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(#M40002986) TCS QUESTION Keep an EYE

20. In 1911 a French Physicist Paul devised a thought experiment based on Einstien’s Special Relativity. In the experiment, a person makes a journey into space at nearly speed of light and comes back to earth. He finds that he has aged five times less than his twin who stays back on earth for 40 years. This is popularly known as the twins paradox. Now consider the case of Hansel and Gretel, who are not twins five years ago. Hansel was twice as old as was Gretel. If they journey in to space, and automatic clock assists in logging the start time of their journey accurately. If the do not journey in to space, 5 years hence Hansel age will be 4/3 times the age of Gretel. Find Hansel’s age today in binary numbers.

Solution

(h-5)=2(g-5)....1
(h+5)3=(g+5)4....2
nw solve it h=15 n g 10
so binary of 15 =1111
This answer is given by VIKAS SINGH and is correct answer


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Asked In TCS Paras Jain (14 years ago)

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(#M40002985) TCS QUESTION Keep an EYE

Metal strip of width „x‟ cm. 2 metal strips are placed one over the other, then the combine length of 2 strips is „y‟. If „z‟ strips are placed in that manner. What is the final width of that arrangement?

Solution

i think three uncleared fonts are x, y, z. and on this basis answer will be x*z. y is only for confusion

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Asked In TCS Himanshu Pandey (14 years ago)

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(#M40002984) SELF QUESTION Party Time Keep an EYE

At the Party:
1. There were 9 men and children.
2. There were 2 more women than children.
3. The number of different man-woman couples possible was 24. Note that if
there were 7 men and 5 women, then there would have been 35 manwoman
couples possible.
Also, of the three groups - men, women and children - at the party:
4. There were 4 of one group.
5. There were 6 of one group.
6. There were 8 of one group.
Exactly one of the above 6 statements is false.
Can you tell which one is false? Also, how many men, women and children are
there at the party?

(14 years ago)

Solved Dr.Dipin Singh Read Solution (1)

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(#M40002983) TCS QUESTION Keep an EYE

45 people (a1, a2…….a45) meet and shake hands in a circular fashion. In other words there totally 45 handshakes involving the pairs (a1, a2), (a2, a3)……(a44, a45), (a45, a1). Then the size of the smallest set of people such that the rest have shaken hands with atleast one person in the set is.

Asked In TCS Paras Jain (14 years ago)

Solved suganya Read Solution (2)

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(#M40002981) TCS QUESTION Keep an EYE

. A greengrocer was selling melon at a penny each, plums at 2 for a penny and pears at 3 for a penny. A father spent 7p and got the same amount of each type of fruit for each of three children Jane, Joe and Jill. Jane is three years older than Jill and Joe is exactly half the age of Jane and Jill together. What did each child get?

Asked In TCS Paras Jain (14 years ago)

Solved mukul Read Solution (3)

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(#M40002980) TCS QUESTION maths Keep an EYE

There are certain number of hats and gloves in a box. They are of 41 red, 23 green, 11 orange. Power gone. But a woman can differentiate between hats and gloves.How many draws are required to obtain a pair of each color.

Asked In TCS (14 years ago)

Solved Zoya Read Solution (1)

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(#M40002978) TCS QUESTION Keep an EYE

rope of given length is used to form a triangle of sides 19,15 and 23 cms. If the same rope is used to form a square, what would be the area of such a square?

Asked In TCS Paras Jain (14 years ago)

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(#M40002970) TCS QUESTION Keep an EYE

The age of two friends is in the ratio 5:6,after how many years will the ages be in the ratio 7:8?

Solution

after 2 year
on adding 2 in 5 and 6 we will get 7 and 8

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Asked In TCS Swarup Bal (14 years ago)

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(#M40002968) TCS QUESTION Keep an EYE

4 years ago ,Athena's age was twice Helen's age.4 years hence,Athena's age will be 4/3 times the age of Helen.Find Athena's present age in binary numbers during the time that the statement holds true.
a)100
b)1001
c)101
d)1100

Asked In TCS Payel (14 years ago)

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(#M40002967) TCS QUESTION math Keep an EYE

A toy can produce 10diiff sounds. Nw toy is defective to produce 2 sounds in 3min. find probability that it produces 6 consecutive is 1 in(_)

Solution

since there are two sounds so we can select the sound in 2 manners.
and probability to get 6 same sounds consecutively probability = (1/2)^6
so answer = 2*(1/2)^6 = 1/32

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Asked In TCS Deependra Chauhan (14 years ago)

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