Latest Group Aptitude Question SOLUTION: A man can row 30 km upstream and 44 km downstream in 10 hours. Also, he can row 40 km upstream and 55 km downstream in 13 hours. Find the rate of current and the speed of the man i

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(#M40039946) GROUP Logical Reasoning question Keep an EYE

A man can row 30 km upstream and 44 km downstream in 10 hours. Also, he can row 40 km upstream and 55 km downstream in 13 hours. Find the rate of current and the speed of the man in still water.

Asked In Group Venkatesha Perumal (10 years ago)

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Venkatesha Perumal  (10 years ago)

Let rate upstream = x km / hr and rate downstream = y km / hr.
Then, 40x+ 55y =13 ...(i)
and 30x+44y=10 ...(ii)
Multiplying (ii) by 4 and (i) by 3 and
subtracting, we get y=11.
Substituting y = 11 in (j), we get : x =
5.
Rate in still water =12(11+5)kmph=8kmph.
Rate of current= 12(11−5) kmph=3kmph.

Is this solution Helpfull? Yes | No   

Venkatesha Perumal  (10 years ago)

Let rate upstream = x km / hr and rate downstream = y km / hr.
Then, 40x+ 55y =13 ...(i)
and 30x+44y=10 ...(ii)
Multiplying (ii) by 4 and (i) by 3 and
subtracting, we get y=11.
Substituting y = 11 in (j), we get : x =
5.
Rate in still water =12(11+5)kmph=8kmph.
Rate of current= 12(11−5) kmph=3kmph.

Is this solution Helpfull? Yes | No   

Venkatesha Perumal  (10 years ago)

Let rate upstream = x km / hr and rate downstream = y km / hr.
Then, 40x+ 55y =13 ...(i)
and 30x+44y=10 ...(ii)
Multiplying (ii) by 4 and (i) by 3 and
subtracting, we get y=11.
Substituting y = 11 in (j), we get : x =
5.
Rate in still water =12(11+5)kmph=8kmph.
Rate of current= 12(11−5) kmph=3kmph.

Is this solution Helpfull? Yes | No   

Venkatesha Perumal  (10 years ago)

Let rate upstream = x km / hr and rate downstream = y km / hr.
40x+ 55y =13 ...(i)
30x+44y=10 ...(ii)
subtracting, we get y=11.
Substituting y = 11 in (j), we get : x =5.
Rate in still water =12(11+5)kmph=8kmph.
Rate of current= 12(11−5) kmph=3kmph.

Is this solution Helpfull? Yes | No   

Venkatesha Perumal  (10 years ago)

Let rate upstream = x km / hr and rate downstream = y km / hr.
40x+ 55y =13 ...(i)
30x+44y=10 ...(ii)
subtracting, we get y=11.
Substituting y = 11 in (j), we get : x =5.
Rate in still water =12(11+5)kmph=8kmph.
Rate of current= 12(11−5) kmph=3kmph.

Is this solution Helpfull? Yes | No   

Venkatesha Perumal  (10 years ago)

Let rate upstream = x km / hr and rate downstream = y km / hr.
40x+ 55y =13 ...(i)
30x+44y=10 ...(ii)
subtracting, we get y=11.
Substituting y = 11 in (j), we get : x =5.
Rate in still water =12(11+5)kmph=8kmph.
Rate of current= 12(11−5) kmph=3kmph.

Is this solution Helpfull? Yes | No   

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