If in a coded language ABHISHEK = -23 HEMANT = -9 NEHA = 10 Then ASHU = ?

Udhaya kumar   11 years AGO

Let A=1 ,B=2 ,.....Z=26 respectively......
Subtract second half of the word from first word..
ABHISHEK ;; ABHI - SHEK
(1+2+8+9)-(19+8+5+11) = 20-43 = -23
SIMILARLY ;; ASHU : AS - HU
(1+19)-(8+21)= -9 ..
SO Ans is (-9)..........

Like? Yes (28) | No (23)  

Shubham Saxena   11 years AGO

ABHISHEK = -23
HEMANT = -9
NEHA = 10
On taking the difference of first half and second half of the words, we are getting the value.
So here
ASHU=1+19+8+21
1+19=20
8+21=29
hence 20-29=-9 Ans

Like? Yes (4) | No (1)  

Pratiksha Gupta   11 years AGO

ABHISHEK = -23
HEMANT = -9
NEHA = 10
On taking the difference of first half and second half of the words, we are getting the value.
So here
ASHU=1+19+8+21
1+19=20
8+21=29
hence 20-29=-9 Ans

Like? Yes (5) | No (2)  

sujata   11 years AGO

Mark each alpha according to their alphabetical arrangement/order i.e

A=1
B=2
C=3
D=4
E=5 and so on

consider HEMANT
H=8
E=5
M=13
A=1
N=14
T=20

Divide it into 2 parts HEM and ANT
(8+5+13)-(1+14+20)
=26-35
=-9

Similarly for NEHA
NE and HA
(14+5)-(8+1)
=19-9
=10

So ASHU will be
AS and HU
(1+19)-(8+21)
=20-29
-9

Like? Yes (2) | No   

Shubham Saxena   11 years AGO

ABHISHEK = -23
HEMANT = -9
NEHA = 10
On taking the difference of first half and second half of the words, we are getting the value.
So here
ASHU=1+19+8+21
1+19=20
8+21=29
hence 20-29=-9 Ans

Like? Yes (2) | No   

pranitha karnati   11 years AGO

ABHI | SHEK --> (A+B+H+I)-(S+H+E+K)
=> (1+2+8+9)-(19+8+5+11)
=> 20-43= -23
HEM | ANT --> (H+E+M)-(A+N+T)
=> (8+5+13)-(1+14+20)
=> 26-35= -9
NE | HA --> (N+E)-(H+A)
=> (14+5)-(8+1)
=> 19-9 = 10
hence, ASHU=
AS | HU = (A+S)-(H+U)
=> (1+19)-(8+21)
=> 20-29= -9
SO , answer is -9
option : 10) none of these

Like? Yes (9) | No (7)  

Darsana K   11 years AGO

assign the alphabets numbers from 1-26
divide the word in 2 halfs
add the numbers assigned to each half and then find the difference between halfs
ABHISHEK divided into ABHI and SHEK
ABHI - SHEK=(1+2+8+9) -(19+8+5+11)=-23
HEM - ANT =(8+5+13)-(1+14+20)=-9
NE - HA=(14+5)-(8+1)=10
AS - HU=(1+19) - (8+21)=-9
therefore ans is option 10

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YUVAN SATHAIAH   11 years AGO

A(1),B(2),C(3),D(4),E(5),F(6),G(7),H(8),I(9),J(10),K(11),L(12),M(13),N(14),O(15),P(16),Q(17),R(18),S(19),T(20),U(21),V(22),W(23),X(24),Y(25),Z(26)

Every name separated equal after using addition and subtraction,

ABHISHEK=(A+B+H+I)-(S+H+E+K)
=(1+2+8+9)-(19+8+5+11)
=20-43
=-23
HEMANT=(H+E+M)-(A+N+T)
=(8+5+13)-(1+14+20)
=26-35
=-9
NEHA=(N+E)-(H+A)
=(14+5)-(8+1)
=19-9
=10
Then
ASHU=(A+S)-(H+U)
=(1+19)-(8+21)
=20-29
=-9
Answer is:-9
Option 10)none of these

Like? Yes (3) | No (1)  

T.Aravinth kumar   11 years AGO

Ashu=As - hu ...
--->
(1 + 19 )- ( 8 + 21) = -9..

