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(#M40009166) SELF QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

In the Battle of Hastings that occurred on October 14, 1066 Harold's forces formed 13 similar squares with exactly same number of soldiers in each square.

When Harold himself joined the fray and was added to the number of his soldiers in those thirteen squares a single huge square could be arranged. How many men there must have been in Harold's force?

Flower (13 years ago)
Unsolved
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(#M40009165) SELF QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

How it is that when I buy yellow bananas at three shillings a bunch and the same number of red ones at four shillings a bunch I would get two more bunches for the same amount if I divided the money evenly between the yellow and red bananas?

Flower (13 years ago)
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(#M40009164) SELF QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

Here is an odd little puzzle which occurred the other day at an archery meeting.

The young lady who carried off the first prize scored exactly one hundred points. Can you figure out how many arrows she must have used to accomplish the feat?

Flower (13 years ago)
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(#M40009161) SELF QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

The five school children in couples weigh 129 pounds, 125 pounds, 124 pounds, 123 pounds, 122 pounds, 121 pounds, 120 pound, 118 pounds, 116 pounds and 114 pounds on a weighing machine. What was the weight of each one of the five little girls if taken separately?

Flower (13 years ago)
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(#M40009158) SELF QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

What are the maximum number of grape vines that can be planted, not closer than nine feet apart, in a square plot containing one-sixteenth of an acre?

(Note: each side of this square plot would be 52 feet 2 inches)

Flower (13 years ago)
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(#M40009157) SELF QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

t appears that an ingenious or eccentric teacher being desirous of bringing together a number of older pupils into a class he was forming, offered to give a prize each day to the side of boys or girls whose combined ages would prove to be the greatest.

Well, on the first day there was only one boy and one girl in attendance, and, as the boy's age was just twice that of the girl's, the first day's prize went to the boy.

The next day the girl brought her sister to school, and it was found that their combined ages were just twice that of the boy, so the two girls divided the prize.

When school opened the next day, however, the boy had recruited one of his brothers, and it was found that the combined ages of the two boys were exactly twice as much as the ages of the two girls, so the boys carried off the honors of that day and divided the prizes between them.

The battle waxed warm and on the fourth day the two girls appeared accompanied by their elder sister; so it was then the combined ages of the three girls against the two boys, and the girls won off course, once more bringing their ages up to just twice that of the boys'. The struggle went on until the class was filled up, but as our problem does not need to go further than this point, to tell the age of that first boy, provided that the last young lady joined the class on her twenty-first birthday. Now, guess the first boy's age.

Flower (13 years ago)
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(#M40009155) SELF QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

Here is a puzzle known as the Covent Garden Problem, which appeared in London half a century ago, accompanied by the somewhat surprising assertion that it had mystified the best mathematicians of England:

Mrs. Smith and Mrs. Jones had equal number of apples but Mrs. Jones had larger fruits and was selling hers at the rate of two for a penny, while Mrs. Smith sold three of hers for a penny.

Mrs. Smith was for some reason called away and asked Mrs. Jones to dispose of her stock. Upon accepting the responsibility of disposing her friend's stock, Mrs. Jones mixed them together and sold them of at the rate of five apples for two pence.

When Mrs. Smith returned the next day the apples had all been disposed of, but when they came to divide the proceeds they found that they were just seven pence short, and it is this shortage in the apple or financial market which has disturbed the mathematical equilibrium for such a long period.

Supposing that they divided the money equally, each taking one-half, the problem is to tell just how much money Mrs. Jones lost by the unfortunate partnership?

Flower (13 years ago)
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(#M40009153) SELF QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

On your travels you come to an old man on the side of the road holding three cards from a standard deck face down. Trying to make conversation you ask him what the three cards are.

He tells you, "To the left of the queen, are one or two jacks. To the right of the jack, are one or two jacks. To the right of the club, are one or two diamonds. To the left of the diamond, are one or two diamonds." What are the three cards?

Flower (13 years ago)
Unsolved Read Solution (1)
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(#M40009151) SELF QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

A man has four cards in his hand facing him, from 2 to 5. He wants them placed in ascending order from his left to his right. To do this, he takes the leftmost card (from your perspective) and puts it last. He then takes the third card from the right (your right) and puts it in last place.

What was the previous order of the cards?

Flower (13 years ago)
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(#M40009148) SELF QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

Three people enter a room and have a green or blue hat placed on their head. They cannot see their own hat, but can see the other hats.

The color of each hat is purely random. They could all be green, or blue, or any combination of green and blue.

They need to guess their own hat color by writing it on a piece of paper, or they can write "pass".

They cannot communicate with each other in any way once the game starts. But they can have a strategy meeting before the game.

If at least one of them guesses correctly they win $50,000 each, but if anyone guess incorrectly they all get nothing.

What is the best strategy?

Flower (13 years ago)
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