2.2 cubic dm. of lead is to be drawn into a cylindrical wire 0.50 cm in diameter. The length of the

Revathi   10 years AGO

vol = pi*r*r*h
diameter=0.50cm
radius=0.50/2cm=0.25/100m
vol=2.2dm=2.2/1000m
2.2/1000=(22/7)((0.25/100)^2)*h
h=(2.2/1000)(7/22)(100^2/0.25^2)
h=7/0.0625
h=112m

Like? Yes (11) | No (4)  

bhagya   10 years AGO

Let the length of the wire be h metres. Then,

? (0.50/(2 x 100))2 x h = 2.2/1000

h = ( (2.2/1000) x (100 x 100)/(0.25 x 0.25) x (7/22) ) = 112 m.

Like? Yes (7) | No (1)  

Rishabh   10 years AGO

(22/7)*(r)^2*h = volume of cube
h = (2.2/1000)*(7/22)/(.5/2)^2

Like? Yes (9) | No (3)  

Pramod Gaikwad   10 years AGO

Let the length of the wire be h metres. Then,
pi* (0.50/(2 x 100))2 x h = 2.2/1000
h = ( (2.2/1000) x (100 x 100)/(0.25 x 0.25) x (7/22) ) = 112 m.

Like? Yes (7) | No (3)  

prudhvi vaddi   10 years AGO

LENGTH OF THE WIRE=X MTS
W. K.T V=(PIE* R^2* H)
H=V/(PIE*R^2)
GIVEN V=2.2CUBI DM=2.2/1000 DM
(0.50/(2 x 100))2 x X = 2.2/1000DM
X= ( (2.2/1000) x (100 x 100)/(0.25 x 0.25) x (7/22) ) = 112MTS

Like? Yes (4) | No   

Anand Dwivedi   10 years AGO

Let Length of Wrire= h Meter then

(0.50/(2*100)^2 * h= 2.2/1000

Than [2.2/1000]*[100*100]/[0.25*0.25]*[7/22]

==112 meter after solving all value

So answer will be 112 meter

Like? Yes (4) | No (2)  

Ashwin Dinesh   10 years AGO

l = 2200/(pi*0.25*0.25) = 11204 cm = 112 m
option 8)

Like? Yes (3) | No (1)  

RAKESH   10 years AGO

2.2 = pi*r^2* h gives value of h

Like? Yes (3) | No (1)  

K.ARun   10 years AGO

V=pi r^2 * h
2.2/1000 = 22/7 * (0.50/(2*100))^2 *h
on solving we get h=112m

Like? Yes (7) | No (6)  

Sravanthi   10 years AGO

pi(r^2)h=volume
22/7 * .25*.25 * h = 2200
h= 2200 * 7 / (22*.25*.25) = 11200 cm =112m

Like? Yes (4) | No (3)  

ravi prakash   10 years AGO

h = ( (2.2/1000) x (100 x 100)/(0.25 x 0.25) x (7/22) ) = 112 m.

Like? Yes (3) | No (2)  

Himanshu porwal   10 years AGO

volume of cyl. =(3,14).r^2h
vol. of lead = 2.2 cubic dm=2200cm^3
(3.14).r^2.h=2200
r=0.25cm
h=112m(approx.)
so option. 8 is correct

Like? Yes (4) | No (3)  

Manasa Kotha   10 years AGO

v=pir2h
2.2/1000 = 22/7 * (0.50/(2*100))^2 *h
on solving 112

Like? Yes (3) | No (2)  

CHANDA VIJAYALAKSHMI   10 years AGO

Let the length of the wire be h metres. Then,

? (0.50/(2 x 100))2 x h = 2.2/1000

h = ( (2.2/1000) x (100 x 100)/(0.25 x 0.25) x (7/22) ) = 112 m.

Like? Yes (2) | No (1)  

Taresh   10 years AGO

2.2 dm^3 =2200cm^3
volume of metal doesn't change with shape
hence
volume of cylinder = pi r^2 h
h= V/pi r^2
= 2200/0.25*3.14
= 11204.51cm
~112m

Like? Yes (4) | No (3)  

Shreya Banerjee   10 years AGO

Answer :
Option c

Explanation :


Let the length of the wire be h metres. Then,

? (0.50/(2 x 100))2 x h = 2.2/1000

h = ( (2.2/1000) x (100 x 100)/(0.25 x 0.25) x (7/22) ) =

112 m.

Like? Yes (3) | No (2)  

Sabita Mohanty   10 years AGO

convert the quantities into m
and apply cylinders volume formula

Like? Yes (4) | No (3)  

Chirag Ranjan Lahiri   10 years AGO

Let the length of the wire be h metres.
Then,
(0.50/(2 x 100))2 x h = 2.2/1000
h = ( (2.2/1000) x (100 x 100)/(0.25 x 0.25) x (7/22) ) = 112 m.

