4, 16, 7, 49, 13, 169, x, y Sum of x and y will be

Surit Datta   9 years AGO

4^2 = 16
6 + 1 = 7
7^2 = 49
4+9 = 13
13^2 = 169
1+6+9 = 16
16^2 = 256
so,
256 + 16 = 272
so option 3
that's it.

Like? Yes (6) | No (3)  

Supriya Mondal   9 years AGO

Here first number is 4
and second number is square of first number, i.e 4*4=16
third number is sum of the digits of second number, i.e 1+6=7
like that, forth number is=7*7=49
and fifth number is=4+9=13
sixth number is 13*13=169
So, x will be=1+6+9=16
and y will be=16*16=256
So, sum of x and y will be 16+256=272
So, option 3)272 is the right answer

Like? Yes (4) | No (3)  

sompon temtheerakij   9 years AGO

4^2 = 16
1+6 = 7
7^2 = 49
4+9 = 13
13^2 = 169
1+6+9 = 16
16^ = 256
16+256 = 272

Like? Yes (1) | No   

Vaibhav Srivastava   9 years AGO

4^2 = 16
1+6 = 7
7^2 = 49
4+9 = 13
13^2 = 169
1+6+9 = 16 = x
16^2 = 256 = y
x+y = 16+256 = 272

Like? Yes (2) | No (1)  

kiran kumar   9 years AGO

4,4*4,7,7*7,13,13*13,
by option verification
16,16*16=272

Like? Yes (1) | No   

Raman   9 years AGO

4, 16, 7, 49, 13, 169, x, y
4, 16, 7( 6+1), 49(7^2), 13(4+9), 169(13^2), 16(1+6+9), 256 (16^2)
x+y=16+256=272

Like? Yes (2) | No (1)  

Ch. Anusha Kumari   9 years AGO

x=16;y=16*16=256
sum of x+y=16+256=272.

Like? Yes (1) | No   

priyanka    9 years AGO

x=1+6+9=16
y=16^2=256
x+y=272

Like? Yes (1) | No   

praveen kumar   9 years AGO

3 is rt ans

Like? Yes (1) | No   

sonu singh   9 years AGO

4*4=16 and 1+6=7 and 7 square is 49 and 4+9=13 and sqr r 169 then answer is 1+6+9=16 and it sqr is 256 +16=272 ans

Like? Yes (1) | No   

Neeraja Aruva   9 years AGO

4,4*4=16
4+3=7,7*7=49
7+6=13,13*13=169
13+3=16,16*16=256
256+16=272

Like? Yes (1) | No   

SUSHANT KUMAR   9 years AGO

4, 16, 7, 49, 13, 169, x, y
4, 4^2
4+3, 7^2
7+6, 13^2
13+3, 16^2
16+256=272 ANS.

Like? Yes (1) | No   

s.durgadevi   9 years AGO

4*4=16
1+6=7
7*7=49
4+9=13
13*13=169
1+6+9=16
16*16=256
x=16,y=256
x+y=272

Like? Yes (2) | No (1)  

Subrata Sadhukhan   9 years AGO

16*16+16=272

Like? Yes (1) | No   

Madhumoy Gope   9 years AGO

Given: 4,4^2,7,7^2,13,13^2,x,y
Then the value of y must be x^2
Now, x+y=x+x^2=16+16^2=272. (putting values one by one starting from14)
So,option 3 is correct

Like? Yes (1) | No   

surya    9 years AGO

1+6+9=16
x=16
y=16*16=256
256+16=272

Like? Yes (1) | No   

nishi   9 years AGO

the series is like 4,16,7,49,169,x,y
as we can see that the odd terms are the square roots of the next even terms ..so as the series goes we need to find x+y
which is x+x*x
which is satisfied by the option 3 only

