A and B are friend and their ages differ by 2 years. A's father D is twice as old as A and B is twice as old as his sister C. The age of D and C Differ by 40 years. Find the ages of A.
By the given condition
A-B=2 (i)
Now as D is twice of 'A'
D's age = 2A years
and B is twice of his sister C
C's age = B/2 years
So D is older than C
2A-(B/2)=40 = 4A-B=80 (ii)
solve (i) and (ii) eq.
A=26
The difference between a two-digit number and the number obtained by interchanging the digits is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the digits of the number is 1 : 2 ?