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(#M40001640) TCS QUESTION puzzle 2010 Keep an EYE

3, 22 , 7, 45, 15, ? , 31
(a) 45 (b) 90 (c) 91 (d) 35

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(#M40001639) TCS QUESTION puzzle 2010 Keep an EYE

6 persons standing in queue with different age group, after two years their average age will be 43 and seventh person joined with them. hence the current average age has become 45. find the age of seventh person?
(a) 69 (b) 70 (c) 40 (d) 45

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(#M40001638) TCS QUESTION puzzle 2010 Keep an EYE

In Tnagar many buildings were under residential category.for buildings they number as 1 to 100. For shops, corporation numbered between 150 and 200 only prime numbers. how many time 6 will appear in building numbering?
(a) 10 (b) 20 (c) 8 (d) 19

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(#M40001636) TCS QUESTION puzzle 2010 Keep an EYE

A train starts full of passengers. At the first station, it drops one-third of the passengers and takes 280 more. At the second station, it drops one-half of the new total and takes 12 more. On arriving at the third station, it is found to have 248 passengers. Find the number of passengers in the beginning.
(a) 240 (b) 248 (c) 280 (d) 288

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(#M40001634) TCS QUESTION puzzle 2010 Keep an EYE

Two unemployed young men decided to start a business together. They pooled in their savings, which came to Rs. 2,000. They were both lucky, their business prospered and they were able to increase their capital by 50 per cent every three years. How much did they have in all at the end of eighteen years?
(a) Rs. 22,781.25 (b) Rs. 24,150.25 (c) Rs. 28,140.50 (d) Rs. 18,000

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(#M40001633) TCS QUESTION question 2010 Keep an EYE

A garrison of 3300 men has provisions for 32 days when supplied at the rate of 850 g per head. At the end of 7 days, a reinforcement arrives, and it is found that the provisions can last for 17 days more when supplied at the rate of 825 g per head. What is the strength of the reinforcement?
(a) 1700 (b) 1000 (c) 3000 (d) 2700

Solution

Ans. a)1700
Total quantity of provision=0.850*3300*32=89760 kg
provision consumed in 7 days=3300*7*.850=19635 kg

remaining provision=89760-19635=70125 kg

let x more men joined
then
(x+3300)*0.825*17=70125
=>x=1700
This answer is given by MITHILA NAND JHA and is the correct answer

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(#M40001632) TCS QUESTION question 2010 Keep an EYE

A scientist was researching into animal behavior in his laboratory. He was very interested in studying the behavior of bears. He travelled a mile to the north and reached the north pole. There he saw a bear. He then followed the bear for an 1 hour to the east with a speed of 2km/hr. After that he travelled south and reached his laboratory in 2 hours. What was the colour of the bear?
(a) Black (b) White (c) Red (d) Blue

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(#M40001631) TCS QUESTION puzzle 2010 Keep an EYE

If an airplane starts at point R and travels 14 miles directly north to S, then 48 miles directly east to T, what is the straight-line distance (in miles) from T to R?
(a) 25 (b) 34 (c) 50 (d) 2500

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(#M40001630) TCS QUESTION puzzle 2010 Keep an EYE

Adam sat with his friends in the Chinnaswamy stadium at Madurai to watch the 100 metres running race organized by the Asian Athletics Association. Five rounds were run. After every round half the teams were eliminated. Finally, one team wins the game. How many teams participated in the race?
(a) 30 (b) 32 (c) 41 (d) 54

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(#M40001628) TCS QUESTION latest question Keep an EYE

A Roman was born the first day of the 35th year before Christ and died the first day of the 35th year after Christ. How many years did he live?
(a) 70
(b) 69
(c) 71
(d) 72

Solution

A Roman was born the first day of the 35th year before Christ means before the start of year 0, 35 years has been past and died the first day of the 35th year after Christ means 35th year is about to start at his death so only 34 years has been completed so total years = 69


