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(#M40151487) CMC QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

A printer started its work at 8.15 a.m and ended its work at 9.20 p.m. It was interrupted twice
for the time duration of 42 min. It can print 100 instructions per hour. Approximate how many
instructions it can print?

Asked In CMC anshika (10 years ago)
Unsolved Read Solution (2)
Is this Puzzle helpful?   (4)   (2) Submit Your Solution undefined

(#M40009001) SELF QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

QAR, RAS, SAT, TAU, _____

A.UAV B.UAT
C.TAS D.TAT

(13 years ago)
Unsolved Read Solution (3)
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(#M40156548) L&T QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

.The bases of a hemisphere and a cone are equal. If their heights are also equal then ratio between their curved surface area is—
(a) 1 : √2
(b) √2 ∶1
(c) 1 : 2
(d) 2 : 1
(e) None of these

Asked In L&T ABHINAV PUSHPAM (9 years ago)
Unsolved Read Solution (5)
Is this Puzzle helpful?   (4)   (4) Submit Your Solution Area and Volume

(#M40154253) AMCAT QUESTION Computer science Keep an EYE Keep an eye puzzle Keep an eye puzzle


Which of the following statements is/are true about the Resource-allocation graph?
1. lf the graph contains no cycles, then no process in the system is deadlocked.
2. lf the graph contains a cycle, then a deadlock may exist.
3. lf each resource type has exactly one instance, then a cycle implies that there is not a deadlock.
4. lf each resource type Which has several instances, then a cycle necessarily implies that a deadlock has occurred.
Options are:-
1) Only 1
2) Both 1 and 2
3) Both 2 and 3
4) Both 1 and 3
5)Only 4

Asked In AMCAT dhritiman (10 years ago)
Unsolved Read Solution (2)
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(#M40105033) OTHER QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

Deepak has a chain which he divides into 5 pieces of equal lengths containing 3 links each. He then takes it to a blacksmith to join all the pieces. How many links should be opened to make it one?
A.7
B.5
C.8
D.9

Asked In other Kalyani Reddy (10 years ago)
Unsolved Read Solution (1)
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(#M40041219) CSC QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

if x = 4 + 4 - 4 + 4 - ......¥ find the value of x

Asked In CSC Ankita Singh (11 years ago)
Unsolved Read Solution (5)
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(#M40157156) OTHERS QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

Raj tossed 3 dices and their results are noted down then what is the probability that Raj gets 10?

Asked In others jigar (9 years ago)
Unsolved
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(#M40017673) OTHERS QUESTION maths Keep an EYE Keep an eye puzzle Keep an eye puzzle

prove (100-100)/(100-100)=1/2

Asked In Others Meghna Jain (12 years ago)
Unsolved Read Solution (1)
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(#M40031445) INFOSYS QUESTION infosys Keep an EYE Keep an eye puzzle Keep an eye puzzle

Q. Venkat has 1boy & 2daughters. The product of these children age is 72.The sum of their ages give the door numberof Venkat.Boy is elder of three.Can you tell the ages of all the three.

Asked In Infosys BISWAJIT (11 years ago)
Unsolved Read Solution (2)
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(#M40001841) INFOSYS QUESTION infosys question Keep an EYE Keep an eye puzzle Keep an eye puzzle

The minute hand of a clock overtakes the hour hand at intervals of 65 minutes of correct time. How much does the clock gain or lose in 12 hours?