Like? Yes (3) | No (1)  

OM PRAKASH JHA   11 years AGO

WE GROUP THE NAME IN 2 PAIRS AND SOLVE AS DONE HERE....
(A+B+H+I)-(S+H+E+K)=(1+2+8+9)-(19+8+5+11)=-23
(H+E+M)-(A+N+T)=(8+5+13)-(1+14+20)=-9
(N+E)-(H+A)=(14+5)-(8+1)=10
(A+S)-(H+U)=(1+19)-(8+21)=-9
HENCE ANSWER IS 10)NON OF THESE...

Like? Yes (3) | No (1)  

OM PRAKASH JHA   11 years AGO

add the alphabetic order of all letter and solve in groups as done here
(A+B+H+I)-(S+H+E+K)=(1+2+8+9)-(19+8+5+11)=-23
(H+E+M)-(A+N+T)=(8+5+13)-(1+14+20)=-9
(N+E)-(H+A)=(14+5)-(8+1)=10
(A+S)-(H+U)=(1+19)-(8+21)=-9

Like? Yes (2) | No   

Rajasekhar Reddy   11 years AGO

let A-1,B-2,..............Z-26
ABHISHEK = ABHI-SHEK
HEMANT = HEM-ANT
NEHA = (N+E)-(H+A) = 19-9 = 10
similarly,
ASHU = (A+S)-(H+U) = 20-29 = -9

Like? Yes (2) | No (1)  

R.RAVIKUMAR   11 years AGO

the coded language follows that subtraction of first half of the letters from last half of the letter as assigning number to alphabeticals.

so,ASHU gives 1 19 8 21
by coded language (1+19)-(8+21)=-9

Like? Yes (2) | No (1)  

Bupathikavya   11 years AGO

sum of first half-sum of second half is the answer so ashu ==>(a+s)-(h+u)=20-29=-9

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A.Sivapriya   11 years AGO

Given coded language

ABHISHEK = -23

By Subtracting the last half of the letters from the first half of the letters we get the answer.

1.(A+B+H+I)-(S+H+E+K)= (1+2+8+9)-(19+8+5+11)

= 20-43

= -23

ASHU = (A+S)-(H+U) = (1+19)-(8+21) = 20 - 29 = -9

So, the answer is -9

Option is none of the above

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Vinay Sipani    11 years AGO

ABHIHEK => (A + B + H + I) - (S + H + E + K)
=> (1 + 2 + 8 + 9) - (19 + 8 + 5 + 11)
=> -23

HEMANT => (H + E + M) - (A + N + T)
=> (8 + 5 + 13) - (1 + 14 + 20)
=> -9

similarly,
ASHU => (A + S) - (H + U)
=> (1 + 19) - (8 + 21)
=> -9

10)None of these

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LOGAN WOLVERINE   11 years AGO

as value 20
hu value 29
20-29=-9
option 10

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mohan lal garg   11 years AGO

ABHISHEK=1+2+8+9-19-8-5-11=-23
HEMANT=8+5+13-1-14-20=-9
NEHA=14+5-9-1=10
NOW
ASHU=1+19-8-21=-9
-9 NOT IN OPTION ANS IS
(10)NONE OF THESE

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DHIRENDRA    11 years AGO

Decode the all name withh the no and then divide the name into two parts and then subtrat the second half from first half
ASHU= 1+19-8-21=-9

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Abhinav Sharma   11 years AGO

when we put the alphabetically order no for the ABHISHEK ,and HEMANT,or NEHA .Abhiskek can divide in ABHI-SHEK,HEMANT in HEM-ANT and NEHA in NE-HA so similarly ASHU in AS-HU.Now take the alphabetic no mand sum this no respectively and then substrate.so we get ABHI=20,SHEK=43 ,20-43=-23=ABHISKEH,Similarly HEM=26,ANT=35,26-35=-9=HEMANT,so as take this reason we say AS=20,HU=29,20-29=-9=ASHU.

