Latest TCS Aptitude Question SOLUTION: The identical circles intersect their centres,and the points at which they intersect,form a square of side 1 cm .the area in sq.cm of portion that is common to the two circles is

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(#M40039891) TCS Numerical Ability question Keep an EYE

The identical circles intersect their centres,and the points at which they intersect,form a square of side 1 cm .the area in sq.cm of portion that is common to the two circles is :

a. sqrt 5
b. 4
c. pie/2-1
d. sqrt2-1

Asked In TCS priyanka (10 years ago)

Unsolved Read Solution (3)

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abhinav  (10 years ago)

two identical circles are intersects at center, and form a square so radious =1 cm.
area of arc ay 90*= (90/360)pi**1*1=pi/4
and area of triangle=1/2*1*1
so area of common part= 2*[(pi/4)-1/2]= pi/2-1 ans....

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PawanChandra  (10 years ago)

Area of sector -Area of Square
assume area of one sector as a semi-cirlce for which diagonal of a square is the diameter diagonal= sqrt(2)
half of the diagonal=1/root2= radius of semicirlce
area of semicirlcle= 1/2(pi*1/root2*1/root2);
for another sector also same so, total area of sector=pi/2;
and
area of square=1*1=1
so,ans is pi/2-1;

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priya  (10 years ago)

ANS:3)pie/2-1

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