Solution
After 60 minute rotation the minute hand will make an angle of 30 degree with hour hand.After that let the time required to make an overtake is t minute
in this time angle covered by minute hand = (360/60)t = 6t
similarly angle covered by hour hand = (30/60)t = t/2
so for overtake 6t = 30 + t/2 or t = 60/11 min = 5 min and 5/11 min = 5 min and 300/11 sec = 5 min and 27.273 sec so clock loses 27.273 seconds

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Asked In Infosys Aditi Sharma (14 years ago)
Solved Read Solution (2)
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(#M40155234) C QUESTION pointer Keep an EYE Keep an eye puzzle Keep an eye puzzle

ARRAY-SHEET
Q1. main()
{
int n=10;
int a[n];
printf("n %d bytes",sizeof(a));
}
(a) compilation error (b) garbage values (c) 20 bytes (d) 10 bytes

Q2. main()
{
int a[]={1,2,3}, i, sum=0, *p, *q;
q=p=a;
for(i=0;i<3;i++)
{
++*p++;
printf(" %d", q[i]);
}
}
(a) 1 2 3 (b) 2 3 4 (c) all garbage values (d) no output

Q3. main()
{
int a[25];
a[0]=46;
a[24]=50;
printf("%d %d",a[24]-a[0],&a[24]-&a[0]);
}
(a) compilation error (b) 24 24 (c) 46 50 (d) 4 24

Q4. main()
{
int a[2]={10,20}, *p, i=1;
p=&a+1;
p--;
for(;i>=0;)
{
printf("%d ", *p--);
i--;
}
}
(a) 20 10 (b) 10 20 (c) 11 21 (d) 21 11

Q5. main()
{ static int a[]={2,4,6};
static int *p[]={a,a+1,a+2};
int *q[]={a+2,a+1,a} , *ptr, i;
for(i=0;i<3;i++)
a[i]=**p+**q;
for(i=0;i<3;i++)
printf("%d ",a[i]); }
(a) 4 8 12 (b) 12 12 12 (c) 8 14 14 (d) 2 4 6

Q6. main()
{ static int a[]={2,4,6};
static int *p[]={a,a+1,a+2};
int *q[]={a+2,a+1,a}, *ptr, i; ;
for(i=0;i<3;i++)
a[i]=*p[i]+*q[i];
for(i=0;i<3;i++)
printf("%d ",a[i]); }
(a) 4 8 12 (b) 12 12 12 (c) 12 22 22 (d) 8 8 14

Q7. Suppose the array a starts with the base address 170 andarray p starts with the base address 180
main()
{ static int a[]={10,12,14,16,18};
static int *p[]={a,a+1,a+2,a+3,a+4} , **ptr, *s;
ptr=p+0;
s=a+0;
printf("n %u %u %d %d ",s,ptr,*s,**ptr);
ptr++; s++;
printf("n %u %u %d %d ",s,ptr,*s,**ptr);
*ptr++; *++s;
printf("n %u %u %d %d ",s,ptr,*s,**ptr);
++*ptr; ++*s;
printf("n %u %u %d %d ",s,ptr,*s,**ptr);
*ptr++; *s++;
printf("n %u %u %d %d ",s,ptr,*s,**ptr); }

Q8. main() {
int a[5]={10,20,30,40,50},*p;
int i;
p=a;
for(i=0;i<3;i++)
printf(" %.4d ",++p[i]); }
(a) 10 20 30 (b) 0010 0020 0030 (c) 0011 0021 0031 (d) all garbage

Q9. main()
{ int a[][2][3]={ { {1,2,3}, { 4, 5, 6} },
{ {7,8,9}, {10,11,12} }
};
printf("%u ",***a+1+1+2);
printf("%u ", ***(a+1)+1+2);
printf("%u ",**(*(a+1)+1)+2);
printf("%u ",*(*(*(a+1)+1)+2)); }
(a) error (b) 1 12 12 12 (c) 1 10 11 12 (d) 5 10 12 12

Q10. main()
{ int a[]={10,20,30};
int *p[3]={a}, i;
for(i=0;i<3;i++)
printf("%u ",p[i]);
} suppose the base address of array a is 170
(a) 170 172 174 (b) 170 0 0 (c) 170 and garbage addresses (d) no output

Q11. main()
{ float x[3][3][3]={1.5,2.5};
printf("%.2f %.2f",x[0][0][0],x[2][2][2]); }
(a) 1.50 garbage value (b) 1.50 2.50 (c) 0.00 0.00 (d) 1.50 0.00 ( e) none of these