Like? Yes (1) | No   

suresh kumar kadavakollu   9 years AGO

4^2=16----->1+6=7
7^2=49------>4+9=13
13^2=169---->1+6+9=16
16^2=256
so X is 16 and Y is 256
X+Y=256+16=272

Like? Yes (1) | No   

kranthi kanchanapally   9 years AGO

4*4=16 next 1+6=7
then 7*7=49 next 4+9=13
then 13*13=169 next 1+6+9=16
so 16*16=256
then x=16 and y=256
sum of x and y is=272 is the right answer

Like? Yes (1) | No   

jalaj   9 years AGO

16,256 becoz
see 4,16,7
3rd nummber is always sum of unit and tens digit of 16(6+1)
2 nd number is square of first number.

Like? Yes (1) | No   

Deepika Maheshwari   9 years AGO

the next nmbr will be sum of prev. nmbr
x=16 will be the nxt nmber
n observing the series square of 16 that is y=256
256+16=272

Like? Yes (1) | No   

Gaurav Goel   9 years AGO

13+3=16 nd 16*16=256
16+256=272

Like? Yes (1) | No   

gulshan kumar   9 years AGO

4*4=16
6+1=7
7*7=49
9+4=13
13*13=169
1+6+9=16
16*16=256+16=272

Like? Yes (1) | No   

Pranati Kundu   9 years AGO

16+16^2=272

Like? Yes (1) | No   

MRITUNJAY   9 years AGO

sum of previous digit = x

x=1+6+9=16
y=x*x

y=16*16=256

x+y=256+16=272

Like? Yes (1) | No   

Srinivas   9 years AGO

1+6+9=16=x,y=256
x+y=272

Like? Yes (1) | No   

Jaspalsingh Parmar   9 years AGO

two series are there
4,7,13,16,22....
16,49,169,256,484.....
sum will be 256+16=272

Like? Yes (2) | No (2)  

SAGNIK DATTA   9 years AGO

y=x*x so only 16 + 16^2 satisfies the option

Like? Yes (1) | No (1)  

anand vijay   9 years AGO

given series is written as 4,4^2=16
next no will be 1+6=7 ,7^2=49(4+9=13)
13,13^2=169(1+6+9=16)
16,16^2=256
16+256=272 ans
option 3

Like? Yes (1) | No (1)  

ABHINAV PUSHPAM   9 years AGO

4, 4^2=16
1+6=7, 7^2=49
4+9=13, 13^2=169
1+6+9=16, 16^2=256
so, x=16 & y=256
sum= 272
option 3)

Like? Yes (1) | No (1)  

rajeev kumar   9 years AGO

16=1+6=7
49=4+9=13
169=1+6+9=16
16^2=256
256+16=272

Like? Yes (1) | No (1)  

RAKESH   9 years AGO

x = 1+6+9 = 16, y=x^2 = 256

x+y = 272

Like? Yes (1) | No (1)  

kishore   9 years AGO

4 ,4^2 , 7, 7^2, 13, 13^2, 16, 16^2

4+3=7 , 7+6=13 , 13+3 = 16

Like? Yes (1) | No (1)  

vivek   9 years AGO

As,
4*4=16.....(1+6)=7
7*7=49.....(4+9)=13
13*13=169.....(1+6+9)=16
16*16=256
so, x+y= 16+256=272

Like? Yes (2) | No (2)  

Anuradha   9 years AGO

4,4^2,(4+3),(4+3)^2,(4+3+6),(4+3+6)^2
=> next numbers are 4+3+6+3,( 4+3+6+3)^2=16,256
therefore sum is 16+256=272

Like? Yes (1) | No (1)  

Ramdas Singathiya   9 years AGO

from series y=x^2
x+y=x+(x^2) = X(X+1)
now check options

Like? Yes (1) | No (1)  

Sundar Kumar   9 years AGO

let us consider x = 16 then y = x^2 = 16^2 = 256
Therefore , Sum of x and y will be = 16+256 = 272

