• Placement Questions

Frequently Asked Interview Questions and Answers

(#M40000614) TCS QUESTION Keep an EYE

Two unemployed young men decided to start a business together. They pooled in their savings, which came to Rs. 2,000. They were both lucky, their business prospered and they were able to increase their capital by 50 per cent every three years. How much did they have in all at the end of eighteen years?
option
(a) Rs. 22,781.25
(b) Rs. 24,150.25
(c) Rs. 28,140.50
(d) Rs. 18,000

Asked In TCS Sumandeep Ghosh (14 years ago)

Solved mohd anas Read Solution (2)

Is this Puzzle helpful?   (8)   (2) Submit Your Solution

(#M40000626) TCS QUESTION Keep an EYE

7. Two unemployed young men decided to start a business together. They pooled in their savings, which came to Rs. 2,000. They were both lucky, their business prospered and they were able to increase their capital by 50 per cent every three years. How much did they have in all at the end of eighteen years?



(a) Rs. 22,781.25 (b) Rs. 24,150.25 (c) Rs. 28,140.50 (d) Rs. 18,000

Asked In TCS anuj (14 years ago)

Solved Pritam Kumar Paul Read Solution (1)

Is this Puzzle helpful?   (4)   (2) Submit Your Solution Age Problem

(#M40000560) INFOSYS QUESTION find the number of man Keep an EYE

There were totally 100 men.85 are married.75 have T.V, 85 have radio,70 have A.C. How many men have T.V, radio, A.C and also married?

Asked In Infosys Aditi Sharma (14 years ago)

Solved Suman Read Solution (2)

Is this Puzzle helpful?   (6)   (0) Submit Your Solution Number System

(#M40000559) INFOSYS QUESTION match puzzle Keep an EYE

There was a match to be held.And 100 nations were to participate in that match.It was totally an elimination match,that is if a team loses a match it must be eliminated.Find out the total number of matches played to find out the grand winner?

Asked In Infosys Aditi Sharma (14 years ago)

Solved Suman Read Solution (3)

Is this Puzzle helpful?   (6)   (1) Submit Your Solution Permutation and Combination

(#M40000648) TCS QUESTION Keep an EYE

A circular dartboard of radius 1 foot is at a distance of 20 feet from you. You throw a dart at it and it
hits the dartboard at some point Q in the circle. What is the probability that Q is closer to the center of the circle than the periphery?
option
a) 0.75
b) 1
c) 0.5
d) 0.25

Solution

Since according to requirement we have to locate Q closer to center in comparison to the circumference, for doing this we shall make a circle in that board whose radius will be half of the radius of dartboard.now we will compare the area of inner circle to the total area
Answer of DIPIN is correct
area of whole circle = pi*(1 foot)^2 = pi (this is according to formula area = pi*(radius)^2
similarly area of inner circle = pi*(1/2foot)^2 = pi/4
so ratio of areas of these two circles will be the probability and that is 1/4


Like manish sir answer on facebook.

Asked In TCS Bhavani (14 years ago)

Solved Read Solution (3)

Is this Puzzle helpful?   (9)   (5) Submit Your Solution

(#M40000645) TCS QUESTION Keep an EYE

Given 3 lines in the plane such that the points of intersection form a triangle with sides of length 20, 20 and 30, the number of points equidistant from all the 3 lines is
option
a) 1
b) 3
c) 4
d) 0

Solution

Answer will be (c)
There will be four points satisfying the given condition
one point will be incentre of the circle and other three will be excentres


Like manish sir answer on facebook.

Asked In TCS (14 years ago)

Solved Read Solution (4)

Is this Puzzle helpful?   (7)   (2) Submit Your Solution Coding Decoding

(#M40000605) TCS QUESTION Keep an EYE

1! + 2! +......... + 50!=?
a)3.1035*10^64
b)2.1021*10^65
c)3.1035*10^63
d)3.1035*10^62

Solution

solve 50! + 49! + 48!
others are lower terms
this can be done by calculator only

Like manish sir answer on facebook.

Asked In TCS Sumandeep Ghosh (14 years ago)

Solved SANTOSH AGRASINGH Read Solution (2)

Is this Puzzle helpful?   (13)   (9) Submit Your Solution Sequence and Series

(#M40000604) TCS QUESTION Keep an EYE

Given a collection of points P in the plane , a 1-set is a point in P that can be separated from the rest by a line, .i.e the point lies on one side of the line while the others lie on the other side. The number of 1-sets of P is denoted by n1(P). The minimum value of n1(P) over all configurations P of 5 points in the plane in general position (.i.e no three points in P lie on a line) is
a) 3
b) 5
c) 2
d) 8

Solution

The meaning of this question is little complicated. In easy language the question should be:


There are some points in the plane. We have to make a separation between these points by forming a line in such a way that one point could be separate from the others. No 3 points are in a line. Maximum no of methods for plotting the line and minimum no of methods for plotting the line will be (arrangement of points is your choice)

Now Answer Is:

For Maximize: The number of methods, Points should be drawn in the circumference of the CIRCLE So answer would be the number of total point in the plane.

For minimize: The number of methods we should draw 3 points in a TRIANGLE and all other point inside this triangle in such a way that no 3 points could be in a line.

If it will be allowed to draw the points in a line then minimum possibilities will be 2 only, because if we take all points in a line then you can separate only the corner points from the others.

For example
If we have 10 points then maximum possibilities = 10
and minimum = 3

similarly for 5 points
Max = 5, Min = 3

for 19
max= 19 Min = 3


Like manish sir answer on facebook.

Asked In TCS Sumandeep Ghosh (14 years ago)

Solved Read Solution (5)

Is this Puzzle helpful?   (7)   (4) Submit Your Solution Blood Relations

(#M40000546) SELF QUESTION Keep an EYE

A circular dartboard of radius 1 foot is at a distance of 20 feet from you. You throw a dart at it and it hits the dartboard at some point Q in the circle. What is the probability that Q is closer to the center of the circle than the periphery?
a) 0.75
b) 1
c) 0.25
d) 0.5

Sayan Bera (14 years ago)

Solved S Ranjith Kumar Read Solution (2)

Is this Puzzle helpful?   (18)   (4) Submit Your Solution

(#M40000436) TCS QUESTION Keep an EYE

The pacelength P is the distance between the rear of two consecutive footprints. For men, the formula, n/P = 144 gives an approximate relationship between n and P where, n = number of steps per minute and P = pacelength in meters. Bernard knows his pacelength is 164cm. The formula applies to Bernard's walking. Calculate Bernard's walking speed in kmph.

Asked In TCS kumar abhinandan (14 years ago)

Solved Manikanta Read Solution (2)

Is this Puzzle helpful?   (11)   (4) Submit Your Solution Algebra