Q12. main()
{ int a[5]={10,20,30,40,50}, *p;
p=a+4;
p[-2]=50;
printf("n%u %d",p[-2],a[2]); }
(a) 30 50 (b) error (c) 30 30 (d) 50 30 (e) none of these

Q13. main()
{ int a[3]={10,20,30},*p;
for(p=a;p<&a[3];p++)
{ *p=p-a;
printf("%d ",*p); }
}
(a) 10 20 30 (b) garbage values (c) 1 2 3 (d) 0 1 2 (e) none of these

Q14. main()
{
int a[3][3];
printf("%u ",&a+0);
printf("%u ",&a+1);
}
if the base address is 65506
(a) 65506 65508 (b) 65506 65518 (c) 65506 65526 (d) 65606 65524

Q15. main()
{
int a[]={10,20,30} , (*p)[3]=a , i;
for(i=0;i<3;i++)
printf("%d ",(*p)[i]);
}
(a) 10 20 30 (b) 10 0 0 (c) 10 10 10 (d) 10 and all garbage values

Q16. What will be the value of a[i] will be printed out in this program?.
main() {
int a[3] , i;
for(i=0;i<3;i++)
{
a[i]=printf("abcde"+i);
printf("%d",a[i]);
} }
(a) 97 98 99 (b) 1 2 3 (c) 5 4 3 (d) all garbage values

Q17. main()
{ int a[]={10,20,30}, i,*p,j=0;
for(i=0;i<3;i++)
{
p=&a[i];
++*p++;
++a[j++];
printf("%d ",a[i]);
}
}
(a) 10 20 30 (b) 11 21 31 (C) 12 22 32 (d) 13 23 33

Q18. main()
{ int a[]={10,11,12}, I;
for(I=0;I<3;I++)
++*a;
for(I=0;I<3;I++)
printf(“%d”,a[I]);
}
(a) error (b) 10 11 12 (c) 11 12 13 (d) 12 13 15 (e) 13 11 12

Q19. main()
{ int a[][3]={1,2,3,4,5,6};
int (*p)[]={a};
printf(“%d %d”,(*p)[1],(*p)[2]);
*p++;
printf(“%d %d”,(*p)[1],(*p)[2]); }
(a) 2 3 5 6 (b) 2 3 4 5 (c) 4 5 0 0 (d) compilation error

Q20 main()
{ char a[ ]="Jyotir";
char b[ ]="Janmay";
char c[10];
c=a;
a=b;
b=c;
printf("%s %s",a,b); }
(a) Jyotir Janmay (b) Janmay Jyotir (c) Jyotir Jyotir (e) error

Q21 main()
{ char *a="Jyotir";
char *b="Janmay";
char *c;
c=a;
a=b;
b=c; printf("n %s %s ",a,b); }
(a) Jyotir Janmay (b) Janmay Jyotir (c) Jyotir Jyotir (d) Janmay Janmay

Q22 main()
{
int *p=&"Janmayjay";
printf("%s",p);
}
(a) Compiolation Error (b) garbage (c) J (d) Janmayjay (e) none of these

Q23 main()
{ char a[10][10];
char *b[10];
char (*c)[10];
printf("n %d %d %d",sizeof(a),sizeof(b),sizeof(c));
}
(a) 100 10 10 (b) 200 20 20 (c) 100 20 2 (d) none of these

Q24. main()
{
char *a[2]={"Jyotir" , "Janmay"};
printf("n%s",*a+1);
printf("n%s",*(a+1));
}
(a) Jyotir Janmay (b) Janmay Janmay (c) yotir Janmay (d) none of thsee

Q25. main()
{ static char *a[]={"Sanjay Sapra", "Janmayjay Sapra", "Jyotirmay Sapra"};
printf("%s",*(a+2)-16); }
(a) Jyotirmay Sapra (b) Sanjay Sapra (c) Janmayjay Sapra (d) none of these

