The perimeters of two semicircles are in the ratio 2:3. The ratio of their areas are..

Subesh Kumar Yadav   11 years AGO

perimeters=2*pi*r
area=pi*(r^2)

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jatin   11 years AGO

pi R1:pi R2 =2:3
=> pi R1^2:pi R2^2=4:9

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Sanjeewani Indurkar   11 years AGO

r1:r2=2:3
therefore ratio of areas=r1^2:r2^2=4:9

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srinivasulareddy   11 years AGO

r1:r2=2:3
22/7*r1^2:22/7*r2^2=4:9

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Rats   11 years AGO

Radius of 1st circle=r1
Radius of 2nd circle=r2
Circumference of circles
π(r1)/π(r2)=2/3
r1/r2=2/3
ratio of area
=π(r1^2)/π(r2^2)
=(r1^2)/(r2^2)
=4:9

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mohan lal garg   11 years AGO

area=1.57*r*r
perimeter=3.14*r
so r1:r2=2:3
area ratio=4:9

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D.Jagruthi   11 years AGO

perimeter of the semi circle is =pi*r
(pi*r1)/(pi*r2)=(2:3)
i.e r1=2 and r2=3
the area of the semi circle is=(1/2)*pi*r^2
((1/2)*pi*r1^2):((1/2)*pi*r2^2)
=((1/2)*pi*2^2):((1/2)*pi*3^2)
=4:9

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krishnapriya   11 years AGO

given the ratio of perimeter of semicircle is 2:3
so, 2*pi*r1:2*pi*r2=2:3
(ie)r1:r2=2:3
area of two semicircle ratio=r1^2:r2^2
=2^2:3^2=4:9

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divya ramesh   11 years AGO

area of two semicircles is 2^2:3^2
so 4:9

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Girish Damodar Ballampalli   11 years AGO

since given c1/c2=2/3
therefore r1/r2=2/3
and so a1/a2=r1square/r2square=4/9

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jiaur rahman   11 years AGO

given, 2pi*r/2pi*r1=2/3
so r/r1=2/3
now 4pi*r^2/4pi*r1^2=r^2/r1^2
=2^2/3^2
=4/9= 4:9

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anjul meid   11 years AGO

2*pi*r1/2*pi*r2=2/3 =>r1/r2=2/3 =>r1^2/r2^2=4/9

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jatin patware   11 years AGO

r1/r2. 2/3

area. (r1/r2)(r1/r2). 4/9

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ajitha   11 years AGO

The perimeter ratio means radius ratio=2:3
hence the ratio of those ares=4:9

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Balakrishnan M   11 years AGO

The perimeters of two semicircles are in the ratio 2:3,
(r+pi*r):(R+pi*R)=2:3
r(1+pi):R(1+pi)=2:3
r:R=2:3
The ratio of their areas are = pi*r^2:pi*R^2
= r^2:R^2
= 2^2:3^2
= 4:9

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jitendra singh   11 years AGO

r^2:R^2

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ravindra   11 years AGO

perimeter of one semicircle is R(pi+2)
another semicircle is r(pi+2)
as R\r=2:3
ratioes ofarea of semicircles are R^2:r^2
hence 2^2:3^2=4:9

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Vinay Sipani    11 years AGO

r1 / r2 = 2 / 3
=> (r1 / r2)^2 = 4 / 9

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vipul pratap singh   11 years AGO

if r1,r2 are the radius of circles.

so given is. (pie*r1+2r1):(pie*r2+2r2)=2:3
=> r1:r2=2:3

then (pie*r1^2):(pie*r2^2)=4:9
as it depends upon squire of radi

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dan   11 years AGO

The ratio of their perimeters-
r1(pi+2)/r2(pi+2)=2/3
[pi=3.41; r1 & r2 are the radius of two semicircles respectively]
=>r1/r2=2/3
Ratio of their areas is=pi*r1^2/pi*r2^2=r1^2/r2^2=(2/3)^2=4/9(ans no.6)

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