Like? Yes (3) | No (2)  

shilpareddy   10 years AGO

applying the formula of volume of cylinder pi*r*r*l=volum
frm that we can find the length of wire as 112m

Like? Yes (1) | No   

Udhaya kumar   10 years AGO

V = pi / 4 * d^2 * l
2.2*10^-3 = pi / 4 * (0.5 *10 ^-2)^2 * l
l =112.045 = = = 112 m..............

Like? Yes (2) | No (1)  

AJAI AGARWAL   10 years AGO

0.22=PI*0.0025*x

Like? Yes (2) | No (1)  

lakshmi   10 years AGO

Let the length of the wire be h metres. Then,
∏ (0.50/(2 x 100))2 x h = 2.2/1000
 h = ( (2.2/1000) x (100 x 100)/(0.25 x 0.25) x (7/22) ) = 112 m.

Like? Yes (2) | No (2)  

Anand   10 years AGO

(0.50/(2 x 100))2 x h = 2.2/1000

h = ( (2.2/1000) x (100 x 100)/(0.25 x 0.25) x (7/22) ) = 112 m.

Like? Yes (3) | No (3)  

jayalakshmi   10 years AGO

Let the length of the wire be h metres. Then,
∏ (0.50/(2 x 100))2 x h = 2.2/1000
 h = ( (2.2/1000) x (100 x 100)/(0.25 x 0.25) x (7/22) ) = 112 m.

Like? Yes (2) | No (2)  

BHASKAR MANDAL   10 years AGO

option 8

Like? Yes (2) | No (2)  

kumari jyoti   10 years AGO

volume of lead given=2.2dm^3.
now calculating the volume of the wire and equating it to the given volume;
(22/7)*r^2*l=2.2 dm^3
now r=d/2, d is given to be 0.5 cm. so,evaluating it we get l=112m i.e. option 8.

Like? Yes (2) | No (2)  

Mithun Kumar Kesari   10 years AGO

112 m

Like? Yes (2) | No (2)  

Surit Datta   10 years AGO

Let the length of the wire be h meters.
Then,
(0.50/(2 x 100))2 x h = 2.2/1000
h = ( (2.2/1000) x (100 x 100)/(0.25 x 0.25) x (7/22) ) = 112 m.

Like? Yes (2) | No (2)  

PAWAN KUMAR   10 years AGO

Volume of lead = 2.2 dm^3 = 2.2*1000 cm^3 = 2200 cm^3
Radius of cylindrical wire = 0.5/2 cm = 0.25 cm
Let length of wire be h cm.
volume of cylinder = volume of lead
=> pi*r*r*h = 2200
=> 22/7*0.25*0.25*h = 2200
=> h = 7*4*4*100 = 112*100 cm = 112 m. Ans.

Like? Yes (2) | No (2)  

Rupesh   10 years AGO

π*0.25/100*0.25/100 *x=2.2/1000
x=112 m ans..

Like? Yes (1) | No (1)  

jagan   10 years AGO

volume of cylinder=2.2 cubic dm=2.2×1000 cubic cmΠr^2h=2200r=0.5/2= 0.25cmh=11210.19 cm=112.10 metre
Ans: Length of wire is 112.10 metre

Like? Yes (1) | No (1)  

Rahul Rathod   10 years AGO

Let the length of the wire be h meters.
pi* (0.50/(2 x 100))2 x h = 2.2/1000
h = ( (2.2/1000) x (100 x 100)/(0.25 x 0.25) x (7/22) )
=112 m.
so ans is 112 m option 8)

Like? Yes (3) | No (4)  

Rajat Rokade   10 years AGO

Let the le3ngth of the wire be x metres.
so, pi*((0.50)/(2*100)) *x = 2.2/1000
x= ((2.2/1000)*(100*100)/(0.25*0.25)*(7/22))
so x=112m

Like? Yes (3) | No (4)  

Sundar Kumar   10 years AGO

Let the length of the wire be h metres. Then,
∏ (0.50/(2 x 100))^2 x h = 2.2/1000
h = ( (2.2/1000) x (100 x 100)/(0.25 x 0.25) x (7/22) ) = 112 m
Answer: Option: 8) 112m

Like? Yes (3) | No (4)  

Praneet   10 years AGO

vol. of cube=vol. of wire
so
lenght of wire =vol. of cube divided by pi*(.50/2)2

Like? Yes (2) | No (3)  

Meera R   10 years AGO

1 cubic dm=0.001 cubic m
1cm=.001m
pi*r*r*l=volume=volume of lead=2.2cubic dm=0.0022cubic m
so l=(0.0022*10000)/(0.25*0.25*pi)
ie l=112.10m

Like? Yes (1) | No (2)  

purushothama   10 years AGO

Let the length of the wire be h metres. Then,

? (0.50/(2 x 100))2 x h = 2.2/1000

h = ( (2.2/1000) x (100 x 100)/(0.25 x 0.25) x (7/22) ) = 112 m.

Like? Yes (1) | No (3)