Answer: Option:3) 272

Like? Yes (1) | No (1)  

moumita   9 years AGO

4
4*4=16
4+3=7
7*7=49
7+6=13
13*13=169
13+3=16
16*16=256
So, x=16 & y=256
Sum=x+y = 16+256 = 272

Like? Yes (1) | No (1)  

umesh   9 years AGO

x=16 y=16*16
x+y=272
the sequence is in form of 3 ,6,3,6 alternate position difference

Like? Yes (1) | No (1)  

mani   9 years AGO

x=16
y=256 i.e. square of 16

x+y= 16+256 is 272

Like? Yes (1) | No (1)  

Niraj   9 years AGO

4, 16, 7, 49, 13, 169, x, y

4, (4)^2, (1+6), (7)^2, (9+4), (13)^2, (1+6+9), (16)^2

so X=(1+6+9) and Y=(16)^2
=> X+Y = 16+256 = 272

Like? Yes (1) | No (1)  

NESAB JAFAR   9 years AGO

di git is the square of another digit

Like? Yes (1) | No (1)  

VIKAS KUMAR THAKUR   9 years AGO

4*4=16
1+6=7
7*7=49
4+9=13
13*13=169
1+6+9=16
16*16=256
sum of x+y=16+256=272

Like? Yes (1) | No (1)  

b.subbarao   9 years AGO

4^2=16
1+6=7 then 7^2=49
4+9=13 then 13^2=169
1+6+9=16^2=256
so x=16,y=256 hence 16+256=272 there fore option 3 is correct

Like? Yes (1) | No (1)  

NITHYA   9 years AGO

=(16*16)+16
=272

Like? Yes (1) | No (1)  

Janamma Vunnam   9 years AGO

13+3=16 then 16*16=256
x=16,y=256 total =272

Like? Yes (1) | No (1)  

siddharth prakash singh   9 years AGO

x=16
y=256
x+y= 272

Like? Yes (2) | No (2)  

Josepheena Joseph   9 years AGO

4^2 = 16
1+6 = 7
7^2 = 49
4+9 = 13
13^2 = 169
1+6+9 = 16
16^2 = 256
ans = 16 + 256 = 272

Like? Yes (1) | No (1)  

M.RAGHAVENDAR   9 years AGO

16^2=256
256+16=272

Like? Yes (1) | No (1)  

PAWAN KUMAR   9 years AGO

x= 13+3=16
y=16*16 = 256
So, x+y = 272.

Like? Yes (1) | No (1)  

Yathiraj   9 years AGO

x=16
y=256
x+y=272

Option 3.

Like? Yes (2) | No (2)  

bhishma   9 years AGO

4+9=13-----13^2---169
1+6+9=16^2---256
256+16=272

Like? Yes (1) | No (1)  

Gourav Rajdhar   9 years AGO

y=x*x
so 256=16*16
hence 256+16=272

Like? Yes (1) | No (1)  

aman aditya   9 years AGO

4 followed by 4*4=16
7 followed by 7*7=49
13 followed by 13*13=169
16+16*16=272

Like? Yes (1) | No (1)  

ADARSH GAURAV   9 years AGO

1+6+9=16
16+256=272

Like? Yes (1) | No (1)  

Anubhav jain   9 years AGO

4
4^2=16
4+3=7
7^2=49
7+6=13
13^2=169
13+3=16
16^2=256
256+16=272

Like? Yes (1) | No (1)  

shirisha karakamukkala   9 years AGO

7-4=3
x-13=3
x=16
16^2+16=272

Like? Yes (1) | No (1)  

M.Ranjith Kumar    9 years AGO

The first no 13+3=16=x
Y=16*16=256
X+y=272

Like? Yes (1) | No (1)  

SENTU PAUL   9 years AGO

after solving the above problem,we get the value of x and y.
so, x=16 and y=256
x+y=272

option 3) 272

Like? Yes (1) | No (1)