Sum of 3 digit of a three digit number is 17. On reversing the digits, the difference of new number & previous number is 297. If units place digit is 3 less then the sum of other two digits. Then product of the digits of the number is..
Let digits are x, y, (17-x-y)
number [100x+10y+(17-x-y)]
By the given condition
[100(17-x-y)+10y+x]-[100x+10y+(17-x-y)]=297
100(17-2x-y)-(17-2x-y)=297
99(17-2x-y)=297
17-2x-y=3
2x+y=14 (i)
17-x-y=x+y-3
2x+2y=20
x+y=10
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7
option 7