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(#M40000612) TCS QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

A Roman was born the first day of the 35th year before Christ and died the first day of the 35th year after Christ. How many years did he live?
option
(a) 70
(b) 69
(c) 71
(d) 72

Solution
A Roman was born the first day of the 35th year before Christ means before the start of year 0, 35 years has been past and died the first day of the 35th year after Christ means 35th year is about to start at his death so only 34 years has been completed so total years = 69


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Asked In TCS Sumandeep Ghosh (14 years ago)
Solved Read Solution (2)
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(#M40000594) TCS QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

A lady has fine gloves and hats in her closet- 18 blue, 32 red, and 25 yellow. The lights are out and it is totally dark. In spite of the darkness, she can make out the difference between a hat and a glove. She takes out an item out of the closet only if she is sure that if it is a glove. How many gloves must she take out to make sure she has a pair of each color?
a) 50
b) 8
c) 60
d) 42

Solution
It is not given that how many of these items are gloves and how many are hats, if we consider that all the items are gloves then according to my opinion 32+25+2 = 59 gloves, she must take out to make sure she has a pair of each color. But closest option is 60 so it will be the answer

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Asked In TCS Sumandeep Ghosh (14 years ago)
Solved Read Solution (1)
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(#M40000623) TCS QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

A and B play a game between them. The dice consist of colors on their faces(instead of number). When the dice are thrown, A wins if both show the same color, otherwise B wins. One die has 3 red faces and 3 blue faces. How many red and blue faces should the other die have if the both players have if the both players have the same chances of winning?
a) 5 red and 1 blue faces.
b) 1 red and 5 blue faces.
c) 3 red and 3 blue faces.

Asked In TCS Sumandeep Ghosh (14 years ago)
Unsolved Read Solution (2)
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(#M40000601) TCS QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

The bacteria has the probability of split into 3 and probability to die is 1/3rd of the total bacteria.Let the probability is P.Some of them survived with probability 1/5.Then which among the following relation is true?
a)P=1/3+1/5*3
b)P=1/5*(1/8-3)

Asked In TCS Sumandeep Ghosh (14 years ago)
Solved marudhupandian .p Read Solution (10)
Is this Puzzle helpful?   (18)   (10) Submit Your Solution Probability

(#M40000589) TCS QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

There are 7 meetings A,B,C,D,E,F,G .one meeting should happen in one day. Meeting A is on Sunday c and d meetings should happen after B. Then E ,F,G meetings should occur in three conjucutive days. And meeting g is on Saturday. Then meeting the should occur on which day?

Asked In TCS Sumandeep Ghosh (14 years ago)
Solved YadeeshKumar Read Solution (4)
Is this Puzzle helpful?   (7)   (0) Submit Your Solution Permutation and Combination

(#M40000615) TCS QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

A man divides Rs.8600 among 5 sons, 4 daughters and 2 nephews. If each daughter receives four times as much as each nephew, and each son receives five times as much as each nephew, how much does each daughter receive?
(a) Rs.800
(b) Rs.600
(c) Rs.200
(d) Rs.700

Asked In TCS Sumandeep Ghosh (14 years ago)
Unsolved Read Solution (3)
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(#M40000596) TCS QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

10men and 10 women are there, they dance with each other, is there possibility that 2 men are dancing with same women and vice versa?
a) 22
b) 20
c) 10
d) none

Asked In TCS Sumandeep Ghosh (14 years ago)
Solved YadeeshKumar Read Solution (5)
Is this Puzzle helpful?   (27)   (3) Submit Your Solution Letter Series

(#M40000603) TCS QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

Six friends decide to share a big cake. Since all of them like the cake, they begin quarreling who gets to first cut and have a piece of the cake. One friend suggests that they have a blindfold friend choose from well shuffled set of cards numbered one to six. You check and find that this method works as it should simulating a fair throw of a die. You check by performing multiple simultaneous trials of picking the cards blindfold and throwing a die. You note that the number shown by the method of picking up a card and throwing a real world die, sums to a number between 2 and 12. Which total would be likely to appear more often 8,9 or 10?
a) 8
b) All are equally likely
c) 9
d) 10

Solution
the best solution will be 7, and there will be total 6 cases for this choice (1,6), (2,5), (3,4), (4,3), (5,2), (6,1)
but this one is not in the choices so out of the 4 choices givem 8 will be the best choice. For this choice there are 5 methods (2,6), (3,5), (4,4), (5,3), (6,2)
similarly for 9 there are 4 choices (3,6), (4,5), (5,4), (6,3)
for 10 there are 3 choices (4,6), (5,5), (4,6)
Answer is (a)

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Asked In TCS Sumandeep Ghosh (14 years ago)
Solved Read Solution (5)
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(#M40000598) TCS QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

A volume of 10936 l water is in a container of sphere. How many semisphere of volume 4l each will be required to tranfer all the water into the small semispheres?
a) 2812
b) 8231
c) 2734
d) 4222

Asked In TCS Sumandeep Ghosh (14 years ago)
Solved Piyush Read Solution (5)
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(#M40000579) TCS QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

On the planet Oz, there are 8 days in a week- Sunday to Saturday and another day called Oz day. There are 36 hours in a day and each hour has 90 min while each minute has 60 sec. As on earth, the hour hand covers the dial twice every day. Find the approximate angle between the hands of a clock on Oz when the time is 12:40 am.
a) 71
b) 251
c) 111
d) 89

Solution
Since total hours in a day = 36 and
as on earth, the hour hand covers the dial twice every day.
so there will be 18 numbers from 1 to 18 in the clock.
when the time will be 12:40(hands will be at 12 and 8 marks in the clock), two hands of the clock will make an angle of 20*4 = 80 degree, here 20 is the angle between two numbers in the clock.
now for 80 min, advancement of the hour hand will be (20/90)*40 = 80/9
so total angle = 80 + (80/9) = 800/9 = 88.889 degree
if we consider the obtuse angle, then it will be 360-88.889 = 271.111 degree

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Asked In TCS Sumandeep Ghosh (14 years ago)
Solved Read Solution (4)
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