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(#M40000102) ACCENTURE QUESTION Keep an EYE

How can a cake(circular) be cut into 8 pieces by making just 3 cuts?

Asked In Accenture (16 years ago)

Solved Sanal Jose Read Solution (8)

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(#M40038625) TCS QUESTION Keep an EYE

how many four digits numbers are formed such that the digits are in decreasing order

Asked In TCS krithika (11 years ago)

Solved abhinav Read Solution (16)

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(#M40032909) TCS QUESTION summations in combinations Keep an EYE

What is ∑ K^2(28cK) where K=0 to 28 and 28cK is the number of ways of choosing k items from 28 items?

a. 406 * 2^27
b. 306 * 2^26
c. 28 * 2^27
d. 56 * 2^27

Asked In TCS vikas (11 years ago)

Solved RAKESH Read Solution (4)

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(#M40005608) IBM QUESTION Permutation and combinations Keep an EYE

When four fair dice are rolled simultaneously, in how many outcomes will at least one of the dice show 3?

Solution

Total no. of outcomes = 6*6*6*6 = 1296
No. of odd outcomes (if no 3 obtained) = 5*5*5*5 = 625
so favourable outcomes = 1296-625 = 671

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Asked In IBM (13 years ago)

Solved

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(#M40007839) SELF QUESTION Keep an EYE

m men agree to purchase a gift for rs D. if three men drop out how much more will each have to contribute towards the purchase of gift

niru (13 years ago)

Solved Aman Read Solution (3)

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(#M40001463) SELF QUESTION Wonder of Maths Keep an EYE

1*8+1=9
12*8+2=98
123*8+3=987
1234*8+4=9876
12345*8+5=98765
123456*8+6=987654
1234567*8+7=9876543
12345678*8+8=98765432
123456789*8+9=987654321

Solution

This is not a question but is a good arrangement of integers. Thanks for giving this in ours site

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ULAGUNATHAN (14 years ago)

Solved

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(#M40038767) CTS QUESTION Keep an EYE

3x+4y=10
x3 + y3=6
What is the minimum value of 3x+11y=?

Asked In CTS sruthi (11 years ago)

Solved anusha Read Solution (7)

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(#M40038639) TCS QUESTION Keep an EYE

there are a no. of chocolates in a bag.if they were equally divided among 14 children,there are 10 chocolates left.if they were to be equally divided among 15 children,there are 8 chocolates left.obviously,this can be satisfied if any multiple of 210 chocolates are added to the bag.What is the remainder when the minimum feasible number of chocolates in the bag is divided by 9

Asked In TCS ranjan kumar (11 years ago)

Solved LOVENEET SALHOTRA Read Solution (12)

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(#M40009957) SELF QUESTION Keep an EYE

How much time is required to cover the distance of 910 Km by a car driver, if he start with the initial speed of 40 Km/hr. and increases the speed by 5 Km/hr for every next hour ?

Devendra Marghade (13 years ago)

Solved Aman Read Solution (4)

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(#M40013659) IBM QUESTION IBM Keep an EYE

9,4,16,6,36,21,44.....................?

Asked In IBM kundan (12 years ago)

Solved NEERAJA REDDY Read Solution (5)

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