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Frequently Asked GENPACT Placement Papers with Solution Page 47

GENPACT Select Another Category Select Another Topic

Company

  • 3i-Infotech 345
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  • Capgemini 519
  • CMC 49
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Keep an EYE (0)
Solved Question (9) UnSolved Question (509)
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(#M40004876) GENPACT QUESTION Miscellaneous Keep an EYE Keep an eye puzzle Keep an eye puzzle

5005 - 5005 ÷ 10.00 = ?

a. 0.5
b. 50
c. 5000
d. 4505

Asked In GENPACT (13 years ago)
Unsolved Read Solution (1)
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(#M40005016) GENPACT QUESTION Pipes & cisterns Keep an EYE Keep an eye puzzle Keep an eye puzzle

A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same time during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. The time required by the first pipe is:

A. 6 hours
B. 10 hours
C. 15 hours
D. 30 hours

Asked In GENPACT (13 years ago)
Unsolved Read Solution (1)
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(#M40004869) GENPACT QUESTION Miscellaneous Keep an EYE Keep an eye puzzle Keep an eye puzzle

A sum of money at simple interest amounts to Rs.720 after 2 years and to Rs.1020 after a further period of 5 years. The sum is :

Asked In GENPACT (13 years ago)
Unsolved Read Solution (1)
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(#M40005206) GENPACT QUESTION Problem on trains Keep an EYE Keep an eye puzzle Keep an eye puzzle

A train 108 m long moving at a speed of 50 kmph crosses a train 112 m long coming from opp direction in 6 seconds.The speed of the second train is
a)48 kmph b)54 kmph c)66 kmph d)82 kmph

Asked In GENPACT (13 years ago)
Unsolved Read Solution (1)
Is this Puzzle helpful?   (6)   (2) Submit Your Solution Time Distance and Speed

(#M40005365) GENPACT QUESTION Problem on time & distance Keep an EYE Keep an eye puzzle Keep an eye puzzle

A man and a woman 81 miles apart from each other, start travelling towrds each other at the same time. If the man covers 5 miles per hour to the women's 4 miles per hour, how far will the woman have travelled when they meet?

Asked In GENPACT (13 years ago)
Unsolved Read Solution (1)
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(#M40005441) GENPACT QUESTION Problem on ages Keep an EYE Keep an eye puzzle Keep an eye puzzle

The age of a man is twice the sum of the ages of his two sons. Five years hence, his age will be 16 years more than the sum of the ages of his sons. What is the father's present age?
a.42 years
b.40 years
c.45 years
d.Inadequate data

Asked In GENPACT (13 years ago)
Unsolved Read Solution (2)
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(#M40005432) GENPACT QUESTION Problem on ages Keep an EYE Keep an eye puzzle Keep an eye puzzle

X and Y are brothers and they differ by 12 years. If 4 years ago, the age of X be twice the age of Y, find their present ages.
a.X = 28 yrs, Y = 16 yrs
b.X = 24 yrs, Y = 14 yrs
c.X = 20 yrs, Y = 8 yrs
d.X = 8 yrs, Y = 20 yrs

Asked In GENPACT (13 years ago)
Unsolved Read Solution (2)
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(#M40005426) GENPACT QUESTION Problem on ages Keep an EYE Keep an eye puzzle Keep an eye puzzle

Nick and Kane were born on consecutive years and on same date. Nick is younger. The sum of their ages is 11. Find the age of the brothers.

Asked In GENPACT (13 years ago)
Unsolved Read Solution (1)
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(#M40005425) GENPACT QUESTION Problem on ages Keep an EYE Keep an eye puzzle Keep an eye puzzle

Miguel is 46 years old. He is 6 years older than thrice his son’s age. Find the age of his son.

Asked In GENPACT (13 years ago)
Unsolved Read Solution (1)
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(#M40005423) GENPACT QUESTION Problem on ages Keep an EYE Keep an eye puzzle Keep an eye puzzle

The sum of present age of Abe and the age before 7 years is 31. Find the present age of Abe. What will be his age after 7 years?

Asked In GENPACT (13 years ago)
Unsolved Read Solution (2)
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Solved Question (9) UnSolved Question (509)
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