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(#M40039889) TCS Numerical Ability question Keep an EYE

in a single throw with two dice,find the probabiloty that a sum is a multiple either of 3 or 4

Asked In TCS ashish (10 years ago)

Unsolved Read Solution (11)

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Read Solution (11) :

BHASKAR MANDAL  (10 years ago)

getting the sum as multiple of 3 and 4
=> getting 3,4,6,8,9,12

getting
3-> (1,2),(2,1)
4-> (1,3),(2,2),(3,1)
6-> (1,5),(2,4),(3,3),(4,2),(5,1)
8-> (2,6),(3,5),(4,4),(5,3),(6,2)
9-> (3,6),(4,5),(5,4),(6,3)
12->(6,6)
total possibility = 2+3+5+5+4+1 = 20
probability = 20/36 = 0.55

Is this solution Helpfull? Yes (22) | No   

dinesh kumar  (10 years ago)

answer is 5/9

Is this solution Helpfull? Yes (2) | No   

Ayush Upadhyaya  (10 years ago)

total favourable events=20
total events=36
probability=20/36=5/9

Is this solution Helpfull? Yes (2) | No   

Ravi teja Mantha  (10 years ago)

probability = 20/36 = 0.55

Is this solution Helpfull? Yes (1) | No   

Dharmendra Ramanujan  (10 years ago)

for sum of multiple of 3 and 4
getting 3,4,6,8,9,12
3-> (1,2),(2,1)
4-> (1,3),(2,2),(3,1)
6-> (1,5),(2,4),(3,3),(4,2),(5,1)
8-> (2,6),(3,5),(4,4),(5,3),(6,2)
9-> (3,6),(4,5),(5,4),(6,3)
12->(6,6)
total possibility = 2+3+5+5+4+1 = 20
probability = 20/36 =5/9

Is this solution Helpfull? Yes (1) | No (1)  

neha  (10 years ago)

20/36= 5/9

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naveen kumar  (10 years ago)

getting mul of 3 is = 12/36
getting mul of 4 is = 8/36
here they give clue as "OR" so we can add both the things
so,we get (12/36)+(8/36)=(20/36)=(5/9)

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Ram  (10 years ago)

sum is multiple of 3----3,6,9,12
sum is multiple of 4----4,8,12
3-----[21]
6-----[15][24][33]
9-----[63][54]
12----[66]
4-----[13][22]
8-----[26][53][44]
so combinations to get on 2 dice = 8*(2!)+4=20
probability=20/(6*6)=5/9

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Saranya .C  (10 years ago)

getting the sum as multiple 3 & 4


(1,2),(1,3),(1,5)
(2,1),(2,2),(2,4),(2,6)
(3,1),(3,3),(3,5),(3,6)
(4,2),(4,4),(4,5)
(5,1),(5,3),(5,4)
(6,2),(6,3),(6,6)

total no of possibility=3+4+4+3+3+3=20
probability=20/36=5/9

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aiyaz sarwar  (10 years ago)

this is a single throw so fav events will be 12 and total is 36 bhence probability is 12/36................can any1 clarify how twenty fav events when there is single throw

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Bhargav  (2 years ago)

4/36 sice 1,2 2,1 1,3 3,1

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