Latest Miscellaneous Company Exam Aptitude Question SOLUTION: . sum of the consequent 7 integers some 1613. Find the no. of prime numbers in that sequence

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(#M40007075) MISCELLANEOUS COMPAN Numerical Ability question Keep an EYE

. sum of the consequent 7 integers some 1613. Find the no. of prime numbers in that sequence

Asked In Miscellaneous Company Exam sankha chowdhury (12 years ago)

Unsolved Read Solution (7)

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Read Solution (7) :

Bruce Wayne  (11 years ago)

WRONG QUESTION!!
CORRECT QUESTION: Sum of the consequent 7 integers equals 1617. Find the no. of prime numbers in that sequence.

SOLUTION:
Let the numbers be x, x+1, x+2, x+3, x+4, x+5, x+6
Since their sum equals 1617, we have-
x+(x+1)+(x+2)+(x+3)+(x+4)+(x+5)+(x+6)=1617
7x+21=1617
7x=1596
x=228

Hence the numbers are: 228,229,230,231,234,235,236
Prime Numbers: 229, 231

Is this solution Helpfull? Yes (56) | No (19)  

rachana dhekane  (11 years ago)

wrong question..please submit correct1..thank you bruce!!!

Is this solution Helpfull? Yes (8) | No (4)  

sushant langade  (10 years ago)

Let the numbers be x, x+1, x+2, x+3, x+4, x+5, x+6
Since their sum equals 1617, we have-
x+(x+1)+(x+2)+(x+3)+(x+4)+(x+5)+(x+6)=1617
7x+21=1617
7x=1596
x=228

Hence the numbers are: 228,229,230,231,232,233,234
Prime Numbers: 229, 231,233

Is this solution Helpfull? Yes (7) | No (5)  

Rohit Patnaik  (10 years ago)

How 231 become a prime no.?? 231 is divisible by 3 231/3=77

Is this solution Helpfull? Yes (6) | No   

Swaraj Behera  (11 years ago)

Let the numbers be x, x+1, x+2, x+3, x+4, x+5, x+6
Since their sum equals 1617, we have-
x+(x+1)+(x+2)+(x+3)+(x+4)+(x+5)+(x+6)=1617
7x+21=1617
7x=1596
x=228

Hence the numbers are: 228,229,230,231,234,235,236
Prime Numbers: 229, 231

Is this solution Helpfull? Yes (5) | No (11)  

Moiz Lokhandwala  (9 years ago)

Let the numbers be x, x+1, x+2, x+3, x+4, x+5, x+6
Since their sum equals 1617, we have-
x+(x+1)+(x+2)+(x+3)+(x+4)+(x+5)+(x+6)=1617
7x+21=1617
7x=1596
x=228

Hence the numbers are: 228,229,230,231,234,235,236

Prime numbers are:- 229 and 233

Is this solution Helpfull? Yes (3) | No   

akhilesh singh  (10 years ago)

Let the numbers be x, x+1, x+2, x+3, x+4, x+5, x+6
Since their sum equals 1617,
we have-
x+(x+1)+(x+2)+(x+3)+(x+4)+(x+5)+(x+6)=1617
7x+21=1617
7x=1596
x=228

Hence the numbers are: 228,229,230,231,232,233,234
Prime Numbers: 229,231,233

Is this solution Helpfull? Yes (1) | No (2)  

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