The hypotenuse of a right triangle is 1m less than twice the shortest side. If the third side is 1m more than shortest side, find the sides of the triangle.
Let shortest side AB=x m, then hypotenuse=(2x-1)m and third side=(x+1)m.
In the given right triangle : (2x-1)^2=(x+1)^2+x^2
solve
x=0,x=3
The sides of the triangle are 3m,4m,5m... option 2