KUNAL GAURAV   11 years AGO

Odds in favour of event A occurring = Pr(A)/Pr(A')

Odds against event A occurring =Pr(A')/Pr(A)

Probability of occurring event = Pr(A)/[Pr(A)+Pr(A')]

In the question
Pr(A')/Pr(A)=5/7 (Since we are given odds against the event)

So probability of occurring the event = 7/(5+7) = 7/12

Like? Yes (18) | No (5)  

Shubhankur Manuja   11 years AGO

Odd against of a event=(Prob. of Losing)/(Prob. of Winning)
if P is Prob of happening (winning) of event then
=> (1-P)/P = 5/7
=> 7-7P = 5P
=> 12P = 7
=> P = 7/12

Like? Yes (11) | No (1)  

Alok Kumar   11 years AGO

odd against = 5/7 so probability = 7 /12
7/(5+7)

Like? Yes (7) | No (2)  

Mariappan   11 years AGO

5:7 means 5 chance of against and 7 chance of occurrence.Thus prob of occurring is 7/12

Like? Yes (7) | No (4)  

sneha   11 years AGO

against is in the ratio 5:7
so,total sample space is (5+7)=12
against is 5 parts of 12
so probability of occurrence is 7 parts of 12 i.e.,7/12

Like? Yes (3) | No   

Undapalli Soujanya   11 years AGO

odds aginst=nonoccurence/ occurence;
P(occurence)=occurence/total

Like? Yes (2) | No   

Ankit Shukla   11 years AGO

since the probility odds against any event is =5/12
so the probility of its occurence is=1-(5/12)=7/12

Like? Yes (3) | No (1)  

sanjay singh   11 years AGO

total probability=1
odds against the event=5/12
probability=1-5/12=7/12

Like? Yes (2) | No   

Tanu   11 years AGO

(1-p)/p =5/7

p=7/12

Like? Yes (2) | No   

Md Intshamuddin   11 years AGO

Odds AGAINST event = P(not E)/P(E) = 5:7
P(not E)/P(E) = 5:7
=> P(E)=7/12

Like? Yes (4) | No (3)  

rahul jha   11 years AGO

Pr(A')/Pr(A) = 5/7

So probability of occurring of the event = 7/(5+7)
=7/12

Like? Yes (3) | No (2)  

Mayuresh Srivastava   11 years AGO

odds against=prob. of non-occurrence/prob. of occurrence
5/7=(1-p)/p
p=7/12

Like? Yes (1) | No   

Chandni Maurya   11 years AGO

ans=(5). 7/12
odd against a certain event = m:n =5:7
probability of occurrence=n/(m+n)
=7/(5+7)
=7/12

Like? Yes (3) | No (2)  

Raju Sharma   11 years AGO

odd against a event occering =p(a')/p(a)
p(a')=1-p(a) and then p(a')/p(a)=5/7
solving this p(a)=5/12;

Like? Yes (2) | No (1)  

praneeth   11 years AGO

odds against a certain event =p(A\')/p(A).we require its occurrence.so,p(A)=7/12.

Like? Yes (1) | No   

Kushal Saraf   11 years AGO

Odds AGAINST event = P(not E)/P(E)

probability of occurence=7/12

Like? Yes (2) | No (1)  

ALOK KUMAR   11 years AGO

ODD AGAINST MEANS P(E')/P(E)=5/7 GIVEN
SO P(E)=P(E)/(P(E)+P(E'))=7/12

Like? Yes (1) | No   

Jagadeesh Rampati   11 years AGO

odd against event i.e (1-p)/p=5/7
from above we get p=7/12
probability of occuring an event=7/12

Like? Yes (1) | No   

bindu   11 years AGO

odds against an event is (1-p):p=5:7.so probability of occurrence is 7/12

Like? Yes (1) | No   

ShAg   11 years AGO

odds against = 5:7
i.e. 7/(5+7) = 7/12

Like? Yes (1) | No   

Rishav kuamr   11 years AGO

odd's against of a certain event is m:n
then probability of not happening a is given by
m/m+n
so probability of a=p(a)=n/m+n
in this question probability of its occurrence is
m=5,n=7
p(a)=7/5+7=7/12

Like? Yes (3) | No (3)  

komal kirti   11 years AGO

odds against=5/7; odd against=p(not E)/p(E);
5/7=(5/12)/x; x=probability of occurance=7/12

Like? Yes (1) | No (1)  

Anil Kumar Bharti   11 years AGO

Exp:
5:7 = 5/7 that means 5/12
Againt odds means : 1-5/12 =7/12 Ans

Like? Yes (1) | No (1)  

richa ahuja   11 years AGO

odds against=unfavourable outcomes/favourable outcomes
odds in favour=fav/unfav
here odds against=5/7
therefore odds in favour=7/5
or probability of its occurrence=7/12

Like? Yes (2) | No (2)  

Harleen Chadha   11 years AGO

if odds against an event = m:n
Then the probability of its occurrence = n / (m+n)
Ans: 7/12

Like? Yes (3) | No (4)  

Manikumar R   11 years AGO

7/5+7

Like? Yes (2) | No (3)  

vky   11 years AGO

1-(5/(5+7))

Like? Yes (1) | No (2)  

S.Jenifersmaily   11 years AGO

odds against certain event:p(lossing)/p(winning)
p(A\')/p(A)=5/7
probability of occurence=7/(5+7)
=7/12

Like? Yes (1) | No (2)