sumit   10 years AGO

1*3^0=1
(1+2)*3^1=9
(1+2+3)*3^2=54
(1+2+3+4)*3^3=270
(1+2+3+4+5)*3^4=1215 option(3) ans

Like? Yes (27) | No (6)  

RAKESH   10 years AGO

1*3^0
3*3^1
6*3^2
10*3^3
15*3^4 = 1215

Like? Yes (13) | No (5)  

Inline Geek   10 years AGO

The sequence is like

3^0 * (1) = 1,
3^1 * (1+2) = 9,
3^2 * (1+2+3) = 54,
3^3 * (1+2+3+4) = 270,

next term would be:

3^4 * (1+2+3+4+5) = 1215

Like? Yes (7) | No (2)  

Neel Patel   10 years AGO

1*3^0=1
(1+2)*3^1=9
(1+2+3)*3^2=54
(1+2+3+4)*3^3=270
so ans
(1+2+3+4+5)*3^4=1215

Like? Yes (3) | No   

somaiah tummala   10 years AGO

1 * 3^0 = 1
3 * 3^1 = 9
6 * 3^2 = 54
10 * 3^3 = 270
so the answer is : 15 * 3^4 = 1215

from above multiplications we get:

the difference between the 1,3 ; 3,6 ; 6,10 is 2,3,4 respectively
so next number is 5 that means the difference between the 10,5 is 5

Like? Yes (3) | No   

Mogilipuri.Harish   10 years AGO

1*3^0 => 1
here 1+2= 3 then
3*3^1 => 9
here 3+3 = 6 then
6*3^2 => 54
here 6+4 =>10 then
10*3^3 =>270
here 10+5= 15 then
15*3^4 =>1215

ans: 1215

Like? Yes (4) | No (2)  

palasiva   10 years AGO

1*3^0, 3*3^1, 6*3^2, 10*3^3,15*3^4
= 1,9,54,270,1215

Like? Yes (4) | No (2)  

Deepak Reegan A   10 years AGO

1215 is the answer , though 1215 get as 5 *3 *3 *3*3 *3, others doesnt have

Like? Yes (1) | No   

kumar aryan   10 years AGO

1=1*1
9=3*3
54=9*6
270=27*10
so next number is 81*15=1215

Like? Yes (1) | No   

elamaran   10 years AGO

each alone sum of 2nd,3rd, and 4 no s are 9

Like? Yes (1) | No   

subhashis mondal   10 years AGO

1*1=1
3*3=9
6*9=54
10*27=270
15*81=1215

Like? Yes (1) | No   

Divakar   10 years AGO

sum is 9 in 1215 as in 9,54 and 270 the digits sum is 9

Like? Yes (1) | No   

GAURAV CHOUDHARY   10 years AGO

1*1 = 1
3*3 = 9
6*9 = 54
10*27 = 270
15*81 = 1215

Like? Yes (1) | No   

Prashant Rupnur   10 years AGO

does not know

Like? Yes (1) | No   

Jyothi P   10 years AGO

3^0*1 ,3^1 *3,3^2*6,3^3*10,3^4*15
here, first term is 3 powers starting from 0
second term 1,3,6,10
we get 3 by adding 2 to previous term 1
we get 6 by adding 2+1 to previous term
we get 10 by adding 3+1 to previous term
so next term will be prev term 10+4+1=15
hence 3 power 4 multiply by 15 we get 1215.

Like? Yes (1) | No   

abhishek pandey   10 years AGO

after 1 ,sum of every term is 9,and every term is amultiple of 9

Like? Yes (1) | No   

Dr.Dipin Singh   10 years AGO

1x3^0 = 3
3x3^1=9
6x3^2=54
10x3^3=270
15x3^4=1215

So option 3 is the answer.

Like? Yes (2) | No (1)  

Tamal Chakraborty   10 years AGO

9's compliment

54 -> 5+4 = 9
270 -> 2+7+0 = 9
1215 -> 1+2+1+5=9

Like? Yes (1) | No   

preeti saw   10 years AGO

9+0=9
5+4=9
2+7+0=9
1+2+1+5=9

Like? Yes (1) | No   

arjun   10 years AGO

1215

Like? Yes (1) | No (1)  

Ankur Gupta   10 years AGO

N\A

Like? Yes (1) | No (1)  

Manikumar R   10 years AGO

5+4=9
2+7=9
1+2+1+5=9

Like? Yes (1) | No (2)  

Jigyasa Kumar   10 years AGO

sum should be equal to 9

Like? Yes (1) | No (2)  

abhilasha   10 years AGO

sum of the digits is 9

Like? Yes (1) | No (2)  

shabih abbas   10 years AGO

15*81=1215

Like? Yes (1) | No (3)  

MUKESH YADAV   10 years AGO

leave the first term all the other term of the series have addition of its digit ids 9..
like this 1+2+1+5=9
thats y option 3 is correct

Like? Yes (2) | No (11)