x, y, z and k are four non zero positive integers satisfying 1/x + y/2 = z/3 + 4/k, minimum integral

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01 Apr 2015 Positive integers

x, y, z and k are four non zero positive integers satisfying 1/x + y/2 = z/3 + 4/k, minimum integral value of k for integral value of x, y and z will be

OPtion

1) 1
2) 2
3) 3
4) 4
5) 5
6) 6
7) 7
8) 8
9) 9
10)10

Solution

Obviously it will be 1
For example
if x = 1, y = 8 and z = 3
1/1 + 8/2 = 3/3 + 4/k
4 = 4/k
k = 1

Option 1)

Correct Option: 1 Best Solution (21)

siddharth prakash singh   9 years AGO

solving the given eq we get k=24x/(6+3xy-2xz)
as we have to obtain the minimum value of k, we will put x=1, y=8 and z=3
on putting we get k=1.

Like? Yes (7) | No (2)  

Supriya Mondal   9 years AGO

Here,
x will be 3 , y will be 8 and z will be 1.
Then k will be 1 which is the minimum value of k
Here, all the values of x,y,z,k are non zero positive integer.
So, option 1)1 is the right answer

Like? Yes (2) | No   

kranthi kanchanapally   9 years AGO

IF WE TAKE X=1 Y=8 AND Z=3
THEN
1+4-1=4/K
=>K=4/4

Like? Yes (1) | No   

Vipul   9 years AGO

3y-2z =18 when solved.
we get values of x=1,y=8 & z=3...
and thus integral value of K=1 we got

Like? Yes (1) | No   

Dr.Dipin Singh   9 years AGO

1/2 + 9/2 = 3/3 +4/1
or
5=5
so k=1

Like? Yes (2) | No (1)  

Aman   9 years AGO

x=2
y=9
z=3
k=1

Like? Yes (2) | No (1)  

Srinivas   9 years AGO

Values of x y z k are1 8 3 1

Like? Yes (1) | No   

Jayanta Dutta   9 years AGO

If I take x,y,z 1,8,3 then k becomes 1...

Like? Yes (1) | No   

abhinav upadhyay   9 years AGO

if x=1 , y= 12 , z= 9 and k=1 satisfies the equation

Like? Yes (1) | No   

nikhil   9 years AGO

x=1,y=8,z=3

Like? Yes (1) | No   

KUMAR HARSH   9 years AGO

let x=1,y=8,z=3 and k=1
1+4=1+4
so minnimum value of k is 1

Like? Yes (1) | No   

Ritesh   9 years AGO

X=1
Y=8
Z=3
K=1

Like? Yes (1) | No   

Vaibhav Mishra   9 years AGO

min value of k=1
x=1,y=8,z=3

Like? Yes (2) | No (1)  

PAWAN KUMAR   9 years AGO

put k=1, x=1, y=8, z=3

Like? Yes (1) | No (1)  

APPIKONDA SANTOSH NAIDU   9 years AGO

1

Like? Yes (1) | No (1)  

jaganmohan rao .pola   9 years AGO

1

Like? Yes (1) | No (1)  

Amarnath Kumar Upadhyay   9 years AGO

put k=1 then
1/x+y/2= (z+12)/3
when z=3,y=8,x=1
LHS=RHS

Like? Yes (2) | No (2)  

Jay parmar   9 years AGO

Optn 1

Like? Yes (1) | No (1)  

pranith   9 years AGO

take 1,8,3 values of x y z

Like? Yes (1) | No (1)  

prabhat kumar   9 years AGO

when x=1,y=8,k=1 then z will be 3

Like? Yes (1) | No (1)  

bharat bhuriya   9 years AGO

1/x+y/2-z/3=4/k
According to question
x,y,z,k=1,2,3,4,5,6,7,8......... n
K is minimum integral value
Assume
K=1,x=1,y=8,z=3
1+4-1=4
Eqn satisfy
K=1

Like? Yes (1) | No (1)