A car plate is written by taking 3 alphabets and 3 integers, if after 3 alphabets 3 zeros are not allowed,
then total possible car plates with no code repeated are ?
total alphabets are 26 hence total possibilities for taking 3 alphabets are 26*26*26 = 17576
Total integers are 10 hence total possibilities for taking 3 integers are
10*10*10 = 1000
Total number of avoided cases are 26*26*26*1*1*1 = 17576
Therefore answer is 17576 * 1000 – 17576 = 17558424