' variable as 5 so ++a means pre-increment of 'a' then 'a' will become a=6,then print a means current 'a' value is 6,then 'a' will be post incremented after perform operation it goes to increment so.., it first print the current value of 'a' and then increment 'a' value

Is this solution Helpfull? Yes (8) | No (2)  

Revanth Kolla  (9 years ago)

7,7,5
in this program we have to come from rigth to left....

Is this solution Helpfull? Yes (5) | No (4)  

sourabh kumar  (9 years ago)

in gcc compilers
++a,a,a++
7 6 5
the pre-increment changes 6 to 7 as a's value has been updated so output is:
7 7 5

turbo c compiler
output is: 7 6 5
the compiler doesn't update the value of a

Is this solution Helpfull? Yes (5) | No   

madhusree  (9 years ago)

++ operator are working in right to left order. but after perform the operation stor in stack.to output in lifo methode.
so s1: a++=5,a=6 store
s2:a=6.
s3:++a=7
print order:s3,s2,s1.
output:765

Is this solution Helpfull? Yes (4) | No (2)  

Bhargav  (9 years ago)

6 6 6
++a means PreIncrementation so the value of a will become 6
Now current value of a is 6
again a++ means the value will remain same because a++ post increment.

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manohar kumar singh  (9 years ago)

result is 6,6,6

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Tufan Mallick  (9 years ago)

the output will be 7,7,5.....

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Dhruv Sharma  (9 years ago)

765 because it works form right to left.

Is this solution Helpfull? Yes (1) | No (1)  

Ashish Singh Patel  (9 years ago)

6 5 5
in ++a it will increment so we get 5+1=6
in a we get as it is 5
in a++ 5 will be assigned then it will increment
so final answer is 6 5 5

Is this solution Helpfull? Yes (1) | No   

Pranoy Bej  (9 years ago)

Output 5,5,6
As ++a is a preincrement operator and a++ is post increment operator.

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divya tadepalli  (9 years ago)

a=5
++a=>pre increment=>5 first increments and that increased value is stored in a =>5+1=6
a++=>post increment=>5 is stored in a and then it increments by 1
so output is 6&5.

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saratha  (9 years ago)

printf works from left to right.so
I st a++ will operate.
a++=>5 is stored & increments by 1.
now a=6
++a=>7.
so,output is 7,6,5.

Is this solution Helpfull? Yes | No (1)  

Prem Kumar  (9 years ago)

It is a compiler dependent, But this is procedure is for Turbo c++ compiler
Actually in printing the statement block, In case of printing a datatype it is designed to execute it in reverse order(it is same in GCC compiler even)
So the output is 7 6 5

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Neha Shahi  (9 years ago)

given a=5,++a=6,a=6& a++=6

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karthik s  (9 years ago)

Output is 7,6,5
because of stack property of c program

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Minakshi Kumari  (9 years ago)

a=5; =7,6,5

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megalamani  (9 years ago)

sorry usually ,(comma) works from left to right hence the solution will be
6,6,7

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shubhangi  (9 years ago)

7 6 5
exe:l to r
print :r to l

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sudhanshu kumar  (9 years ago)

in this program printf() evaluation take place from right to left. so when a++ execute then first value of 'a' store in program stack then post inc take place ,then after when move to next 'a' become 6 and store in stack,after that when we came to ++a then first pre inc then store value in stack .then after print value of a from stack one by one.
ANS:-765

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Swati Sadani  (9 years ago)

765 because ++ operator works from right to left

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snehal jadhav  (9 years ago)

printf("%d %d %d",++a,a,a++);
execution start from left to right
so a++ is post increment ans is 5
then a is 6
then ++a is 7
so finally it will print 7 6 5

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venkata ramana  (9 years ago)

++a---- a value become 6
then a++-- a value will incremented but it is done after completing of printf statement.
so answer is 6 6 6.

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Monishashaik   (9 years ago)

++a=6 a=6 a++=6

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kousalya  (9 years ago)

coming from right to left
a++ remains 5
in memory a stores 6
++a incremented to 7
ans will be 7 6 5

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sumanth  (9 years ago)

7,7,5
increment will have more precedence than normal variable so compiler compiles a++ first as 5 then ++a as 7 and stores final value of into a=7

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Brunda  (9 years ago)

since der are multiple number of %d of same variable in printf statement evaluation starts from right so the right answer is 5,6,7

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