Latest L&T Aptitude Question SOLUTION: 29. The perimeter of a rhombus is 52 units. One of its diagonal is 24 units. What is its second diagonals length? Ans: 10

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29. The perimeter of a rhombus is 52 units. One of its diagonal is 24 units. What is its second diagonals length?
Ans: 10

Asked In L&T (13 years ago)

Unsolved Read Solution (5)

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Sanjana Patnaik  (13 years ago)

When the perimeter of a triangle is 52 units each side is 13 units
Next, the diagonal of a rhombus bisect each other at 90 degree
Thus the half of the diagonal is 12 units
Now in a right angle triangle so formed, the perpendicular is 12 and the hypptenuse is 13(that is the side of the triangle)
Finding the base(which is half of the other diagonal):
13^2-12^2 =25
Thus half of the diagonal is 5 and the diagonaL IS 10UNITS

Is this solution Helpfull? Yes (29) | No (1)  

mary  (11 years ago)

The thing about a rhombus is that its sides are all equal, so the length is 13, and the diagonals bisect each other, at a right angle.
If you draw a rhombus, you see that the diagonals make 4 right angled triangles, and you have the length of two sides (one 12 and the other 13), so half the remaining diagonal has to be 5 i.e.sqrt(13^2-12^2)=5
2nd diagonal lenth=2*5=10

Is this solution Helpfull? Yes (9) | No   

akshit  (7 years ago)

Take PQRS is a point of rhombus .
1st Diagonal PR=24 units
2nd Diagonal QS
now take O as a center of Diagonal PR . so , PO=24/2=12
we know that side of rhombus is equal.
so perimeter/4= 52/4 =13
so PQ=13
now QO find by pythagoras theorem =5
so QS =2 * QO =10

ANS=10

Is this solution Helpfull? Yes (2) | No   

gurjeet  (8 years ago)

Diagonal of rhombus=2¤{d1^2+d2^2}=52
52/2=26
0ne of diagnal is 24.
so 24^2+x^2=26^2
=676
X^2=676-576=100

So x=10

Is this solution Helpfull? Yes | No (1)  

Divya Batra  (7 years ago)

formula is:
(side)^2=(d1/2)^2+(d2/2)^2
side=perimeter/4=52/4=13
d1/2=24/2=12
therefore, d2/2=5 units
hence, d2=5*2=10 units

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