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(#M40001707) TCS QUESTION 2010 question Keep an EYE

On planet korba, a solar blast has melted the ice caps on its equator. 9 years after the ice melts, tiny planetoids called echina start growing on the rocks. Echina grows in the form of circle, and the relationship between the diameter of this circle and the age of echina is given by the formula d = 4*(t-9) for t>9, where d represents the diameter in mm and t the number of years since the solar blast. Jagan recorded the radius of some echina at a particular spot as 7mm. How many years back did the solar blast occur?
a) 17 b) 21.25 c) 12.25 d) 14.05

Solution

some fonts in the question are meaningless, so it is difficult to understand the meaning clearly. If we consider the meaning as d = 4*(t-9) then according to the given condition r = 7 mm so diameter = 14 mm, on putting d = 14, we get
14 = 4*(t-9) or 3.5 = t-9 or t = 12.5

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(#M40001699) TCS QUESTION latest puzzle Keep an EYE

There are two pipes A and B. If A filled 10 liters in an hour, B can fill 20 liters in same time. Likewise B can fill 10, 20, 40, 80, 160. If B filled 1/16 of a tank in 3 hours, how much time will it take to fill the tank completely?
a) 9 B) 8 c) 7 d) 6

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(#M40001697) TCS QUESTION puzzle Keep an EYE

Find the value of @@+25-++@16, where @ denotes square and + denotes square root and - has its usual meaning

Solution

@@5-++256
=@25-+16
=625-4
=621
This answer is given by SOMIL NAIN and is correct answer

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(#M40001660) TCS QUESTION december 2010 question Keep an EYE

In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
(a) 1 hour (b) 2 hours (c) 3 hours (d) 4 hours

Solution

suppose avg speed of aircraft is v km/hr,and it takes t hr to trip 600 km.
then t=600/v.......(1)
now avg speed slowed down by 200 km/hr and it takes 30 more minutes that means now it takes t+30/60=t+1/2 hr and speed is v-200
now time=distance/speed=>t+1/2=600/(v-200)
2t+1=1200/(v-200)
(2t+1)(v-200)=1200
(2t+1)((600/t)-200))=1200 from (1)
on solving it t= -3/2 or 1
time cant be -ve,hence answer is 1 hr.
This answer is given by MOHD ANAS and is correct answer

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(#M40001656) TCS QUESTION 2010 question Keep an EYE

. In how many different ways can the letters of the word 'LEADING' be arranged in such a way that the vowels always come together?
(a) 360 (b) 480 (c) 720 (d) 5040

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(#M40001653) TCS QUESTION latest 2010 question Keep an EYE

Two trains move in the same direction at speeds 50 kmph and 32 kmph respectively. A man in the slower train observes that 15 seconds elapse before the faster train completely passes by him. What is the length of faster train?
(a) 100m (b) 75m (c) 120m (d) 50m

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(#M40001651) TCS QUESTION puzzle 2010 Keep an EYE

. 2 oranges, 3 bananas and 4 apples cost Rs.15. 3 oranges, 2 bananas, and 1 apple costs Rs 10. What is the cost of 3 oranges, 3 bananas and 3 apples?
(a) Rs10 (b) Rs15 (c) Rs20 (d) Rs25

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(#M40001650) TCS QUESTION puzzle 2010 Keep an EYE

A bus started from bus stand at 8.00a m and after 30 min staying at destination, it returned back to the bus stand. The destination is 27 miles from the bus stand. The speed of the bus 50 percent fast speed. At what time it returns to the bus stand.
(a) 11a.m (b) 12a.m (c) 10a.m (d) 10.30p.m

Solution

The question is not complete, it should also be given in the question that average speed of the bus is equal to the starting speed of the bus
if we make this correction then answer by RAJAT SHARMA given below is correct

the answer is 11 a.m. ..........
let the initial speed of bus is V.....so it takes time in going T1 = 27/V and speed increases 50 %, while returning so time taken T2 = 27/(1.5V) = 18/V and it stops for 30 mins i.e., (.5 hr),
therefore total time taken T =(27/V)+(18/V)+(.5).
then average speed, V = total dist. traveled / total time
i.e.,V=2*27/T on solving we get V = 18 mph
hence finally time taken while going = 1.5hr + staying time (.5hr.) + time in returning with increased speed of 27 mph (1hr.)
hence total time taken=3 hrs. hence 11a.m.

but if we use the initial speed (18 mph) as a given term, then answer given below by YADEESHKUMAR is correct
ans is a)11am
bus covers 27 miles with 18mph in= 27/18 = 1 hr. 30 min.
it waits at stand = 30min.
after this, speed of return increases by 50 % so 50 % of 18 mph = 9 mph
total speed of returning = 18+9 = 27 mph
then in return it takes 27/27 = 1hr.
thus total time in journey = 1+1.30+0.30 = 3hr
so it will come at 8+3hr=11am.


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(#M40001646) TCS QUESTION question 2010 Keep an EYE

A man jogs at 6 mph over a certain journey and walks over the same route at 4 mph. What is his average speed for the journey?
(a) 2.4 mph (b) 4 mph (c) 4.8 mph (d) 5 mph

Solution

Let the length of the journey = x
so time taken = x/6 for first and x/4 for second journey
so avg. velocity = (x+x)/[(x/6)+(x/4)] = 4.8

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(#M40001643) TCS QUESTION puzzle 2010 Keep an EYE

It is dark in my bedroom and I want to get two socks of the same color from my drawer, which contains 24 red and 24 blue socks. How many socks do I have to take from the drawer to get at least two socks of the same color?
(a) 2 (b) 3 (c) 48 (d) 25

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