For TCS exam preparation you can go to placement puzzle section or you can use http://www.m4maths.com/placement-puzzles.php?SOURCE=tcs link. try to check all maximum question. Best of Luck

from the que u see that S+M=MO that means their is two digit no so the value of M is not greater then 1 so M=1.
and when M is 1 so that means S is 9 hence the total is 10 so the value of O is 0.

so
9END
+ 10RE
--------
10NEY

as we at third place E+0=N its not possible so their is carry from the last place hence E+1=N.
and from second place N+R+0/1=E+10
so putting the value of N from last eq we getting the value of R=8/9. But we use 9 for S so the value of R=8.
so the new eq is E+1=N and N+8+(1)=E {here 1 is used for carry}

so their is many combination like (1,2)(2,3)(3,4)(4,5)(5,6)(6,7)(7,8)(8,9) for the value of E and N but the possible combination is (5,6) so the vale of E and N is 5 and 6.

so 956D
+ 1085
----------
1065Y

so for genrate the carry in second place no 7 is used.

so
the ans is

9567
+ 1085
--------
10652



if their is any doubt then plz.....ask

can any one package of syntel

can anyone know package of syntel