Q26. main()
{ char a[]="AABBCC";
int i;
for(i=0;i<3;i++)
printf("%d",(int)a[i]);
}
(a) compilation error (b) 65 65 66 (c) 65 65 66 66 67 67 (d) 65 66 67

Q27. main()
{ char a[0];
printf("%d",sizeof(a));
}
(a) compilation error (b) 1 (c) 2 (d) 0

Q28. main()
{
char s[ ]={'a','b','c','n','c',''};
char *p,*str,*str1;
p=&s[3];
str=p;
str1=s;
printf("%d",++*p + ++*str1-32);
}

Q29. What will be the output of this program if I store 3 strings
at time of scanf( ). “Sanjay” “Jyotirmay” “Janmayjay”
main( )
{ char *q;
int j;
for (j=0; j<3; j++) scanf(“%s” ,(q+j));
for (j=0; j<3; j++) printf(“%c” ,*(q+j));
for (j=0; j<3; j++) printf(“%s” ,(q+j));
}
(a) S J J Sanjay Jyotirmay Janmayjay (b) S J J
(c) S J J Sanjay anjay njay (d) S J J SJJanmayjay JJanmayjay Janmayjay

Q30 main()
{
char *p;
p="%dn";
p++;
p++;
printf(p-2,300);
}

Q31. main()
{
char *p = “Iyqm”;
char c;
c = ++*p++;
printf(“%c”,c);
printf(“%s”,p);
}

Q32.
void main()
{ printf(“sizeof (void *) = %d n“, sizeof( void *));
printf(“sizeof (int *) = %d n”, sizeof(int *));
printf(“sizeof (double *) = %d n”, sizeof(double *));
printf(“sizeof(struct unknown *) = %d n”, sizeof(struct unknown*));
}

Q33. main()
{ char a[ ]={10,20,30,40,50,60,70,80};
char *ptr;
ptr=&(a+2)[5];
printf(“%d”,*ptr);
}

Q34.
main()
{
char *str;
str=(char*) malloc(12);
strcpy(str,”Jyotirmay”);
printf(“%s”,str);
str=(char*) realloc(str,22);
strcat(str,”Janmayjay”);
printf(“%s”,str);
}

Q35. main( )
{ static char *arr[ ]={ “sanjay”, “balou” , ”Janmay” , ”Jyotir” };
static char **ptr[ ]={ arr+3, arr+2, arr+1, arr};
char ***p=ptr;
**p++;
printf(“%s”,**p);
printf(“%s”,*--*++p);
printf(“%s”,*p[-2]+3);
printf(“%s”,p[-1][-1]+1);
}

Q36. What will be output if you will compile and execute the following c code?
void main()
{ int i=320;
char *ptr=(char *)&i;
printf("%d",*ptr);
}
(a) 320 (b) 1 (c) 64 (d) Compilation error

Q37. What will be output if you will compile and execute the following c code?
void main()
{ int array[]={10,20,30,40};
printf("%d",-2[array]);
}
(a) 60 (b) -30 (c) 60 (d) Garbage value (e) Compilation error

Q38. int main()
{ char str[] = "Programming";
printf("%s ",&str[2]);
printf("%s ",str);
printf("%s ",&str);
}

Q39. What will be output if you will compile and execute the following c code?
void main()
{ int i;
float a=5.2;
char *ptr;
ptr=(char *)&a;
for(i=0;i<=3;i++)
printf("%d ",*ptr++);
}
(a)0 0 0 0 (b)Garbage Garbage Garbage Garbage (c)102 56 -80 32 (d**)102 102 -90 64

Q40. What will be output if you will compile and execute the following c code?
void main()
{
printf("%s","c" "question" "bank");
}
(a) c question bank (b) c (c) bank (**d) cquestionbank (e) Compiler error

Q41. What will be the output of the following program
main( )
{ char a[ ]=”hello”, b[ ]=”hello”;
if(a==b)
printf(“String matched “);
else
printf(“String not matched”);
}

