Seven times a given two digit number is equal to four times the number obtained by inter changing the digits and the difference of the digits is 3. Find the numbers.
Suppose x is digit in ten's place and y is the digit in unit's place.
So the number 10x+y
By reversing the order of the digits, the new Number is 10y+x
According to the given condition 7(10x+y)=4(10y+x)
Also x-y=3
Solve
number is 36
option 4