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(#M40003213) TCS QUESTION maths Keep an EYE Keep an eye puzzle Keep an eye puzzle

A father and his son go out for a 'walk-and-run' every morning around a track formed by an equilateral triangle. The father's walking speed is 2 mph and his running speed is 5 mph. The son's walking and running speeds are twice that of his father. Both start together from one apex of the triangle, the son going clockwise and the father anti-clockwise. Initially the father runs and the son walks for a certain period of time. Thereafter, as soon as the father starts walking, the son starts running. Both complete the course in 45 minutes. For how long does the father run? Where do the two cross each other?

Solution
Let father runs t hours and walks (0.75-t) hours, then according to the given condition
5t+2(0.75-t)=x (for father)
10(0.75-t)+4t=x (for son)
on comparing these two we will get t=2/3 hrs=40 min
on taking t=2/3 hrs, x=3.5 miles
so father will run for 2/3 hrs = 40 min

now let the two will cross each other after time x then according to the given condition 5x+4x=3.5 so x = 7/18 hrs = 70/3 min in this much time father will run
5*7/18 = 35/18 miles and son will walk (7/2)-(35/18) = 28/18 = 14/9 miles

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Asked In TCS Deependra Chauhan (14 years ago)
Solved
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(#M40003212) TCS QUESTION math Keep an EYE Keep an eye puzzle Keep an eye puzzle

Doller stores, the stores which sell all of their merchandise for $1, have long had a reputation for being down at the heels places to buy cheap, generic goods. While keeping their low prices, they are revamping their image and climbing the respectability ladder, in some cases to the fortune 500. One such dollar store which recently made an entry in the fortune list which has 2500 stores all over the United States said that they had a 2 percent increase in the number of transaction in 2008 compared with the previous year to 37 million. The company made a profit of $20 million this year. What is the average profit per store?

Solution
Per store profit = 20/2500 million $ = 2/250 million $ = 0.008*1000000 $ = 8000 $

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Asked In TCS kalpesh jain (14 years ago)
Solved
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(#M40003208) TCS QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

Suppose n is an integer, such that the sum of the digits of n is 2, and 10^10 < n < 10^11 . The number of different values for n is:

Solution
10000000001
10000000010
10000000100
10000001000
10000010000
10000100000
10001000000
10010000000
10100000000
11000000000
20000000000

so the ans is 11
This answer is given by RAJNI CHAUHAN and is correct answer

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Asked In TCS Jaijayendra Kumar (14 years ago)
Solved
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(#M40003206) TCS QUESTION maths Keep an EYE Keep an eye puzzle Keep an eye puzzle

A father and his son go out for a 'walk-and-run' every morning around a track formed by an equilateral triangle. The father's walking speed is 2 mph and his running speed is 5 mph. The son's walking and running speeds are twice that of his father. Both start together from one apex of the triangle, the son going clockwise and the father anti-clockwise. Initially the father runs and the son walks for a certain period of time. Thereafter, as soon as the father starts walking, the son starts running. Both complete the course in 45 minutes. For how long does the father run? Where do the two cross each other?

Solution
Let father runs t hours and walks (0.75-t) hours, then according to the given condition
5t+2(0.75-t)=x (for father)
10(0.75-t)+4t=x (for son)
on comparing these two we will get t=2/3 hrs=40 min
on taking t=2/3 hrs, x=3.5 miles
so father will run for 2/3 hrs = 40 min

now let the two will cross each other after time x then according to the given condition 5x+4x=3.5 so x = 7/18 hrs = 70/3 min in this much time father will run
5*7/18 = 35/18 miles and son will walk (7/2)-(35/18) = 28/18 = 14/9 miles


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Asked In TCS Deependra Chauhan (14 years ago)
Solved Read Solution (2)
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(#M40003199) INFOSYS QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

Y=min(3x+5,10-2x)
what is the maximum value of Y?

Asked In Infosys arjun (14 years ago)
Solved Dr.Dipin Singh Read Solution (4)
Is this Puzzle helpful?   (5)   (0) Submit Your Solution Algebra

(#M40003198) TCS QUESTION maths Keep an EYE Keep an eye puzzle Keep an eye puzzle

19 people(a1,a2......a19)are invited to a party. The host and the
hostess shake hands with each invitee and also with each other. The
invitee shake hands in a circular fashion, i.e. the
pairs(a1,a1),(a2,a3).........(a18,a19),(a19,a1)shake hands. So in all
three are 58 handshakes. Let S be a set of people such that every
pair in S shake hands. The size of S is at most

Asked In TCS Deependra Chauhan (14 years ago)
Solved Krishanu Das Read Solution (3)
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(#M40003197) TCS QUESTION persentages Keep an EYE Keep an eye puzzle Keep an eye puzzle

The % obtained by a student is 74. If we take % on the basis of 4 subjects (leaving the marks of fifth subject) then % is 76. How many marks, he got in the fifth subject.

Asked In TCS yugandharkancham (14 years ago)
Solved niroopa pothuraju Read Solution (2)
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(#M40003196) TCS QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

There exists a relation n/p = 195, where n=number of steps in meters and p = pace length. There is a man Shivam who knows his pace length =185cm, then what will be the speed of Shivam in kmph? EXPLAIN PLZ....!!!!

Asked In TCS Sneha Singh (14 years ago)
Solved Dr.Dipin Singh Read Solution (6)
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(#M40003194) TCS QUESTION maths Keep an EYE Keep an eye puzzle Keep an eye puzzle

There are 16 different stations between A and B.how many different railway tickets have to be printed in each station except platform tickets?

Solution
Total no. of tickets for each station for journey from that station to other stations= 15
Total no of tickets will be 16*15=240
This answer is given by Dipin and is right answer.
But if A and B are also stations other than 16 middle stations then
There are total 18 stations with A and B
so Total no. of tickets = 18*17 = 306
here 18 for total stations and 17 for ticket available at particular station.
This answer is given by PRAVIN and is coorrect answer.


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Asked In TCS (14 years ago)
Solved Read Solution (3)
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(#M40003193) TCS QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

3 years ago Jacob's age was twice John's age. 3 years hence Jacob's age will be 4/3 times the age of John's. Find Jacob's present age in binary numbers.

Asked In TCS suraj kumar (14 years ago)
Solved Dr.Dipin Singh Read Solution (2)
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