Latest Elitmus Aptitude Question SOLUTION: if n>0 a(n)=1/log base n ^2002 then what is the value of a1+a2+a3+a4-a11-a12-a13-a14..?

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(#M40074931) ELITMUS Numerical Ability question logarithim Keep an EYE

if n>0
a(n)=1/log base n ^2002 then what is the value of a1+a2+a3+a4-a11-a12-a13-a14..?

Asked In Elitmus Masood Ahmad (9 years ago)

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Shashank Shekhar Singh  (9 years ago)

Anant look from line-
=log base 2002^1 + log base 2002^2 + log base 2002^3 + log base 2002^4 + log base 2002^5 - log base 2002^11 -log base 2002^12 -log base 2002^13 -log base 2002^14
=log base 2002^(1*2*3*4*5)- log base ^(10*11*12*13*14*)
=log base 2002^(1*2*3*4*5/10*11*12*13*14)
=log base 2002^(1/11*13*14)
=log base 2002^(1/2002)
=-log base 2002^(2002)
=-1

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Sunanda Anand  (9 years ago)

question is wrong a1+a2+a3+a4+a5-a10-a11-a12-a13-a14
answer is -1

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suresheca2012@gmail.com  (9 years ago)

a1+a2+a3+a4+a5-a10-a11-a12-a13-a14=?
using log property log base a^b = 1/ log base b^a
1/ log base 1^2002 + 1/ log base 2^2002 + 1/ log base 3^2002 + 1/ log base 4^2002 + 1/ log base 5^2002 - 1/ log base 11^2002 - 12/ log base 13^2002 - 1/ log base 14^2002
= log base 2002^1 + log base 2002^2 + log base 2002^3 + log base 2002^4 + log base 2002^5 - log base 2002^11 -log base 2002^12 -log base 2002^13 -log base 2002^14

u can solve it.....
n ans is = -1

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ANANT VIKRAM SINGH  (9 years ago)

pls solve....how -1

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