Q42. main( )
{
printf(“%c”, “abcde”[2]);
printf)”%c”,”abcde”+1)[2]);
}

Q43. main( )
{ printf(“%s”, &“abcde”[2]);
printf(”%s”,&”abcde”+1)[2]);
}

Q44. main()
{
static int a[3]={10,20,30},**c,****d;
int *b[]={a,a+1,a+2,a+3,a+4};
c=b;
d=&c;
++*++*c;
printf("%d %d %d",a[0],a[1],a[2]);
}

Q45 main()
{
static int a[3]={10,20,30},***d;
static int *b[]={a,a+1,a+2};
static int **c[]={b,b+1,b+2};
d=c;
++*++*++*d;
printf("%d %d %d",a[0],a[1],a[2]);
}

Q46. main( )
{
if(strcmp(&“abc”,&”abc”))
printf(“matched”);
else
printf(“not matched”);
}
(a) matched (b) not matched (c) no output (d) compilation error

Q47. main( )
{
if(strncmpi(“ramesh”,”RAMNARESH”,3))
printf(“matched”);
else
printf(“not matched”);
}
(a) matched (b) not matched (c) no output (d) compilation error

Q48. What will the output?
main( )
{
int array[ ] = {1, 2, 3, 5, 8, 13, 21, 34, 55};
int sum = 0,i;
for (i = 0; i < 4; i++)
sum += array[array[i]];
printf(“%d”,sum);
}

Q49. What will the output?
main()
{
char *p = NULL;
char *q = 0;
if (p)
printf(" p ");
else
printf("nullp");
if (q)
printf("qn");
else
printf(" nullqn");
}

Q50. int main()
{
int ary[4] = {1, 2, 3, 4};
int *p = ary + 3;
printf("%d %dn", p[-2], ary[*p]);
}

Q51. void main()
{
char a[10][5] = {"hi", "hello", "fellows"};
printf("%d", sizeof(a[1]));
}

Q52. What will be output of following program?
int main(){
char *ptr1 = NULL;
char *ptr2 = 0;
strcpy(ptr1," c");
strcpy(ptr2,"questions");
printf("n%s %s",ptr1,ptr2);
return 0;
}
(a) c question (b) c (null) (c) (null) (null) (d) Compilation error (e) none of these

Q53.
What will be output of following program?
int main(){
int a = 10;
void *p = &a;
int *ptr = p;
printf("%u",*ptr);
return 0;
}
(a) 10 (b) address (c) 2 (d) Compilation error

Q54. What will be output of following program?
int main( )
{
int a,b,c,d;
char *p = ( char *)0;
int *q = ( int *q)0;
float *r = ( float *)0;
double *s = 0;
a = (int)(p+1);
b = (int)(q+1);
c = (int)(r+1);
d = (int)(s+1);
printf("%d %d %d %d",a,b,c,d);
return 0;
}
(a) 2 2 2 2 (b) 1 2 4 8 (c) 1 2 2 4 (d) compilation error

Q55.What will be output of following program?
int main()
{
int a = 5,b = 10,c;
int *p = &a,*q = &b;
c = p - q;
printf("%d" , c);
return 0;
}
(a) 1 (b) 5 (c) -5 (d) Error (e) None of these

Q56. What will be output if you will compile and execute the following c code?
int main()
{
int a[2][4]={3,6,9,12,15,18,21,24};
printf("%d %d %d",*(a[1]+2),*(*(a+1)+2),2[1[a]]);
return 0;
}
(a) 15 18 21 (b) 21 21 21 (c) 24 24 24 (d) Error (e) None of these

Q57. What will be output if you will compile and execute the following c code?
int main()
{
char arr[]="C Question Bank";
char *p;
p+=3;
p=arr;
p+=3;
*p=100;
printf("%s",arr);
return 0;
}
(a) C question Bank (b) C quesdion Bank (c) C qdestion Bank (d) C q100estion Bank