Like? Yes (2) | No (1)  

Dr.Dipin Singh   11 years AGO

ABHISHEK = -23
Take sum of number values of first 4( half of total) letters and subtract sum of number values of first 4( half of total) letters i.e.
(1+2+8+9)-(19+8+5+11)=-23
..
..
similarly
In ASHU,
Take sum of number values of first 2( half of total) letters and subtract sum of number values of first 2( half of total) letters i.e.
(1+19)-(8+21)=20-29=-9.. option 10.. none of these

Like? Yes (2) | No (1)  

K.ARun   11 years AGO

-9,
Because The sum of the first half of the number
Minus
The sum of the other half of the number,
i.e. by replacing each char (A-Z) by (1-26) Number.

Like? Yes (2) | No (1)  

pavani   11 years AGO

first half letters sum of a word is substracted from the second half letters sum of a word.............
1)Given word(ABHISHEK)
ABHI-SHEK
SUM OF ABHI=20
SUM OF SHEK=43
ABHI-SHEK=20-43
=-23
2)HEMANT
SUM OF HEM=26
SUM OF ANT=35
HEM-ANT=26-35
=-9
3)NIHA
SUM OF NI=19
SUM OF HA=9
NI-HA=19-9
=10
4)ASHU
SUM OF AS=20
SUM OF HU=29
AS-HU=20-29
=-9
so,answer is none of these

Like? Yes (1) | No   

shaswata tripathy   11 years AGO

alphabteical position of A-1 B-2 C-3 ...like this
so if we calculate
the first word
1 2 8 9 19 8 5 11..ABHISHEK
now the sum of the 1st four - Last four
= (1+2+8+9)-(19+8+5+11)
=20 - 43= -23

hemant = 8 5 13 1 14 20
(8+5+13) - (1+14+20)
=26 - 35
= -9
neha 14 5 8 1
= (14 + 5 ) - (8+1)
=19 - 9
=10

now ASHU = 1 , 19 , 8 , 21
(1+19) - (8+21) = - 9
ans - 9

Like? Yes (2) | No (1)  

Anurag Agrawal   11 years AGO

A+S=20
H+U=29
20-29= -9

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mounika   11 years AGO

given is ABHISHEK=-23,then a=1,b=2,h=8,i=9,s=19,h=8,e=5,k=11(this will get by giving the numbers from 1 to 26 to the alphabets from begging)
sum of the(a,b,h,i)-sumof(s,h,e,k)will give the -23
(1+2+8+9)-(19+8+5+11)=20-43=-23
like this way only we get hemant=-9((8+5+13)-(1+14+20)=(26-35)=-9)and neha=10((14+5)-(8+1)=(19)-(9)=10)
so the ASHU is -9 because sum of the (a,s)-sum of the(h,u)=(1+19)-(8+21)=20-29=-9

Like? Yes (1) | No   

javed ahmad   11 years AGO

First of all we arrenge all charecter according to there no position
ABHISHEK=-23
A=1, B=2, H=8, I=9, S=19, H=8, E=5, K=11
Now divide total no of charecter into two equal part
Sum of.first part - sum if second part
1+2+8+9-(19+8+5+11)= -23
HEMANT=-9
8+5+13-(1+14+20)= -9
NEHA = 10
14+5-(8+1))= 10
SIMILARLY
ASHU= -9
1+19-(8+21)= -9
Answer is none of these

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~Sandeep~   11 years AGO

- 9 is the answer

Like? Yes (1) | No   

srinivasan ramesh   11 years AGO

Split the letters in two half and subtract using coded no.

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krishna   11 years AGO

ans is -9
because
i.e if we convert the letters into numbers and then
half of the letters sum - other of the letters sum = ans
example:
ABHISHEK = -23
half of the letters sum = A+B+H+I = 20
other half part sum = S+H+E+K = 43
so total ans is 20-23=43
now
given that:
ASHU = (A+S)- (H+U)
= (1+19) - (8+21)
= 20-29
= -9

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Satyendra Singh   11 years AGO

ABHISHEK - 1+2+8+9-19+8+5+11= -23
HEMANT = 8+5+13-1+14+20 = -9
NEHA = 14+5-8+1=10
ASHU= 1+19-8+21 = -9
NONE OF THESE is as given answer

Like? Yes (1) | No   

Yelda Ramesh   11 years AGO

Give the numbering to a=1,b=2 and so on z=26.
sum of the first half of the letters minus second half of the letters.
ABHI=1+2+8+9=20 & SHEK=19+8+5+11=43
then 20-43=-23

Like the above: AS=1+19=20 & HU=8+21=29
then 20-29= -9;
ans is not there so "None of these" is ans.

