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(#M40009075) SELF question Easy one? Keep an EYE

It is a 6 digit number.
Sum of 3rd and 4th digits is equal to Sum of 2nd and last digit.
5th digit is double of 2nd digit.
1st digit is equal to sum of 2nd and 4th digits.
3rd digit is double of 4th digit.
Final Clue: 5th digit is three greater than 2nd digit.

Find that number

Vignesh (12 years ago)

Unsolved Read Solution (3)

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kusuma  (12 years ago)

let the number be abcdef
c+d=b+f
e=2b
a=b+d
e=b+3
equate e's
2b=b+3
b=3;
e=6;
now we have c+d=3+f;
a=3+d;
assume d=1,then a=4;
assume f=2 then c=4;


the number is 434162

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Aradhana  (12 years ago)

let the digits be a,b,c,d,e,f.
A/Q; c+d=b+f....(1) , e=2b....(2) , a=b+d....(3) , c=2d....(4) , e=b+3....(5)
on solving (2) & (5): 2b=b+3 i.e.,b=3 & e=6
likewise substituting (4) in (1): 3d=3+f & frm above a=3+d.
on solving for d,we get: 4d=a+f
substituting value of d in a=3+d,we get: 3a=12+f
substituting value of f & d from above in (1): 2a=6+c
so finally the equations are : 2a=6+c, 3a=12+f, 3d=3+f, 4d=a+f
The min value of a to satisfy the equatn is 4.(as a=3 will not satisfy for 3a=12+f)
so put a=4 n solve for the unknowns.
a=4,b=3,c=2,d=1,e=6,f=0.
so the no. is : 432160
the no. can also be : 636366 for a=6

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arunraj  (12 years ago)

let the number be ABCDEF
C+D=B+F
E=2B
A=B+D
E=B+3
equate E's
2B=B+3 => B=3 ; E=6;
assume D is 3;
so C=6;
C+D = B+F So 6+3 = 3+F ;
Therefore F=6;
A= B + D;
Therefore A=9
The Number is = 936366

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