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(#M40001626) TCS QUESTION latest question Keep an EYE

Where X, Y and Z are variables representing single digits (0 to 9), Alok would like to maximize N while Bhanu would like to minimize it. Towards this end, Alok chooses a single digit number and Bhanu substitutes this for a variable of her choice (X, Y or Z). Alok then chooses the next value and Bhanu, the variable to substitute the value. Finally Alok proposes the value for the remaining variable. Assuming both play to their optimal strategies, the value of N at the end of the game would be

a) 2 b) 4 c) 9 d) -18

Solution

incomplete question

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(#M40001624) TCS QUESTION latest Keep an EYE

The IT giant Tirnop has recently crossed a head count of 150000 and earnings of $7 billion. As one of the forerunners in the technology front, Tirnop continues to lead the way in products and services in India. At Tirnop, all programmers are equal in every respect. They receive identical salaries ans also write code at the same rate.Suppose 12 such programmers take 12 minutes to write 12 lines of code in total. How many lines of code can be written by 72 programmers in 72 minutes?
a) 72 b) 432 c) 12 d) 144

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(#M40001623) TCS QUESTION latest puzzle Keep an EYE

A hollow cube of size 5 cm is taken, with a thickness of 1 cm. It is made of smaller cubes of size 1 cm. If 1face of the outer surface of the cube are painted, totally how many faces of the smaller cubes remain unpainted?

a) 900 b) 488 c) 563 d) 800

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(#M40001622) TCS QUESTION LATEST PUZZLE Keep an EYE

A sheet of paper has statements numbered from 1 to 45. For all values of n from 1 to 45, statement n says “At most n of the statements on this sheet are false”. Which statements are true and which are false?

A. The odd numbered statements are true and the even numbered are false.

B. The even numbered statements are true and the odd numbered are false.

C. All statements are true.

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(#M40001620) TCS QUESTION latest question Keep an EYE

Given 3 lines in the plane such that the points of intersection form a triangle with sides of length 20, 20 and 30, the number of points equidistant from all the 3 lines is


a) 4 b) 3 c) 0 d) 1

Solution

Answer will be a
There will be four points satisfying the given condition
one point will be incentre of the circle and other three will be excentres


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(#M40001619) TCS QUESTION latest question Keep an EYE

10 suspects are rounded by the police and questioned about a bank robbery. Only one of them is guilty. The suspects are made to stand in a line and each person declares that the person next to him on his right is guilty. The rightmost person is not questioned. Which of the following possibilities are true?
A. All suspects are lying
B. leftmost suspect is innocent .
C. leftmost suspect is guilty

a) A only b) A or C c) A or B d) B only

Solution

if first is victim then all suspects are lying. here you should remember that the rightmost person is not questioned.
If any of the person leaving leftmost is victim then the leftmost suspect is innocent. but "and" should not be used between the conditions because leftmost is not innocent necessarily
so answer is c) A or B


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(#M40001613) TCS QUESTION latest puzzle Keep an EYE

Given a collection of points P in the plane , a 1-set is a point in P that can be separated from the rest by a line, .i.e the point lies on one side of the line while the others lie on the other side. The number of 1-sets of P is denoted by n1(P). The minimum value of n1(P) over all configurations P of 5 points in the plane in general position (.i.e. no three points in P lie on a line) is
a) 3 b) 5 c) 2

Solution

The meaning of this question is little complicated. In easy language the question should be:


There are some points in the plane. We have to make a separation between these points by forming a line in such a way that one point could be separate from the others. No 3 points are in a line. Maximum no of methods for plotting the line and minimum no of methods for plotting the line will be (arrangement of points is your choice)

Now Answer Is:

For Maximize: The number of methods, Points should be drawn in the circumference of the CIRCLE So answer would be the number of total point in the plane.

For minimize: The number of methods we should draw 3 points in a TRIANGLE and all other point inside this triangle in such a way that no 3 points could be in a line.

