A 3 digit number is such that 2 digits of the number are 1 and 2. What is the probability that we would get success in our one trail to guess the number.
Number of method to select 3rd digit = 10
If is 0 then total 3 digit number = 2*2*1 = 4
If it is 1 then total 3 digit number = 3!/2! = 3
Similarly if number is 2
possible number = 3
If selected number is 3 then 3 digit number = 3! = 6
Similar for 4, 5, 6, 7, 8, 9
So total 3 digit number
= 4 + 2*3 + 7*6
= 4+6+42
52
So required probability = 1/52