A trader purchase 4 bags of rice and 10 bags of wheat for Rs.3600. He sells rice at 10% gain and wheat 2% loss and thus he gained Rs.120. Find C.P. of one bag of rice.
Let C.P. of one bag of rice be Rs.x and C.P. of one bag of wheat be Rs. y.
Then
4x+10y=3600
2x+5y=1800 (i)
by given condition (gain and profit)
Gain of Rs.4x @10% = (10/100)*4x = Rs.(2x/5)
Loss of Rs. 10y @ 2% = (2/100)*10y = Rs.y/5
(2x/5) + (y/5) = 120
2x-y=600 (ii)
solve
x=400
optin 3