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Frequently Asked c interview questions and answers for freshers Page 39

(#M40029237) C QUESTION C Keep an EYE

output?
main()
{i
nt i=5;
printf("%d%d%d%d%d%d",i++,i--,++i,--i,i);
}

Answer: 45545

Explanation: The arguments in a function call are pushed into the stack from left to right. The evaluation is by popping out from the stack. And the evaluation is from right to left, hence the result.

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(#M40029234) C QUESTION C Keep an EYE

output??
#include
main()
{
struct xx
{i
nt x=3;
char name[]="hello";
};
struct xx *s;
printf("%d",s->x);
printf("%s",s->name);
}

Answer: Compiler Error

Explanation: You should not initialize variables in declaration

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(#M40029232) C QUESTION C Keep an EYE

#include
main()
{
char s[]={'a','b','c','n','c',''};
char *p,*str,*str1;
p=&s[3];
str=p;
str1=s;
printf("%d",++*p + ++*str1-32);
}

Answer: 77

Explanation: p is pointing to character 'n'. str1 is pointing to character 'a' ++*p. "p is pointing to
'n' and that is incremented by one." the ASCII value of 'n' is 10, which is then incremented to
11. The value of ++*p is 11. ++*str1, str1 is pointing to 'a' that is incremented by 1 and it
becomes 'b'. ASCII value of 'b' is 98.
Now performing (11 + 98 – 32), we get 77("M"); So we get the output 77 :: "M" (Ascii is 77).

output??

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(#M40029230) C QUESTION C Keep an EYE

main()
{i
nt c=- -2;
printf("c=%d",c);
}
Answer: c=2;
Explanation: Here unary minus (or negation) operator is used twice. Same maths rules applies,
ie. minus * minus= plus.
Note: However you cannot give like --2. Because -- operator can only be applied to variables as
a decrement operator (eg., i--). 2 is a constant and not a variable

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(#M40029228) C QUESTION C Keep an EYE

output??
main()
{
printf("%x",-1

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(#M40029227) C QUESTION C Keep an EYE

output??
main()
{
char *p;
printf("%d %d ",sizeof(*p),sizeof(p));
}
Answer: 1 2
Explanation: The sizeof() operator gives the number of bytes taken by its operand. P is a
character pointer, which needs one byte for storing its value (a character). Hence sizeof(*p)
gives a value of 1. Since it needs two bytes to store the address of the character pointer
sizeof(p) gives 2.

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(#M40029226) C QUESTION C Keep an EYE

main()
{i
nt i=-1,j=-1,k=0,l=2,m;
m=i++&&j++&&k++||l++;
printf("%d %d %d %d %d",i,j,k,l,m);
}
Answer: 0 0 1 3 1
Explanation: Logical operations always give a result of 1 or 0. And also the logical AND (&&)
operator has higher priority over the logical OR (||) operator. So the expression ‘i++ && j++ &&
k++’ is executed first. The result of this expression is 0 (-1 && -1 && 0 = 0). Now the
expression is 0 || 2 which evaluates to 1 (because OR operator always gives 1 except for ‘0 || 0’
combination- for which it gives 0). So the value of m is 1. The values of other variables are also
incremented by 1.

find output

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(#M40029225) C QUESTION C Keep an EYE

main()
{
extern int i;
i=20;
printf("%d",i);
}
Answer: Linker Error : Undefined symbol '_i'
Explanation: extern storage class in the following declaration,
extern int i;
specifies to the compiler that the memory for i is allocated in some other program and that
address will be given to the current program at the time of linking. But linker finds that no other
variable of name i is available in any other program with memory space allocated for it. Hence a
linker error has occurred
find output

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(#M40029224) C QUESTION C Keep an EYE

How can I search for data in a linked list?
Unfortunately, the only way to search a linked list is with a linear search, because the only way
a linked list’s members can be accessed is sequentially.
Sometimes it is quicker to take the data from a linked list and store it in a different data
structure so that searches can be more efficient.

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(#M40029223) C QUESTION C Keep an EYE

What is the purpose of main( ) function ?
The function main( ) invokes other functions within it.It is the first function to be called when the
program starts execution.
· It is the starting function
· It returns an int value to the environment that called the program
· Recursive call is allowed for main( ) also.
· It is a user-defined function
· Program execution ends when the closing brace of the function main( ) is reached.
· It has two arguments 1)argument count and 2) argument vector (represents strings passed).
· Any user-defined name can also be used as parameters for main( ) instead of argc and argv

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