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(#M40000590) TCS QUESTION Keep an EYE

There are 9 weights like 16,19.156.26, 106,15,24,36 (in kg). There are three persons like rohit, sameer and imran. each lifts 3 types of weights. Rohit”s total lifted weight is 2 times than the weight lifted by rohit. What is the weight lifted by imran?

Asked In TCS Sumandeep Ghosh (14 years ago)

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(#M40000617) TCS QUESTION Keep an EYE

A pizza shop, there were 2 kinds of pizzas available. But now they have introduces 8 new types, a person buy two different type pizzas of new type in how many ways he can select?
option
(a) 24
(b) 43
(c) 56
(d) 58

Asked In TCS Sumandeep Ghosh (14 years ago)

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(#M40000619) TCS QUESTION Keep an EYE

If on an item a company gives 25% discount, they earn 25% profit. If they now give 10% discount then what is the profit percentage.
option
(a) 40%
(b) 55%
(c) 35%
(d) 30%

Asked In TCS Sumandeep Ghosh (14 years ago)

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(#M40000614) TCS QUESTION Keep an EYE

Two unemployed young men decided to start a business together. They pooled in their savings, which came to Rs. 2,000. They were both lucky, their business prospered and they were able to increase their capital by 50 per cent every three years. How much did they have in all at the end of eighteen years?
option
(a) Rs. 22,781.25
(b) Rs. 24,150.25
(c) Rs. 28,140.50
(d) Rs. 18,000

Asked In TCS Sumandeep Ghosh (14 years ago)

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(#M40000605) TCS QUESTION Keep an EYE

1! + 2! +......... + 50!=?
a)3.1035*10^64
b)2.1021*10^65
c)3.1035*10^63
d)3.1035*10^62

Solution

solve 50! + 49! + 48!
others are lower terms
this can be done by calculator only

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Asked In TCS Sumandeep Ghosh (14 years ago)

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(#M40000604) TCS QUESTION Keep an EYE

Given a collection of points P in the plane , a 1-set is a point in P that can be separated from the rest by a line, .i.e the point lies on one side of the line while the others lie on the other side. The number of 1-sets of P is denoted by n1(P). The minimum value of n1(P) over all configurations P of 5 points in the plane in general position (.i.e no three points in P lie on a line) is
a) 3
b) 5
c) 2
d) 8

Solution

The meaning of this question is little complicated. In easy language the question should be:


There are some points in the plane. We have to make a separation between these points by forming a line in such a way that one point could be separate from the others. No 3 points are in a line. Maximum no of methods for plotting the line and minimum no of methods for plotting the line will be (arrangement of points is your choice)

Now Answer Is:

For Maximize: The number of methods, Points should be drawn in the circumference of the CIRCLE So answer would be the number of total point in the plane.

For minimize: The number of methods we should draw 3 points in a TRIANGLE and all other point inside this triangle in such a way that no 3 points could be in a line.

If it will be allowed to draw the points in a line then minimum possibilities will be 2 only, because if we take all points in a line then you can separate only the corner points from the others.

For example
If we have 10 points then maximum possibilities = 10
and minimum = 3

similarly for 5 points
Max = 5, Min = 3

for 19
max= 19 Min = 3


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Asked In TCS Sumandeep Ghosh (14 years ago)

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