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ganesh reddy to G.S.Kantharao 4 years ago

i got answer 1:1 but there is no option

Reply Like? Yes (1) | No

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ganesh reddy 4 years ago

Gold is 19 times as heavy as water and copper is 9 times as heavy as water. In
what ratio should these be mixed to get an alloy 15 times as heavy as water.

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Devendra Marghade 4 years ago

Required ratio = (15-9)/(19-15) = 6/4 = 3/2
Therefore, these should be mixed in the ratio 3:2.

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AYAN PAUL 4 years ago

Does anyone think that the prize system of today's puzzle needs to be changed and it needs to return the earlier system of distribution of prize amount. Whoever wants to win the prize needs to compete with other candidates. Otherwise there is no benefit of becoming topper of the week again if you already won a prize in a month.

Reply Like? Yes (3) | No (1)

ganesh reddy 4 years ago

In what respective ratio must water be mixed with juice costing Rs 16 per litre to
obtain a mixture worth Rs 12 per litre ?

Reply Like? Yes (1) | No

Devendra Marghade 4 years ago

Water. Juice
0 -------------------------- 16
12
(16-12). ---------------- (12-0)
=4 =12
Therefore, ratio of water & juice = 4 : 12 = 1 : 3

Like? Yes (3) | No

Pushyamithra Gyadhari to Roopa 4 years ago

22000 is correct

Reply Like? Yes | No

Mayank 4 years ago

Select the right option from the given alternativesKPQR:LRTV:DGHY:?
1 point
A) EIKC
B) ETKC
C) EJKD
D) EHKD

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AYAN PAUL 4 years ago

Answer is : EIKC (Option A)

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ASM Zahadul Hoq 4 years ago

20% of the people own only two cars each, 40% of the remaining, own three cars each and the remaining members own only one car each. Which statement is true ?

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Sunil 4 years ago

Vedik ganit
https://youtu.be/YzFMYk4s2JE

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Dimple 4 years ago

For today's puzzle,
CP comes out to be Rs. 28000.
Sp is Rs. 5000.
Loss= Rs. 23000..nobe of given options
But answer has been accepted by calculating loss difference of two selling prices.
What a murder of maths!

Why to calculate cp, if not required to calculate loss.
Please think, think and think if pissible.

Reply Like? Yes (6) | No

Dr.Dipin Singh 4 years ago

Good observation.
I think Site administrators are busy somewhere else due to lockdown.
or
Puzzles are being checked by Kirana merchants who are inable to open shops and they compare loss with max sale price (MSP).

Please check and respond .

Like? Yes (3) | No

Dr.Dipin Singh 4 years ago

Good observation.
I think Site administrators are busy somewhere else due to lockdown.
or
Puzzles are being checked by Kirana merchants who are unable to open shops and they compare loss with max sale price (MSP) to be expected or max gain possible.

Please check and respond .

Like? Yes (4) | No

Jagat 4 years ago

Answer should be Rs. 23000/-
option 10. None of these

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Nikhil 4 years ago

best placement questions ...thank u m4maths

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Parth M 4 years ago

In a class if 1 is absent the rest of them can be divided into 6 equal groups and if two are absent can be divided into 7 equal groups. Find the minimum number of students in the class

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Debayani Chakraborty 4 years ago

6*6=36
If we assume the number is 37 then
37-1=36 divisible by 6
And 37-2=35 divisible by 7

Like? Yes | No (1)

Devendra Marghade 4 years ago

Let the number of students be 'x' then x-1=6y and x-2=7z
=> 6y+1 = 7z+2 or 6y - 7z = 1
Which is true for y=6, z=5
So, minimum number of students=6y+1 or 7z+2 = 37

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Reyaz Dar 4 years ago

Find the largest 2- digit number which when divided by 2,3 and 5 leaves remainder 1, 2 and 4....Any short trick please.

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Debayani Chakraborty 4 years ago

Calculate the l. C. M
That is 30 , 30+4=34 when divisible by 3 gives one remainder but does got go with 2,5 . So the next number can be 37. It helds all the option

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Leander 4 years ago

https://en.m.wikipedia.org/wiki/File:FCOC.jpg

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Leander 4 years ago

https://en.m.wikipedia.org/wiki/File:FCOC.jpg

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antim yadav 4 years ago

MADAN=CODPC
REENA=.....?

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G.S.Kantharao 4 years ago

MADAN=CODPC
REENA=.....?=GTECP

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Suparna Dutta to SAYAN CHATTERJEE 4 years ago

Please help with this problem.
If two numbers are divided by a dividor produce remaindes 3 and 4, but then the sum of the numbers is divided by that divisor gives remainder 2. Find the divisor.

Reply Like? Yes (1) | No

Devendra Marghade 4 years ago

Ans=5

Let the divisor be a, first no. be x and second no. be y, then in given 3 conditions
X = ak + 3 —(i)
y = al + 4 —(ii)
x+y = am + 2 —(iii)
Adding (i) & (iii), and Substituting x+y in (iii), we get (ak+3) + (al+4) = am+2
a(m-k-l) = 5
Prime factorization gives a=5 or 1
As divisor cannot be 1 in above given conditions, so divisor a=5.

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