If it will be allowed to draw the points in a line then minimum possibilities will be 2 only, because if we take all points in a line then you can separate only the corner points from the others.

For example
If we have 10 points then maximum possibilities = 10
and minimum = 3

similarly for 5 points
Max = 5, Min = 3

for 19
max= 19 Min = 3

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(#M40001610) TCS QUESTION latest puzzle Keep an EYE

Anoop managed to draw 7 circles of equal radii with their centers on the diagonal of a square such that the two extreme circles touch two sides of the square and each middle circle touches two circles on either side. Find the ratio of the radius of the circles to the side of the square.
a) 1:(4+ 7v3) b) 1:(2+ 6v2)
c) 1:(2+ 7v2) d) (2+ 7v2):1

Solution

Let the radius of circle be r
let the side of square be a
then diagonal of square= a*sqrt(2)
This diagonal length = 12*r + 2r * sqrt(2)
(because the extreme circle's radius is perpendicular to side of square.)
Thus we get

12*r+2r*sqrt(2)=a*sqrt(2)

r(6*sqrt(2)+2)=a

r/a=1/(6*sqrt(2)+2)

Thus ratio: r:a = 1:(6*sqrt(2)+2)

Ans: 1:(6*sqrt(2)+2)
this answer is given by MUGIL VANNAN, and is right

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Asked In TCS Aditi Sharma (14 years ago)

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(#M40001605) TCS QUESTION latest question Keep an EYE

Alice and Bob play the following coins-on-a-stack game. 50 coins are stacked one above the other. One of them is a special (gold) coin and the rest are ordinary coins. The goal is to bring the gold coin to the top by repeatedly moving the topmost coin to another position in the stack.Alice starts and the players take turns. A turn consists of moving the coin on the top to a position i below the top coin (0 ≤ i ≤ 20). We will call this an i-move (thus a 0-move implies doing nothing). The proviso is that an i-move cannot be repeated; for example once a player makes a 2-move, on subsequent turns neither player can make a 2-move. If the gold coin happens to be on top when it's a player's turn then the player wins the game. Initially, the gold coinis the third coin from the top. Then
a) In order to win, Alice’s first move should be a 0-move.
b) In order to win, Alice’s first move should be a 1-move.
c) Alice has no winning strategy.

d) In order to win, Alice’s first move can be a 0-move or a 1-move

Solution

(b)In order to win, Alice's first move should be a 1-move....
reason:there are two possibility after 1- move by Alice:-
1. when bob takes 0-move....then the coin config is same ..... but now alice can neither take 1-move nor 0-move.... so she has to take 2 or greater move(let it be 2 move)............
now we have only one coin above the gold coin......now bob can neither take 1-move nor 0-move nor 2-move.... so she has to take 3 or greater move.......
but the move greater then 2-move brings gold coin on top....makes alice win...

2.now bob takes 2-move after alice's first move....... now thre is only one coin above the gold coin..... so Alice takes 0-move........now we have only one coin above the gold coin......now bob can neither take 1-move nor 0-move nor 2-move.... so she has to take 3 or greater move.......
but the move greater then 2-move brings gold coin on top....makes alice win...
This answer is given by ROHIT KUMAR and is the correct answer

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Asked In TCS Aditi Sharma (14 years ago)

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(#M40001604) TCS QUESTION latest question Keep an EYE

Mr. Bean went to a shop for buying a gift to his wife on her Birthday. He bought 28 purple marbles as her wife was fond of marbles. He also bought 21greem marbles. While coming out of the shop on the way he also bought 24 red, 42 yellow and 12 pink marbles and he put them all in a bag. When he was returning back to the home a lightning occurred and suddenly due to some reasons the red, green, and yellow balls got converted into white color. But in spite of this Mr. Beans decided to give few marbles to his lovely wife. So, how many times he should put his hand in the bag so that he can gift his wife at least one ball of each color.

Asked In TCS Aditi Sharma (14 years ago)

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