A number is formed by using the integers 2, 3, 4 and 9. According to the condition given below.
1) Number is even
2) Thousand's digit of the number is odd
3) Ten's digit is smaller then hundred digit
What will be the sum of all such numbers.
Total numbers = 4*3*2*1 = 24
Condition one - Number is even so possibilities = 3*2*1*2 = 12
Condition two - Thousand digit of the number is odd so possibilities = 2*2*1*2 = 8
Condition three - Ten's digit is smaller then hundred digit so possibilities = 2*2*1*2/2 = 4
These are
3 9 4 2
9 4 3 2
3 9 2 4
9 3 2 4
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2 6 6 2 2