x more than 50% fishes of a pond are taken and fishes equal to square root of total number of fishes

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27 Aug 2015 Fishes

x more than 50% fishes of a pond are taken and fishes equal to square root of total number of fishes are sold for aquarium purposes. 1 more than 10% of the remaining fishes are purchased by a shopkeeper and fishes equal to square root of the number of fishes purchased by shopkeeper are sold for food purposes. If 16 fishes are sold for food purpose, then minimum possible value of x will be

OPtion

1) 1
2) 3
3) 5
4) 11
5) 19
6) 21
7) 25
8) 29
9) 31
10)35

Solution

Definitely 1, Think why?

Correct Option: 1 Best Solution (3)

Dinni   9 years AGO

Total no. of fishes in a pond=13, 004, 998
Let take x as 1
Then, 50% fishes in a pond=6, 502, 499
1 more than 50% fishes of a pond=6, 502, 500
Square root of fishes=2550
1 more than 10% of remaining fishes purchased by shopkeeper=256
Square root of fishes purchased by shopkeeper are sold for food purposes=16.

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SAGNIK DATTA   9 years AGO

let pond fish =a
((x+a/2)^(1/2)*0.1 + 1)^(1/2)=16
now depending on the value of a x min value is 1

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GOURANGA SUNDAR MANDAL   9 years AGO

no of fishes fopr food purchase=16. so, nop of fishes purchased by shopkeeper=16^2=256.suppose remaining fish=x; so, x/10+1=256...so, x=2550..y-root(y)=2550..so, y=2601..so,minimum possible value of x will be 1..

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