A and B are friend and their ages differ by 2 years. A's father D is twice as old as A and B is twice as old as his sister C. The age of D and C Differ by 40 years. Find the ages of A.
By the given condition
A-B=2 (i)
Now as D is twice of 'A'
D's age = 2A years
and B is twice of his sister C
C's age = B/2 years
So D is older than C
2A-(B/2)=40 = 4A-B=80 (ii)
solve (i) and (ii) eq.
A=26