Q58. What will be output the following c code?
int main()
{
int i;
char *arr[4] = {"C","C++","Java","VBA"};
char *(*ptr)[4] = &arr;
for(i=0;i<4;i++)
printf("Address of String %d : %un",i+1,(*ptr)[i]);
return 0;
}

Q59. What will be output the following c code?
int main()
{
int i;
char *arr[4] = {"C","C++","Java","VBA"};
char *(*ptr)[4] = &arr;
for(i=0;i<4;i++)
printf("String %d : %sn",i+1,(*ptr)[i]);
return 0;
}

Q60. What will be output the following c code?
int main()
{
int i;
char *arr[4] = {"C","C++","Java","VBA"};
char *(*ptr)[4] = &arr;
printf("%s",++(*ptr)[2]);
return 0;
}

Asked In C Anshul jain (9 years ago)
Unsolved Read Solution (4)
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(#M40031148) INFOSYS QUESTION number of bought Keep an EYE Keep an eye puzzle Keep an eye puzzle

Q. A lady goes for shopping.she bought some shoestrings.4 times the number of shoestring,she bought pins and 8 times,handkerchiefs.she paid each item with their count as each piece's cost. she totally spent Rs.3.24. How many handkerchiefs did she buy?

Asked In Infosys praveen (11 years ago)
Unsolved Read Solution (5)
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(#M40118230) REVENUE OFFICER QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

mmmmmmmmmmmmmmmmmmmmnnnnnnnnn/mmmmmmmmmmm=

Asked In REVENUE OFFICER ravi (10 years ago)
Unsolved
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(#M40154735) RSA QUESTION Profit and loss Keep an EYE Keep an eye puzzle Keep an eye puzzle

The cp of 21 articles is equal to sp of 18 articles.find gain or loss %

Asked In Rsa RAKESH KUMAR (9 years ago)
Unsolved Read Solution (1)
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(#M40005197) GENPACT QUESTION Problem on trains Keep an EYE Keep an eye puzzle Keep an eye puzzle

A goods train runs at a speed of 72 kmph and crosses a 250 m long platform in 26 seconds.What is the length of the goods train?
a)230 m b)240 m c)260 m d)270 m

Asked In GENPACT (13 years ago)
Unsolved Read Solution (1)
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(#M40157989) ANDROID QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

What is the difference between service and a thread?

Options
1) Service - is a component of android, which runs in the background with out any UI. Service will have default one thread to run in background. Thread - is similar to service, it also runs in the background.
2) Service - is a component of android, which runs in the background with out any UI. By default service will run in Main thread only. Thread - is not android component, but still one can use thread to do some background task. Using thread in place of service is discouraged.
3) Option 2 is right, but one can use Thread in place of Service, no problem will come.
4) Option 1 is right, but it may have UI also some times.

Asked In Android Ashish (8 years ago)
Unsolved Read Solution (1)
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(#M40019615) OTHERS QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

2,6,12,20,32,_
a) 42 b) 46 c)52 d)48

Asked In Others mohan lal garg (12 years ago)
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(#M40051100) EXAM QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

Substitute the given values into the formula, and solve for the unknown variable.

A=bh; A=60, h=12

Asked In exam (10 years ago)
Unsolved Read Solution (1)
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(#M40038484) GATE QUESTION Time and Work Keep an EYE Keep an eye puzzle Keep an eye puzzle

There is a leak in the bottom of a cistern. Before the leak it could be filled in 9/2h. It now takes 1/2h longer. If the cistern is full, in how much time would the leakage empty the full cistern?
(a) 45h
(b) 40h
(C) 36h
(d) 56h

Asked In Gate Swechchha Agarwal (11 years ago)
Unsolved Read Solution (2)
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(#M40153379) SYNTEL QUESTION Keep an EYE Keep an eye puzzle Keep an eye puzzle

One pipe fills in 4 hrs and another in 5hrs when they both work alternately
how much time will be taken to fill the tank.

Asked In Syntel shete swapnil (10 years ago)
Unsolved Read Solution (2)
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