Total cost of 2 rubbers and 3 pencils is greater than 20 rupee whereas total cost of 3 rubbers and 2

M4maths Previous Puzzles

12 Feb 2014 Solve

Total cost of 2 rubbers and 3 pencils is greater than 20 rupee whereas total cost of 3 rubbers and 2 pencils is less than 24 rupee. If cost of pencil is less then 7 rupee then for what prize of rubber and pencil total cost of 4 rubbers and 5 pencils is minimum

OPtion

1) 1, 3
2) 2, 6
3) 3, 6
4) 4, 5
5) 3, 5
6) 1, 6
7) 2, 5
8) 5, 4
9) 3, 4
10)None of these

Solution

2x+3y > 20
3x+2y < 24
y < 7
We have to find a condition such that 4x+5y is minimum

Correct Option: 5 Best Solution (16)

madanpal vishwakarma    10 years AGO

ACCORDING TO THE QUESTION
2X+3Y >20
3X+2Y20 : 2*1+3*3=11 (condition false)

option 2)2,6
2X+3Y >20 : 2*2+3*6=22 (condition true)
3X+2Y20 : 2*3+3*6=24 (condition true)
3X+2Y20 : 2*4+3*5=23 (condition true)
3X+2Y20 : 2*3+3*5=21 (condition true)
3X+2Y20 : 2*1+3*6=20 (condition false)


option 7)2,5
2X+3Y >20 : 2*2+3*5=19 (condition false)

option 8)5,4
2X+3Y >20 : 2*5+3*4=22 (condition true)
3X+2Y20 : 2*3+3*4=18 (condition false)

so the option 5 gives the lowest cast price value

Like? Yes (8) | No (1)  

S.SHAFI   10 years AGO

ans) option 5
rubber cost = r
pencil cost = p

2r + 3p > 20
3r + 2r < 24 and p < 7

Total cost of 4r + 5p is minimum if r = 3, p = 5

Like? Yes (3) | No   

Mahalakshmi   10 years AGO

3,5 satisfy all conditions

Like? Yes (1) | No   

KRISHNAN   10 years AGO

Let cost of rubber be x and pencils be y
then
2x+3y > 20
3x+2y < 24
y < 7
4x+5y is minimum at x = 3 and y = 5 so option 5 is correct

Like? Yes (2) | No (1)  

Kaustubh karekar   10 years AGO

4*3+5*5=37 is minimum
so it is 3,5

Like? Yes (1) | No   

viveka   10 years AGO

2r+3p>20
3r+2p2.4 r

Like? Yes (1) | No   

aviral bhargava   10 years AGO

choosing by options

Like? Yes (2) | No (2)  

Varunraj Reddy   10 years AGO

Given Conditions are
2r+3p>20-----i)
3r+2p

Like? Yes (1) | No (1)  

PINTU KUMAR   10 years AGO

it gives min value

Like? Yes (1) | No (1)  

sravani   10 years AGO

solve for the common values then we get p is < r
p:pencil
r:rubber
then for r=3
p=5 we get min values satisfying the above conditions.

Like? Yes (1) | No (1)  

Suman   10 years AGO

ans will be (3,5)
Using hit and trial method, option five satisfy given conditions and price of 4 rubber and 5 pencil will be minimum =3*4+5*5=12+25=37rupees

Like? Yes (1) | No (1)  

T G   10 years AGO

ans is 5
x=price of rubber
y=price of pencil
2x+3y>20...(1)
3x+2y

Like? Yes (1) | No (1)  

Sushma Reddy   10 years AGO

By options we get minimum amount at 3,5 as
4*3+5*5= 37

Like? Yes (1) | No (1)  

Praneeth   10 years AGO

By options we get minimum value 37 for 3,5

Like? Yes (1) | No (1)  

R.RAVIKUMAR   10 years AGO

By substitution and comparing with original equations, we will get minimum cost for 3,5

Like? Yes (1) | No (1)  

Srinath   10 years AGO

Check all options for given data:
2r+3p>20
3r+2p

Like? Yes (1) | No (2)