Latest Book Aptitude Question SOLUTION: How Many Zeroes Will be there at the end of the expression (2!)^2! +(4!)^4! +(8!)^8! +(9!)^9! +(10!)^10! +(11!)^11! ?

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(#M40038768) BOOK Numerical Ability question Series Keep an EYE

How Many Zeroes Will be there at the end of the expression (2!)^2! +(4!)^4! +(8!)^8! +(9!)^9! +(10!)^10! +(11!)^11! ?

Asked In Book Ritesh Agarwal (9 years ago)

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Ashok reddy  (9 years ago)

Ans is : 33281281

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raju  (9 years ago)

To form a zero we need one 2 and one 5. In general any factorial contains more 2's than 5's. So limiting factor is 5's. We will find how many 5's each factorial has.
2! and 4! does not contain any zeros. 8!, 9! contains 1 and 10! and 11! contains 2 each.
So total zeroes are 1 x 8! + 1 x 9! + 2 x 10! + 2 x 11! = 8!+9!+2(10!)+2(11!)

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