Latest TCS Aptitude Question SOLUTION: In this question A^B means A raised to power B. Let f(X)=1+X+X^2+...X^6. The remainder when f(X^7) is divided by f(X) is a)0 b)7 c)6 d)none of the above

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(#M40039203) TCS Numerical Ability question Keep an EYE

In this question A^B means A raised to power B. Let f(X)=1+X+X^2+...X^6.
The remainder when f(X^7) is divided by f(X) is
a)0
b)7
c)6
d)none of the above

Asked In TCS Sunita (10 years ago)

Unsolved Read Solution (12)

Is this Puzzle helpful?   (7)   (2) Submit Your Solution Co-ordinate geometry

Read Solution (12) :

srajasekharreddy  (10 years ago)

take a example f(1)=1+1+1^2+1^3+1^4+1^5+1^6=1+1+1+1+1+1+1=7
ans f(1^7)=f(1)=7
so 7/7 then remainder is 0
is it right

Is this solution Helpfull? Yes (11) | No (11)  

Swayanti Bhaumik  (10 years ago)

7 is the answer...
use fermat little theorem

Is this solution Helpfull? Yes (4) | No (1)  

RAVI VERMA  (10 years ago)

7 is the ans

Is this solution Helpfull? Yes (4) | No (2)  

shrey  (10 years ago)

answer in open seesame is 7

Is this solution Helpfull? Yes (3) | No (1)  

srikanth  (10 years ago)

assume x=1 then remainder is 0.
f(2)=1+2+4+8+16+32+64=127
f(x^7)=1+(x^7)+(x^14)+(x^21)+......+(x^42)==>1+{(x^7)*[1+(x^2)+(x^3).....+x^6)]}
==>1+{(2^7)*[1+(2^2)+(2^3).....+(2^6)]==>1+16000=16001
remainder is 26
assume x=3 then remainder is something.
so ans is none of the above.

Is this solution Helpfull? Yes (2) | No   

Shyamal k Mala  (10 years ago)

d) apply polynomial divison method

Is this solution Helpfull? Yes (1) | No   

Raghav gupta  (10 years ago)

please dont misguide others corrdct answer is 56 as once she selected one topping 7 toppings remain out of which she then selects one topping so 8c1 *7c1

Is this solution Helpfull? Yes (1) | No (1)  

Ankush Ojha  (10 years ago)

if we take x=2 we get different remainder than when x=1.
hence answer is none of the above.

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sindhuja  (10 years ago)

remainder is 0

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Sunita  (10 years ago)

plz explain

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ANKIT KUMAR  (10 years ago)

.

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divya  (10 years ago)

0 is answer.....

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