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sandy   11 years AGO

1+19-8-21=-9

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Mahesh   11 years AGO

A=1
s=19
H=8
U=21
There fore
A+s-H-u = 1+19-8-21 = -9

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piyush   11 years AGO

divide the string into two parts
convert the alphabets to their corresponding numbers(a=1,b=2....z=26)
add all the numbers in the first part, and same for second part also.
subtract second part from first part,resulting number is the code.
a b h i || s h e k
1 2 8 9 19 8 5 11
sum of first part = 20
sum of second part = 43
first part-second part = 20 - 43 = -23
similarly,
a s || h u
1 19 8 21
sum of first part = 20
sum of second part = 29
first - second = -9
since -9 is not their in options none of these is answer

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sharathkumarp   11 years AGO

ans=-9
Abhishek =1+2+8+9-(19+8+5+11)=-23
similarly others
so ASHU=-9

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mirtunjay verma   11 years AGO

pattern is follow first half num add and subtract by
add second half..
so it will.
A=1,S=19,H=8,U=21..
so (1+19)-(8+21)=-9

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Ankit Goyal   11 years AGO

Get the rank of each letter given in the words above

subtract the sum of position of second half of letters from sum of position of letters in first half

e.g. ABHISHEK
A(1)+B(2)+H(8)+I(9) = 20
S(19)H(8) E(5) K(11) = 43

20 - 43 = -23

likewise for ASHU
A(1)+S(19) = 20
H(8)+U(21) = 29

20 - 29 = -9
which doesn't matches any of the options, hence None of the above options is correct

Like? Yes (1) | No (1)  

Leelanand Kumar Yalla   11 years AGO

Here Divide Each number into equal parts;
ABHI= 1+2+8+9=20;
SHEK= 19+8+5+11=43;
20-43=-23;
HEM= 8+5+13=26;
ANT= 1+14+20=35;
26-35=-9;
NE= 14+5=19;
HA=8+1=9;
19-9=10;
THEN
AS= 1+19=20;
HU= 8+21=29;
20-29= -9;
THEREFORE NONE OF THESE IS ANSWER........

Like? Yes (1) | No (1)  

vishal shanker polowalia   11 years AGO

In abhishek
a-k = 1- 11= -10
b-e = 2 - 5 = -3
h-h = 8 - 8 = 0
i-s = 9 - 19 = -10
The sum of digit is -23
similarly
In hemant
h-t = 8 - 20= - 12
e-n = 5 - 14 = -9
m-a = 13 - 1 = 12
The sum of digit is -9
similarly
In neha
n-a = 14 - 1= 13
e-h = 5 - 8 = -3
The sum of digit is 10

similarly
In ashu
a-u = 1 - 21= -20
s-h = 19 - 8 = 11
The sum of digit is -9

Like? Yes (1) | No (1)  

Keshav Kishlay   11 years AGO

ABHISHEK=-23 So, ABHI-SHEK=(1+2+8+9)-(19+8+5+11)=-23,
HEMANT=-9 So, HEM-ANT=(8+5+13)-(1+14+20)=-9,
NEHA=10 So, NE-HA=(14+5)-(8+1)=10
Hence, ASHU=AS-HU=(1+19)-(8+21)=-9

Like? Yes (1) | No (1)  

julee verma   11 years AGO

FIRSTLY DIVIDE THE WORDS INTO TWO PART THEN TAKE SUM OF POSITION VALUE OF WORDS AND SUBRTRACT FIRST PART FROM SECOND PART,SO
ABHISHEK= (A+B+H+I)-(S+H+E+K)=20-43=-23
HEMANT=(H+E+M)-(A+N+T)=26-35=-9
NEHA=(N+E)-(H+A)=19-9=10
HENCE ASHU=(A+S)-(H+U)=20-29=-9
SO ANSWER =-9

Like? Yes (1) | No (1)  

lovely verma   11 years AGO

break it into two parts and and then add value of words and subtract it so we get-
(ABHI)-(SHEK)=20-43=-23
(HEM)-(ANT)=26-35=-9
(NE)-(HA)=19-9=10
(AS)-(HU)=20-29=-9
SO ANSWER=-9

Like? Yes (1) | No (1)