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Frequently Asked Interview Questions and Answers

(#M40009629) AIEEE QUESTION Keep an EYE

If a number is chosen at random from the set {1,2,3,.....,28,29,30}.What is the probability that
the number chosen is a product of exactly two different prime numbers?

Asked In AIEEE Devendra Marghade (13 years ago)

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(#M40003862) HCL QUESTION HCL puzzle Keep an EYE

E occurs which one cannot occurs
(a) A
(b) F
(c) D
(d) C
(e) J

Asked In HCL (13 years ago)

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(#M40154351) AMCAT QUESTION Operating system Keep an EYE

Friends,Please give the answer after studying process table and give detailed solution in comments.
Shortforms-
Process ->Pro
Burst Time in Milliseconds (ms)--> B

Process table with shortforms is as follows :

Pro B(in ms)
P1 8
P2 3
P3 5


There are 3 processes P1, P2 and P3, as shown which arrive at the same time and are processed by shortest Job-first (SJF) scheduling algorithm. Calculate the average waiting time in milliseconds.
1) 3.6
2) 5.6
3)6.3
4) 7.3

Asked In AMCAT dhritiman (9 years ago)

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(#M40165535) TCS QUESTION TCs Logical Keep an EYE

If n is a positive integer, let s(n) denote the integer obtained by
removing the last digit of n and placing it in front. For example, s(731) =
173. What is the smallest positive integer n ending in 6 satisfying s(n) =
4n? Please do not add white space around the answerIf n is a positive integer, let s(n) denote the integer obtained by
removing the last digit of n and placing it in front. For example, s(731) =
173. What is the smallest positive integer n ending in 6 satisfying s(n) =
4n? Please do not add white space around the answer

Asked In TCS Mehul KOTHARI (7 years ago)

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(#M40015249) MBA QUESTION time speed and distance, work, alligations & mixtures Keep an EYE

A man arrives at a railway station 1.5 before the time at which he had ordered his carriage to meet him. He walks at the rate of 4kmph and meets the carriage 8km from his house and reaches 1 hr earlier than usual time. what is the speed of the carriage and distance from the station to his house?

1) 8kmph, 12 km
2) 12kmph, 16 km
3) 4kmph, 12 km
4) none of these

Asked In MBA (12 years ago)

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(#M40037613) ACCENTURE QUESTION Keep an EYE

372, 823, 644, 582, 46?, 8?7. Then which digits will come at the place of (?)
A 6,7
B 5,9
C 6,2
D 5,3

Asked In Accenture Sundar Kumar (11 years ago)

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(#M40020755) EXAM QUESTION permutation Keep an EYE

a,b,c,d and e are five natural numbers. Find the number of ordered sets (a,b,c,d,e) possible such that a+b+c+d+e=64.

A.

64C5

B.

63C4

C.

65C4

D.

63C5

Asked In exam MAN (12 years ago)

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(#M40019397) OTHERS QUESTION Keep an EYE

Find the maximum value of n such that
570*60*30*90*100*500*700*343*720*81 is perfectly divisible by 30^n.

Asked In Others mohan lal garg (12 years ago)

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(#M40020373) SELF QUESTION Keep an EYE

ABCDEFGH is a regular octagon. A and E are opposite vertices of the octagon. A frogstarts jumping from vertex to vertex, beginning from A. From any vertex of the octagon except E, it may jump to either of the two adjacent vertices. When it reaches E, the frog stops and stays there. Let an be the number of distinct paths of exactly n jumps ending in E. Then, what is the value of a2n-1?

vikash singh (12 years ago)

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(#M40001790) TCS QUESTION latest placement puzzle Keep an EYE

A father and his son go out for a 'walk-and-run' every morning around a track formed by an equilateral triangle. The father's walking speed is 2 mph and his running speed is 5 mph. The son's walking and running speeds are twice that of his father. Both start together from one apex of the triangle, the son going clockwise and the father anti-clockwise. Initially the father runs and the son walks for a certain period of time. Thereafter, as soon as the father starts walking, the son starts running. Both complete the course in 45 minutes. For how long does the father run? Where do the two cross each other?

Solution

Let father runs t hours and walks (0.75-t) hours, then according to the given condition
5t+2(0.75-t)=x (for father)
10(0.75-t)+4t=x (for son)
on comparing these two we will get t=2/3 hrs=40 min
on taking t=2/3 hrs, x=3.5 miles
so father will run for 2/3 hrs = 40 min

now let the two will cross each other after time x then according to the given condition 5x+4x=3.5 so x = 7/18 hrs = 70/3 min in this much time father will run
5*7/18 = 35/18 miles and son will walk (7/2)-(35/18) = 28/18 = 14/9 miles

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Asked In TCS Aditi Sharma (14 years ago)

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