RAKESH   10 years AGO

x-k = 7(4k+1)

x-k is divisible by 5, so k should be 6.

Like? Yes (4) | No (1)  

Aashish gohel   10 years AGO

let x-k=5m
where m=1,2,3,......
x-29k=7
(x-k)-28k=7
5m-28k=7
k=5m-7/28
k=6

Like? Yes (3) | No (1)  

sompon temtheerakij   10 years AGO

X = 29k+7........1
X-k = 5A...........2
from 1,2 ;- 28k+7 = 5A
The product can divided by 5 , k = 1 , 6
ans. k= 6

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Venkatesh kadali   10 years AGO

x=29k+7 we substitute k value than we x value.wecan subtract k value from x ,nd the result is divisible by 5 than we get k=6.

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Radhika   10 years AGO

Put the values of k from the options in the given equation
x=29k+7 by putting the value of k in this equation we get the value of x.
Then calucate x-k if its unit place is 0 or 5 ten it is divisible by 5 and the value of k which we have taken is the required answer.
i.e. by taking k=6 x=29*6+7=181 that means x=181 and we have k=6 now x-k=181-6=175 which is divisible by 5.
therefore, this is our required answer

Like? Yes (2) | No (1)  

Jotshnesh Patel   10 years AGO

put the value of x into x-k,
We'll get one equation that is 28k+7.
put the value of k (k=6) and answer 175 which is divisible by 5.

Like? Yes (1) | No   

atmakuri jagadish   10 years AGO

x=29k-7
so , x-k = 28k+7
As x-k is divisible by 5
So, 28K + 7 should also be divisible by 5
Hit and trial of the options given results in only one correct option
So answer is 6 , option 5

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sai   10 years AGO

taking -k on both sides
x-k= 28k+7 this is divisible by 5 go through options 6 is answer so k=6

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KUMAR HARSH   10 years AGO

X=29*k+7
X-k=28*k+7
28*6+7=175
Which is divisible by 5

Like? Yes (1) | No   

Aditi Khandagale   10 years AGO

x=29k+7 and x-k divisible by 5
x=29(6)+7
=181

and x-k=181- 6
so x-k=175
as last digit of the answer is 5 the number is divisible by 5

Like? Yes (1) | No   

Kavitha Lakshmi A N V   10 years AGO

if a number is divisible by 5 then tha last number must be 0 or 5....

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sivaramakrishna   10 years AGO

just check the unit digit for every option.
if K=6,
29*6+7=----1
----1-6=---5
number divisible by 5.

Like? Yes (1) | No   

Debayan   10 years AGO

x-k = 28k+7
Now, 28k+7 can be divisible by 5 only when it either ends with 5 or 0 i.e 28k must end either with 6 or 3.
Since 28k will always be even, hence 28k must end with 6.
Now, K must take values which when multiplied by 8 result in 6 at unit digit's place.
Therefore, k = 6,16,26...

Like? Yes (2) | No (1)  

Piyush Kumar   10 years AGO

Put 6 in 1st eqn, x = 181
181-6 = 175 which is divisible by 5.

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PRASHANT KUMAR   10 years AGO

x-k=5n;
so
(28k+7)/5=n;.............................so for k=6....n is an integer

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akas   10 years AGO

If k=6
X=29(6)+7
X=181 X-K=181-6=175
IT IS DIVISIBLE BY 5.
THEREFORE OPTION 5)6

Like? Yes (1) | No   

prashanth   10 years AGO

29k+7-k=28k+7
put k=6 then we get 175/5=35 so that
k=6

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L KOUSHIK KUMAR   10 years AGO

since (x-k) is divisible by 5, the last digit of (x-k) should be either 0 or 5.
multiply last digit 9 with different values and add it with 7. from result obtained, subtract the given value. if it is divisible by 5, then that is the solution.

Like? Yes (1) | No   

Karthick Raja   10 years AGO

x=29k+7
if k=6
x=(29*6)+7
x=234+7
x=241
x-k=241-6
x-k=235
235 is divisible by 5
so k is 6

Like? Yes (1) | No   

T.Aravinth kumar   10 years AGO

sub the k value (choices) in
x=27k+7
if sub k=6
then get x=181
now check x-k is divisible by 5..
x-k=181-6=175
175/5=35...
so
and 5)6..

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nasrul   10 years AGO

as if the k is 6, hence the x will be 181. thus, it is applicable for x-k will be divisible with 5 as it will be 175.

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Amartya Bhattacharyya   10 years AGO

x-k=7*(4k+1)
now, check options to find out for which value of k, (4k+1) will be multiple of 5

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ganesh babu   10 years AGO

x-k=28k+7 divisible by 5
may be k=1 and 6

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Pranati Kundu   10 years AGO

put the values of k from the options...

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Chitra.S   10 years AGO

sub x = 29k+7 in (x-k)/5,
then...from the options check..,.
if k=6,then condition satisfies.

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vibhu raj gupta   10 years AGO

write eqation as this x-k=28k+7
multiply 28 by 6=168+7=175
which is divided by 5

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aman aditya   10 years AGO

x=29k+7
x=(29*6)+7
x=174+7=181
now
x-k=181-6=175 i.e divisible by 5

Like? Yes (1) | No (1)  

devvrata   10 years AGO

x-k=28k+7 If x-k is divisible by 5 then 28k+7 will also be divisible by....put k =6 we will get 175 which is divisible by 5

Like? Yes (1) | No (1)  

Shiva Teja   10 years AGO

x=29 k+7
x-k=29 k +7 -k=28 k+7
By substituting the given values
the expression (x-k) i.e, (28 k+7) is divided by 5...When k=6

Therefore from the given option k=6.

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padam   10 years AGO

29*6+7=181
181-5=175 divisible by 5

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ABHINAV PUSHPAM   10 years AGO

X=29*6=174+6=181
181-6=175 which is divisible by 5
So K = 6

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MRITUNJAY   10 years AGO

putting the value of k from 1 to 9
it only satisfy at 6
so k will be 6.

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ANANTHI.P   10 years AGO

29*6=174+7=181
x=181;k=6
DIFF=175 WHICH IS DIVISIBLE BY 5

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PAWAN KUMAR   10 years AGO

When k=6, x=29*6+7 = 181
x-k = 181-6 = 175, which is divisible by 5.

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Ankita Anand   10 years AGO

x=29k+7
and x-k%5=0
by solving we get k=6

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chepuru sai priyanka   10 years AGO

given that x-k is divisible by 5
let (x-k)/5=a
x-k=5a => x=5a+k
given, x=29k+7
5a+k=29K+7
28k=5a-7
let a=7 then k=1 not in option try for next possible value
a=35 then k=6

Like? Yes (1) | No (1)  

poojasaisri   10 years AGO

x=(29*6)+7
x=181
x-k=175
175 is divisible by 5

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ravi singh   10 years AGO

answer is 6

as given,
X=29*K + 7
then, X - K = 28*K +7

put the value of k only 6 is verified.
hence answer is 6

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Ayush Gupta   10 years AGO

29*6=174 174+7=181
181-6=175 divisible by 5

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syed kashif ullah   10 years AGO

28*6+7 =175
it is divisible by 5

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MURALI KUDUPUDI   10 years AGO

28*6+7=175

Like? Yes (1) | No (2)